The Central Idea
Consider the two equations
\[ y=2x+1 \]and
\[ y=-x+7. \]Each equation describes a line.
A solution to the system must satisfy both equations at once.
Because both expressions equal \(y\), set them equal:
\[ 2x+1=-x+7. \]Then
\[ 3x=6, \] \[ x=2. \]Substitute:
\[ y=2(2)+1=5. \]So the system has solution
\[ \boxed{(2,5)}. \]Graphically, \((2,5)\) is exactly where the two lines intersect.
What Is a System of Equations?
A system of equations is a collection of two or more equations considered together.
For example,
\[ \begin{cases} x+y=7,\\ 2x-y=5 \end{cases} \]is a system of two equations in two variables.
The goal is to find values of \(x\) and \(y\) that make both equations true simultaneously.
Simultaneous Conditions
Solving one equation tells us which values satisfy one condition.
Solving a system asks for the overlap among several conditions.
In set language, if
\[ S_1 \]is the solution set of the first equation and
\[ S_2 \]is the solution set of the second, then the system solution set is
\[ \boxed{S_1\cap S_2}. \]Systems therefore connect algebra directly with intersection of sets.
Ordered Pairs as Solutions
For a system in two variables, a solution is usually an ordered pair
\[ (x,y). \]For example, test
\[ (3,4) \]in
\[ \begin{cases} x+y=7,\\ 2x-y=2. \end{cases} \]First equation:
\[ 3+4=7. \]Second equation:
\[ 2(3)-4=2. \]Both are true.
Therefore,
\[ \boxed{(3,4)} \]is a solution of the system.
A Point Must Satisfy Every Equation
Suppose
\[ (3,4) \]satisfies the first equation of a system but not the second.
Then it is not a solution of the system.
A system uses logical “and”:
\[ \boxed{ \text{equation 1 is true} \quad\text{and}\quad \text{equation 2 is true} }. \]Graphical Meaning
For equations in two variables, each equation has a graph.
The system solutions are the points common to all the graphs.
For two lines, this means:
- one intersection point;
- no intersection points;
- every point on the same line.
One Solution
Consider
\[ \begin{cases} y=2x+1,\\ y=-x+7. \end{cases} \]The slopes are different:
\[ 2 \]and
\[ -1. \]Distinct nonparallel lines intersect exactly once.
So the system has one solution.
No Solution
Consider
\[ \begin{cases} y=3x+2,\\ y=3x-5. \end{cases} \]Both lines have slope
\[ 3, \]but different intercepts.
They are distinct parallel lines.
Therefore, they never intersect and the system has
\[ \boxed{\text{no solution}}. \]The solution set is
\[ \boxed{\varnothing}. \]Infinitely Many Solutions
Consider
\[ \begin{cases} y=2x+4,\\ 2y=4x+8. \end{cases} \]The second equation simplifies to
\[ y=2x+4. \]Both equations describe the same line.
Every point on that line satisfies both equations.
So the system has
\[ \boxed{\text{infinitely many solutions}}. \]Consistent and Inconsistent Systems
A system is consistent if it has at least one solution.
A system is inconsistent if it has no solution.
Thus:
- one solution: consistent;
- infinitely many solutions: consistent;
- no solution: inconsistent.
Independent and Dependent Equations
In a two-equation linear system:
- independent equations contribute genuinely different constraints and often produce one intersection;
- dependent equations describe the same relationship in different forms.
For example,
\[ x+y=5 \]and
\[ 2x+2y=10 \]are dependent because one equation is a scalar multiple of the other.
Three Geometric Cases for Two Linear Equations
| Geometry | Solutions | System Type |
|---|---|---|
| Lines intersect once | One | Consistent, independent |
| Distinct parallel lines | None | Inconsistent |
| Same line | Infinitely many | Consistent, dependent |
Why Two Nonparallel Lines Have One Solution
Two distinct nonparallel lines in the plane have different directions.
