Algebra 101 - Unit 13

Lesson 82: Solving Nonlinear Systems with Three Variables

Nonlinear systems with three variables involve equations in x, y, and z, with at least one equation being nonlinear. Solutions represent points (x, y, z) where the surfaces intersect in 3D space.

These systems appear in physics, engineering, and optimization problems.

Methods for Solving

Example

Solve the system:

x + y + z = 6
x² + y² = 13
z = x − y

Step 1 — Substitute z = x − y into first equation:

x + y + (x − y) = 6 → 2x = 6 → x = 3

Step 2 — Solve for y using second equation:

x² + y² = 13 → 3² + y² = 13 → 9 + y² = 13 → y² = 4 → y = 2 or y = −2

Step 3 — Solve for z:

z = x − y → if y = 2, z = 3 − 2 = 1 → (3, 2, 1)
if y = −2, z = 3 − (−2) = 5 → (3, −2, 5)

Solution: (3, 2, 1) and (3, −2, 5)

Practice Problems

  1. Solve: x + y + z = 7, x² + y² = 25, z = y − x
  2. Solve: x − y + z = 4, y² + z² = 10, x = 2y
  3. Solve: x + 2y + z = 5, x² + z² = 13, y = z − 1
  4. Solve: x + y + z = 9, x² + y² = 41, z = 2x − y
  5. Solve: 2x + y − z = 3, x² + y² = 10, z = x + y