Lesson 9.1: Area of Polygons & Circles Exercises

Apply geometric formulas to calculate area of triangles, quadrilaterals, regular polygons, and circles.

Lesson Description

This lesson focuses on calculating the area of common polygons and circles. Students will apply formulas, substitute algebraic expressions, and solve multi-step problems involving composite reasoning.

Learning Objectives

  • Find the area of triangles, parallelograms, trapezoids, and regular polygons.
  • Use the formula for the area of a circle.
  • Substitute algebraic expressions into area formulas.
  • Solve real-world problems involving area.

Key Formulas

  • Triangle: \( A = \frac{1}{2}bh \)
  • Parallelogram: \( A = bh \)
  • Trapezoid: \( A = \frac{1}{2}(b_1 + b_2)h \)
  • Regular Polygon: \( A = \frac{1}{2}aP \)
  • Circle: \( A = \pi r^2 \)

Lesson Examples

Example 1: Area of a Triangle

Find the area of a triangle with base 10 cm and height 6 cm.

\[ A = \frac{1}{2}(10)(6) = 30 \text{ cm}^2 \]

Example 2: Area of a Trapezoid

Bases measure 8 m and 12 m, height is 5 m.

\[ A = \frac{1}{2}(8 + 12)(5) = \frac{1}{2}(20)(5) = 50 \text{ m}^2 \]

Example 3: Area of a Circle

Find the area of a circle with radius 7 inches.

\[ A = \pi (7)^2 = 49\pi \approx 153.94 \text{ in}^2 \]

Practice Problems

  1. Find the area of a triangle with base 14 ft and height 9 ft.
  2. Find the area of a parallelogram with base 11 cm and height 4 cm.
  3. Find the area of a trapezoid with bases 6 and 10 and height 8.
  4. Find the area of a circle with radius 5.
  5. A regular hexagon has apothem 6 and perimeter 36. Find its area.

Challenge Problems

  1. The side of a square is \( x + 3 \). Write and simplify an expression for its area.
  2. A circle has diameter \( 2x \). Express its area in terms of \( x \).
  3. A triangular garden has base \( 3x \) and height \( 2x + 4 \). Write its area as a polynomial.

Summary

Area formulas allow us to quantify two-dimensional space. Mastery of substitution, algebraic manipulation, and correct formula selection is essential for solving geometry problems efficiently and accurately.

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