Because neither direction is parallel to the other, the lines meet at exactly one point.
That unique intersection is the unique ordered pair satisfying both equations.
Systems as Intersections of Functions
Suppose
\[ f(x)=2x+5 \]and
\[ g(x)=-x+11. \]To find where the graphs intersect, solve
\[ f(x)=g(x). \]That is,
\[ 2x+5=-x+11. \]Then
\[ 3x=6, \] \[ x=2. \]The common output is
\[ 9. \]So the intersection is
\[ \boxed{(2,9)}. \]Method 1: Graphing
One way to solve a system is to graph every equation and identify their common point or points.
For linear systems, graphing is especially useful for understanding:
- whether a solution exists;
- approximately where the solution lies;
- whether lines are parallel or identical;
- the geometric meaning of the algebra.
Graphing May Give Approximate Solutions
If two lines intersect at
\[ \left(\frac{7}{3},\frac{11}{5}\right), \]a hand-drawn graph may show only an approximate intersection.
Graphing is excellent for structure and checking, but symbolic methods may be better when exact values are required.
Method 2: Substitution
Substitution replaces one variable with an equivalent expression from another equation.
Consider
\[ \begin{cases} y=2x+1,\\ x+y=7. \end{cases} \]Because the first equation already isolates \(y\), substitute
\[ 2x+1 \]for \(y\) in the second equation.
Substitution Example
Start with
\[ x+y=7. \]Substitute
\[ y=2x+1: \] \[ x+(2x+1)=7. \]Then
\[ 3x+1=7, \] \[ 3x=6, \] \[ x=2. \]Now find \(y\):
\[ y=2(2)+1=5. \]So
\[ \boxed{(2,5)}. \]Why Substitution Works
If
\[ y=2x+1, \]then \(y\) and \(2x+1\) represent the same quantity wherever the first equation is true.
Replacing one with the other preserves the meaning of the system.
Substitution is therefore an application of equality and equivalence.
Substitution When \(x\) Is Isolated
Consider
\[ \begin{cases} x=4-y,\\ 3x+2y=10. \end{cases} \]Substitute
\[ x=4-y \]into the second equation:
\[ 3(4-y)+2y=10. \]Then
\[ 12-3y+2y=10, \] \[ -y=-2, \] \[ y=2. \]So
\[ x=4-2=2. \]The solution is
\[ \boxed{(2,2)}. \]Method 3: Elimination
Elimination combines equations so that one variable cancels.
Consider
\[ \begin{cases} x+y=7,\\ x-y=1. \end{cases} \]Add the equations:
\[ (x+y)+(x-y)=7+1. \]Then
\[ 2x=8, \] \[ x=4. \]Substitute into either original equation:
\[ 4+y=7, \] \[ y=3. \]So
\[ \boxed{(4,3)}. \]Why Elimination Works
If two equalities are true, we may add their left sides and add their right sides.
For
\[ L_1=R_1 \]and
\[ L_2=R_2, \]we obtain
\[ L_1+L_2=R_1+R_2. \]Elimination chooses combinations that make one variable disappear.
Elimination by Subtraction
Consider
\[ \begin{cases} 3x+2y=14,\\ 3x-y=5. \end{cases} \]Subtract the second equation from the first:
\[ (3x+2y)-(3x-y)=14-5. \]Then
\[ 3y=9, \] \[ y=3. \]Substitute:
\[ 3x-3=5, \] \[ 3x=8, \] \[ x=\frac83. \]So
\[ \boxed{\left(\frac83,3\right)}. \]Elimination by Scaling an Equation
Sometimes coefficients do not cancel immediately.
