The Central Idea
Many algebraic expressions can be written in either an expanded form or a factored form.
For example,
\[ (x+2)(x+5) \]can be expanded to
\[ x^2+7x+10. \]Conversely,
\[ x^2+7x+10 \]can be factored as
\[ (x+2)(x+5). \]These are not different mathematical quantities. They are different representations of the same polynomial.
Expansion emphasizes addition and individual terms. Factoring emphasizes multiplication and common structure.
Expansion
Expansion rewrites a product as an equivalent sum or difference by using the distributive property.
For example,
\[ 3(x+4)=3x+12. \]For a product of two binomials, distribution is applied more than once:
\[ (x+2)(x+5). \]Distribute \(x+2\) across the second factor:
\[ x(x+5)+2(x+5). \]Then distribute again:
\[ x^2+5x+2x+10. \]Combine like terms:
\[ x^2+7x+10. \]Therefore,
\[ (x+2)(x+5)=x^2+7x+10. \]FOIL Is a Shortcut for Distribution
For two binomials, students often learn the mnemonic FOIL: First, Outer, Inner, Last.
For
\[ (a+b)(c+d), \]FOIL produces
\[ ac+ad+bc+bd. \]But FOIL is not a separate algebraic law. It is simply a memory aid for repeated distribution.
The distributive property is more general because it also works for expressions with more than two terms.
Expanding Two Binomials
Consider
\[ (x+3)(x-4). \]Distribute:
\[ x(x-4)+3(x-4). \]Then
\[ x^2-4x+3x-12. \]Combine like terms:
\[ x^2-x-12. \]So
\[ (x+3)(x-4)=x^2-x-12. \]Expanding with Coefficients
Now consider
\[ (2x+3)(x+4). \]Distribute:
\[ 2x(x+4)+3(x+4). \]Then
\[ 2x^2+8x+3x+12. \]Combine like terms:
\[ 2x^2+11x+12. \]Therefore,
\[ (2x+3)(x+4)=2x^2+11x+12. \]Expanding More Than Two Factors
Expressions may contain several factors.
For example,
\[ (x+1)(x+2)(x+3). \]One approach is to multiply two factors first:
\[ (x+1)(x+2)=x^2+3x+2. \]Then multiply by the remaining factor:
\[ (x^2+3x+2)(x+3). \]Distribute:
\[ x^3+3x^2+3x^2+9x+2x+6. \]Combine like terms:
\[ x^3+6x^2+11x+6. \]The associative property of multiplication lets us choose which factors to multiply first.
Factoring
Factoring rewrites an expression as a product of simpler expressions.
Factoring is closely related to multiplication in arithmetic.
For example,
\[ 12=3\cdot4=2\cdot6=2^2\cdot3. \]Likewise, a polynomial can often be decomposed into factors:
\[ x^2+7x+10=(x+2)(x+5). \]The factored form reveals multiplicative structure that may be hidden in expanded form.
Always Check for a Common Factor First
The first factoring question should usually be:
Do all terms share a common factor?
Consider
\[ 6x^2+9x. \]Both terms contain \(3x\), so
\[ 6x^2+9x=3x(2x+3). \]This is the reverse of distribution:
\[ 3x(2x+3)=6x^2+9x. \]Extracting a greatest common factor often makes additional structure easier to see.
Greatest Common Factor
Consider
\[ 12x^3y+18x^2y^2. \]The numerical coefficients share a greatest common factor of \(6\).
Both terms also contain at least
\[ x^2y. \]So a greatest common factor is
\[ 6x^2y. \]Factor it out:
\[ 12x^3y+18x^2y^2 = 6x^2y(2x+3y). \]Factoring a Simple Trinomial
Consider
\[ x^2+7x+10. \]We look for two numbers whose product is \(10\) and whose sum is \(7\).
The numbers are \(2\) and \(5\), so
\[ x^2+7x+10=(x+2)(x+5). \]Why does this work?
Expanding the right side gives
\[ x^2+(2+5)x+(2)(5), \]which is
\[ x^2+7x+10. \]The middle coefficient comes from the sum of the two constants, while the constant term comes from their product.
Factoring When the Constant Is Negative
Consider
\[ x^2+x-12. \]We need two numbers whose product is \(-12\) and whose sum is \(1\).
The numbers are \(4\) and \(-3\).
Therefore,
\[ x^2+x-12=(x+4)(x-3). \]Checking by expansion:
\[ (x+4)(x-3)=x^2+x-12. \]Factoring When the Leading Coefficient Is Not 1
Consider
\[ 2x^2+7x+3. \]A possible factorization is
\[ (2x+1)(x+3). \]Expand to verify:
\[ 2x^2+6x+x+3 \]which becomes
\[ 2x^2+7x+3. \]For more complicated trinomials, several systematic factoring methods are possible. The essential goal remains the same: find factors whose expansion reproduces the original polynomial.