Consider
\[ \begin{cases} 2x+y=7,\\ 3x-2y=4. \end{cases} \]Multiply the first equation by \(2\):
\[ 4x+2y=14. \]Add to the second:
\[ (4x+2y)+(3x-2y)=14+4. \]So
\[ 7x=18, \] \[ x=\frac{18}{7}. \]Finish the Scaled-Elimination Example
Use
\[ 2x+y=7. \]Substitute
\[ x=\frac{18}{7}. \]Then
\[ 2\left(\frac{18}{7}\right)+y=7. \]So
\[ \frac{36}{7}+y=\frac{49}{7}, \] \[ y=\frac{13}{7}. \]Therefore,
\[ \boxed{ \left(\frac{18}{7},\frac{13}{7}\right) }. \]Choosing a Method
No single solving method is always best.
A useful rule of thumb:
- use graphing when visual structure or an approximate answer is useful;
- use substitution when one variable is already isolated or easily isolated;
- use elimination when coefficients already match or can be made to match easily.
Different Methods Should Agree
If a system has one exact solution, graphing, substitution, elimination, and later matrix methods all describe the same mathematical solution set.
The methods differ in representation and efficiency, not in the underlying answer.
Verify the Final Ordered Pair
Suppose a system solution is claimed to be
\[ (4,3). \]For
\[ \begin{cases} x+y=7,\\ x-y=1, \end{cases} \]check:
\[ 4+3=7, \]and
\[ 4-3=1. \]Both equations are true.
The ordered pair is verified.
Verification Is Especially Important with Fractions
When elimination or substitution produces fractions, arithmetic mistakes are easy to make.
Substituting the final values into every original equation is often the fastest way to catch an error.
Detecting No Solution Algebraically
Consider
\[ \begin{cases} 2x+y=5,\\ 4x+2y=14. \end{cases} \]Multiply the first equation by \(2\):
\[ 4x+2y=10. \]But the second equation says
\[ 4x+2y=14. \]Subtracting gives
\[ 0=4. \]This contradiction means
\[ \boxed{\text{no solution}}. \]Detecting Infinitely Many Solutions Algebraically
Consider
\[ \begin{cases} 2x+y=5,\\ 4x+2y=10. \end{cases} \]Multiply the first equation by \(2\):
\[ 4x+2y=10. \]This is exactly the second equation.
Elimination produces
\[ 0=0. \]This identity means the equations describe the same line.
There are infinitely many solutions.
A Free Variable in a Dependent System
For
\[ 2x+y=5, \]we may solve for
\[ y=5-2x. \]Because the second equation adds no new condition, \(x\) remains free.
Every point of the form
\[ \boxed{(x,5-2x)} \]satisfies the dependent system.
Parameterizing Infinitely Many Solutions
We may introduce a parameter
\[ t\in\mathbb{R}. \]Let
\[ x=t. \]Then
\[ y=5-2t. \]So the entire solution set can be written
\[ \boxed{ (x,y)=(t,5-2t), \qquad t\in\mathbb{R} }. \]Systems in Standard Form
Linear systems are often written
\[ \begin{cases} A_1x+B_1y=C_1,\\ A_2x+B_2y=C_2. \end{cases} \]Standard form aligns like variables, which makes elimination especially natural.
It also prepares the equations for matrix representation later.
Coefficient Structure Predicts Geometry
Consider
\[ A_1x+B_1y=C_1 \]and
\[ A_2x+B_2y=C_2. \]If the coefficient pairs
\[ (A_1,B_1) \]and
\[ (A_2,B_2) \]are proportional, the lines have the same direction.
Then they are either parallel or identical.
Example: Proportional Left Sides
Compare
\[ 2x+3y=12 \]and
\[ 4x+6y=30. \]The left-side coefficients are proportional:
\[ (4,6)=2(2,3). \]But doubling the first equation gives
\[ 4x+6y=24, \]not \(30\).
So the lines are distinct parallel lines and the system has no solution.
Example: Entire Equations Proportional
Compare
\[ 2x+3y=12 \]and
\[ 4x+6y=24. \]Every coefficient, including the constant, is doubled.
So the equations are equivalent and the system has infinitely many solutions.
Systems with Horizontal and Vertical Lines
Consider
\[ \begin{cases} x=4,\\ y=7. \end{cases} \]The vertical line
\[ x=4 \]and horizontal line
\[ y=7 \]intersect at
\[ \boxed{(4,7)}. \]This is one of the simplest linear systems.
A Vertical Line and an Affine Function
Consider
\[ \begin{cases} x=3,\\ y=2x-1. \end{cases} \]The first equation immediately gives
\[ x=3. \]Substitute:
\[ y=2(3)-1=5. \]So
\[ \boxed{(3,5)}. \]Systems Need Not Be Linear
The general idea of a system is broader than straight lines.
For example,
\[ \begin{cases} y=x^2,\\ y=2x+3 \end{cases} \]asks for intersections of a parabola and a line.
Such a system may have zero, one, two, or more solutions depending on the equations.
This section begins with linear systems because their structure is especially clear and reusable.
Linear Systems as Simultaneous Models
Systems become powerful when two models describe the same situation.
For example, two cost plans may be
\[ A(x)=5x+20 \]and
\[ B(x)=3x+40. \]Solving the system identifies where the plans have the same cost.
Example: Compare Two Plans
Set
\[ 5x+20=3x+40. \]Then
\[ 2x=20, \] \[ x=10. \]The common cost is
\[ 5(10)+20=70. \]So the graphs intersect at
\[ \boxed{(10,70)}. \]The system identifies the crossover point.
Break-Even as a System
Suppose revenue and cost are
\[ R(q)=25q \]and
\[ C(q)=15q+400. \]Break-even means both models have the same output:
\[ R(q)=C(q). \]This is a system-intersection problem.
The solution is
\[ q=40, \]with common value
\[ 1000. \]So the intersection is
\[ \boxed{(40,1000)}. \]Systems from Two Unknown Quantities
Suppose a theater sells adult tickets for \$12 and student tickets for \$8.
A total of \(100\) tickets are sold for \$1000.
Let
\[ a=\text{adult tickets}, \] \[ s=\text{student tickets}. \]The total-ticket condition is
\[ a+s=100. \]The revenue condition is
\[ 12a+8s=1000. \]Together:
\[ \begin{cases} a+s=100,\\ 12a+8s=1000. \end{cases} \]Solve the Ticket System
From
\[ a+s=100, \]we get
\[ s=100-a. \]Substitute:
\[ 12a+8(100-a)=1000. \]Then
\[ 12a+800-8a=1000, \] \[ 4a=200, \] \[ a=50. \]So
\[ s=50. \]Therefore,
\[ \boxed{(a,s)=(50,50)}. \]Interpret the Solution in Context
The ordered pair
\[ (50,50) \]means \(50\) adult tickets and \(50\) student tickets were sold.
A system solution should be translated back into the quantities represented by the variables.
Mixture Example
Suppose \(x\) liters of a \(20\%\) solution are mixed with \(y\) liters of a \(50\%\) solution to make \(30\) liters of a \(40\%\) solution.
Total volume:
\[ x+y=30. \]Total amount of solute:
\[ 0.20x+0.50y=0.40(30). \]So the system is
\[ \begin{cases} x+y=30,\\ 0.20x+0.50y=12. \end{cases} \]Solve the Mixture System
From
\[ x+y=30, \]we have
\[ x=30-y. \]Substitute:
\[ 0.20(30-y)+0.50y=12. \]Then
\[ 6-0.20y+0.50y=12, \] \[ 0.30y=6, \] \[ y=20. \]Thus,
\[ x=10. \]The mixture uses
\[ \boxed{10\text{ L at }20\%\text{ and }20\text{ L at }50\%}. \]Motion Example
Suppose two travelers' positions are modeled by
\[ d_1(t)=50t \]and
\[ d_2(t)=200-30t. \]They meet when
\[ d_1(t)=d_2(t). \]So
\[ 50t=200-30t. \]Then
\[ 80t=200, \] \[ t=2.5. \]The meeting position is
\[ 50(2.5)=125. \]Thus,
\[ \boxed{(t,d)=(2.5,125)}. \]System Variables Need Not Be \(x\) and \(y\)
Systems may use whatever variables fit the situation:
\[ \begin{cases} a+s=100,\\ 12a+8s=1000 \end{cases} \]or
\[ \begin{cases} V_1+V_2=30,\\ 0.2V_1+0.5V_2=12. \end{cases} \]The algebraic structure matters more than the letter names.