Factoring by Grouping
Some expressions can be factored by grouping terms into smaller collections.
Consider
\[ ax+ay+bx+by. \]Group the first two terms and the last two terms:
\[ (ax+ay)+(bx+by). \]Factor each group:
\[ a(x+y)+b(x+y). \]Now \(x+y\) is a common factor:
\[ (a+b)(x+y). \]Thus,
\[ ax+ay+bx+by=(a+b)(x+y). \]A Numerical-Looking Grouping Example
Factor
\[ x^3+3x^2+2x+6. \]Group:
\[ (x^3+3x^2)+(2x+6). \]Factor each group:
\[ x^2(x+3)+2(x+3). \]Collect the repeated factor:
\[ (x^2+2)(x+3). \]Therefore,
\[ x^3+3x^2+2x+6=(x^2+2)(x+3). \]Difference of Squares
One of the most useful factoring patterns is the difference of squares:
\[ a^2-b^2=(a-b)(a+b). \]For example,
\[ x^2-25 \]is
\[ x^2-5^2, \]so
\[ x^2-25=(x-5)(x+5). \]Checking by expansion:
\[ (x-5)(x+5)=x^2-25. \]The middle terms cancel.
Perfect Square Trinomials
Two important expansion patterns are
\[ (a+b)^2=a^2+2ab+b^2 \]and
\[ (a-b)^2=a^2-2ab+b^2. \]These can also be read backward as factoring patterns.
For example,
\[ x^2+6x+9 \]matches
\[ x^2+2(x)(3)+3^2. \]Therefore,
\[ x^2+6x+9=(x+3)^2. \]Likewise,
\[ x^2-10x+25=(x-5)^2. \]Sum and Difference of Cubes
Higher-power patterns can also be useful.
The sum of cubes factors as
\[ a^3+b^3=(a+b)(a^2-ab+b^2). \]The difference of cubes factors as
\[ a^3-b^3=(a-b)(a^2+ab+b^2). \]For example,
\[ x^3-8 \]is
\[ x^3-2^3, \]so
\[ x^3-8=(x-2)(x^2+2x+4). \]These patterns become more useful as polynomial work becomes more advanced.
Recognizing Structure Before Calculating
Factoring becomes easier when we first classify the expression.
For example:
| Expression | Useful Observation |
|---|---|
| \(8x+12\) | Common factor |
| \(x^2+9x+20\) | Quadratic trinomial |
| \(x^2-49\) | Difference of squares |
| \(x^2+10x+25\) | Perfect square trinomial |
| \(x^3+2x^2+3x+6\) | Possible grouping |
The structure suggests which transformation is likely to be useful.
Factoring Can Continue in Stages
Sometimes one factoring step is not enough.
Consider
\[ 2x^2-18. \]First factor out the common factor \(2\):
\[ 2(x^2-9). \]Then recognize a difference of squares:
\[ 2(x-3)(x+3). \]A complete factorization usually continues until no obvious factorization remains over the number system being used.
Factoring Depends on the Number System
An expression may be factorable over one number system but not another.
For example,
\[ x^2+1 \]does not factor into linear factors over the real numbers.
But over the complex numbers,
\[ x^2+1=(x-i)(x+i). \]So the phrase “fully factored” always depends on the allowed kinds of factors.
At this stage, most factoring problems will use integers or real-number coefficients unless stated otherwise.
Why Factored Form Is Useful
Factored form often makes zeros visible.
Consider
\[ x^2-5x+6=0. \]Factor:
\[ (x-2)(x-3)=0. \]A product equals zero only if at least one factor equals zero:
\[ x-2=0 \]or
\[ x-3=0. \]Therefore,
\[ x=2 \]or
\[ x=3. \]The expanded form hides these solutions; the factored form exposes them.
Why Expanded Form Is Useful
Factored form is not always preferable.
Consider
\[ (x+4)(x-1). \]Expanded form is
\[ x^2+3x-4. \]This form makes the polynomial's individual coefficients visible and may be more convenient for addition, subtraction, coefficient comparison, or certain computational methods.
The best form depends on the task.
Expansion and Factoring Are Reverse Directions
At a basic level, expansion and factoring move through the same equivalence in opposite directions:
\[ (x+2)(x+5) \longleftrightarrow x^2+7x+10. \]Expansion moves from product structure toward additive structure.
Factoring moves from additive structure toward product structure.
Because both forms are equal for every value of \(x\), either may replace the other whenever useful.
Checking a Factorization
The safest general check for a proposed factorization is simple:
Expand it.
Suppose we believe
\[ x^2-2x-15=(x-5)(x+3). \]Expand the right side:
\[ x^2+3x-5x-15. \]Combine:
\[ x^2-2x-15. \]The expansion matches the original expression, so the factorization is correct.
Factoring Is Not Canceling
Factoring rewrites an expression as a product. It does not by itself remove anything.