Domain Restrictions in Systems
A system may have an algebraic solution that does not make sense in context.
If variables count objects, we may require
\[ x,y\in\mathbb{Z}_{\ge0}. \]If they represent physical amounts, we may require
\[ x\ge0,\qquad y\ge0. \]Always check the solution against the model's domain.
Example of an Invalid Contextual Solution
Suppose a ticket system produced
\[ a=120, \qquad s=-20. \]The equations might be algebraically satisfied, but negative ticket counts are not physically meaningful.
The mathematical solution would reveal that the original assumptions or data do not describe a feasible ticket scenario.
Systems as Constraint Intersections
Each equation restricts the possible values of the variables.
One equation may leave infinitely many possibilities.
A second independent equation narrows the possibilities further.
Geometrically, each line is a one-dimensional constraint in the plane, and their intersection may reduce the solution to a single point.
More Equations Can Add More Constraints
Consider three equations in two variables:
\[ \begin{cases} x+y=5,\\ x-y=1,\\ 2x=6. \end{cases} \]The first two give
\[ x=3,\qquad y=2. \]The third equation also gives
\[ x=3. \]So the third condition is consistent and redundant.
Too Many Conditions Can Conflict
Suppose the third equation were instead
\[ 2x=8. \]The first two require
\[ x=3, \]while the third requires
\[ x=4. \]No point satisfies all three equations.
The expanded system is inconsistent.
Three Variables
A linear system may involve three variables:
\[ \begin{cases} x+y+z=6,\\ 2x-y+z=3,\\ x+2y-z=4. \end{cases} \]A solution is an ordered triple
\[ \boxed{(x,y,z)} \]that satisfies all three equations simultaneously.
Geometric Meaning in Three Variables
A linear equation in three variables such as
\[ Ax+By+Cz=D \]typically describes a plane in three-dimensional space.
A system of such equations asks for the common intersection of several planes.
That intersection may be:
- one point;
- a line;
- a plane;
- empty.
Why Systems Lead Naturally to Matrices
As systems become larger, repeatedly writing every variable name becomes cumbersome.
For example,
\[ \begin{cases} 2x+3y-z=7,\\ x-4y+2z=5,\\ 3x+y+5z=12 \end{cases} \]contains a regular grid of coefficients.
Matrices provide a compact way to organize those coefficients and perform systematic elimination.
Coefficient Pattern Preview
The system
\[ \begin{cases} 2x+3y=7,\\ 4x-y=5 \end{cases} \]contains coefficient rows
\[ (2,3) \]and
\[ (4,-1). \]Later these can be organized into a coefficient matrix, while the constants form a separate column or an augmented matrix.
Systems and Row Operations Preview
Elimination already uses operations that will later become row operations:
- swap equations;
- multiply an equation by a nonzero constant;
- add a multiple of one equation to another.
These operations preserve the solution set when used correctly.
Why Equivalent Systems Matter
When solving by substitution or elimination, we replace the original system with a simpler system having the same solution set.
Such systems are equivalent systems.
The goal is not to preserve the appearance of the equations, but to preserve exactly which variable values satisfy them.
Example of Equivalent Systems
Start with
\[ \begin{cases} x+y=7,\\ x-y=1. \end{cases} \]Add the equations to obtain
\[ 2x=8. \]The system can then be represented as
\[ \begin{cases} x=4,\\ x+y=7. \end{cases} \]Then
\[ y=3. \]Each stage preserves the unique solution
\[ (4,3). \]Do Not Change Only One Equation Arbitrarily
An equation in a system may be replaced only by an equivalent consequence that preserves the common solution set.