For example,
\[ x^2-9=(x-3)(x+3). \]No factor disappears.
Cancellation occurs only within a quotient when the same nonzero factor appears in both numerator and denominator.
For example,
\[ \frac{(x-3)(x+3)}{x-3}=x+3 \]provided that
\[ x\ne3. \]This distinction becomes important when rational expressions are simplified.
Common Errors in Expansion
Failing to Multiply Every Term
Incorrect:
\[ 2(x+5)=2x+5. \]Correct:
\[ 2(x+5)=2x+10. \]Sign Errors
Incorrect:
\[ (x-3)(x+2)=x^2+5x-6. \]Correct expansion:
\[ x^2+2x-3x-6=x^2-x-6. \]Incorrect Squaring
Incorrect:
\[ (a+b)^2=a^2+b^2. \]Correct:
\[ (a+b)^2=a^2+2ab+b^2. \]Common Errors in Factoring
Ignoring the Greatest Common Factor
For
\[ 6x^2+12x, \]writing only
\[ 2(3x^2+6x) \]is a valid partial factorization, but
\[ 6x(x+2) \]reveals the full common factor.
Using the Wrong Signs
If
\[ (x+a)(x+b)=x^2+(a+b)x+ab, \]then both the sum and product of \(a\) and \(b\) must match the polynomial.
Stopping Too Early
For
\[ 3x^2-27, \]factoring out \(3\) gives
\[ 3(x^2-9), \]but the difference of squares can still be factored:
\[ 3(x-3)(x+3). \]Worked Example: Expand and Simplify
Expand:
\[ (3x-2)(x+5). \]Distribute:
\[ 3x(x+5)-2(x+5). \]Then
\[ 3x^2+15x-2x-10. \]Combine like terms:
\[ 3x^2+13x-10. \]Therefore,
\[ (3x-2)(x+5)=3x^2+13x-10. \]Worked Example: Factor a Trinomial
Factor:
\[ x^2-3x-10. \]We need two numbers whose product is \(-10\) and whose sum is \(-3\).
The numbers are \(-5\) and \(2\).
Therefore,
\[ x^2-3x-10=(x-5)(x+2). \]Check:
\[ (x-5)(x+2)=x^2-3x-10. \]Worked Example: Factor Completely
Factor:
\[ 4x^3-36x. \]First extract the greatest common factor:
\[ 4x(x^2-9). \]Then factor the difference of squares:
\[ 4x(x-3)(x+3). \]So the complete factorization over the integers is
\[ 4x(x-3)(x+3). \]Worked Example: Choose the Better Form
Suppose we want to solve
\[ x^2+8x+15=0. \]The expanded form does not immediately reveal the solutions.
Factor:
\[ (x+3)(x+5)=0. \]Now the solutions are visible:
\[ x=-3 \]or
\[ x=-5. \]Here the factored form is more useful because the problem asks for zeros.
Practice
1. Expand
Expand and simplify:
\[ (x+4)(x+6). \]Check Answer
\[ x^2+6x+4x+24=x^2+10x+24. \]2. Expand with Coefficients
Expand:
\[ (2x-1)(x+3). \]Check Answer
\[ 2x^2+6x-x-3=2x^2+5x-3. \]3. Factor the Greatest Common Factor
Factor:
\[ 15x^2+20x. \]Check Answer
\[ 15x^2+20x=5x(3x+4). \]4. Factor a Trinomial
Factor:
\[ x^2+9x+20. \]Check Answer
\[ x^2+9x+20=(x+4)(x+5). \]5. Difference of Squares
Factor:
\[ x^2-64. \]Check Answer
\[ x^2-64=(x-8)(x+8). \]6. Perfect Square Trinomial
Factor:
\[ x^2-12x+36. \]Check Answer
\[ x^2-12x+36=(x-6)^2. \]7. Factor Completely
Factor:
\[ 2x^3-18x. \]Check Answer
First factor out \(2x\):
\[ 2x(x^2-9). \]Then factor the difference of squares:
\[ 2x(x-3)(x+3). \]Key Ideas
- Expansion rewrites products as equivalent sums or differences.
- Factoring rewrites sums or differences as equivalent products.
- Both processes are grounded in the distributive property.
- FOIL is a shortcut for repeated distribution, not a separate algebraic law.
- Always check for a greatest common factor before using more specialized factoring patterns.
- Important patterns include difference of squares, perfect square trinomials, and sums or differences of cubes.
- Factoring by grouping can expose a repeated factor that is not initially obvious.
- A factorization can be checked by expanding it.
- Factored form often reveals zeros and multiplicative structure.
- Expanded form often reveals coefficients and additive structure.
- The best representation depends on the next mathematical task.
Where This Leads
Expansion and factoring give us two complementary ways to move between additive and multiplicative structure.
Next, we will use these equivalence tools to study Rearranging Formulas, where equations containing several variables are transformed to isolate whichever quantity we need.