Changing a coefficient or constant without a valid operation changes the problem itself.
Approximate Systems from Data
Real models may not intersect perfectly because of measurement noise.
Two fitted lines may produce an approximate intersection rather than an exact physical truth.
In such cases, use approximate notation and interpret the intersection as model-based.
Example: Approximate Crossover
Suppose fitted cost models are
\[ A(x)\approx4.9x+21.2 \]and
\[ B(x)\approx3.1x+39.8. \]Set the models equal:
\[ 4.9x+21.2=3.1x+39.8. \]Then
\[ 1.8x=18.6, \] \[ x\approx10.33. \]The crossover is itself an estimate based on approximate models.
Graphing as a Check on Symbolic Work
If algebra gives
\[ (10.33,71.8) \]as an approximate intersection, a graph should show the fitted lines crossing near that point.
If the graph suggests a completely different region, recheck the algebra or model.
Substitution Versus Elimination
Consider
\[ \begin{cases} y=5x-2,\\ 3x+2y=10. \end{cases} \]Substitution is natural because \(y\) is isolated.
But for
\[ \begin{cases} 3x+2y=10,\\ 5x-2y=6, \end{cases} \]elimination is natural because the \(y\)-coefficients already cancel.
Method choice is part of mathematical efficiency.
One Equation Can Be Solved Before Combining
Consider
\[ \begin{cases} 2x=8,\\ x+3y=13. \end{cases} \]The first equation immediately gives
\[ x=4. \]Then
\[ 4+3y=13, \] \[ 3y=9, \] \[ y=3. \]There is no need to force a more complicated method.
Systems as Information Structures
Each independent equation contributes information.
In two variables:
- one ordinary linear equation usually leaves infinitely many possible points;
- a second independent linear equation usually identifies one point;
- a dependent equation adds no new restriction;
- a contradictory equation can eliminate all possibilities.
Underdetermined Systems
A system has fewer independent constraints than needed when variables remain free.
For example,
\[ x+y+z=6 \]is one equation in three variables.
Many ordered triples satisfy it.
Additional independent equations are needed to determine a unique triple.
Overdetermined Systems
A system may contain more equations than variables.
That does not automatically mean no solution exists.
The extra equations may be:
- consistent and redundant;
- consistent and informative;
- inconsistent with the others.
System Rank Preview
Later matrix methods formalize the idea of how many genuinely independent constraints a system contains.
This concept is connected to rank.
For now, the important intuition is that repeated or dependent equations do not add new information.
Exact Arithmetic Is Often Worth Preserving
If a system produces
\[ x=\frac{18}{7}, \]keep the fraction when exact values matter.
A decimal such as
\[ 2.571428\ldots \]may be useful for interpretation, but the fraction preserves exact structure.
Units in Applied Systems
Each equation should be dimensionally meaningful.
For ticket equations:
\[ a+s=100 \]counts tickets, while
\[ 12a+8s=1000 \]measures dollars.
The equations represent different conditions but share the same unknown quantities.
Variable Definitions Prevent Confusion
Before solving an applied system, write definitions such as
\[ a=\text{number of adult tickets}, \] \[ s=\text{number of student tickets}. \]This makes the final ordered pair interpretable and helps prevent switching variable meanings during the calculation.
A Reliable Graphing Workflow
- Graph each equation accurately.
- Identify all common points.
- Estimate coordinates if necessary.
- Check the candidate solution in every original equation.
- Recognize parallel or coincident graphs when no single intersection appears.
A Reliable Substitution Workflow
- Choose an equation with an isolated or easily isolated variable.
- Solve for that variable if necessary.
- Substitute the equivalent expression into the other equation.
- Solve the resulting one-variable equation.
- Back-substitute to find the remaining variable.
- Verify the ordered pair in every original equation.
A Reliable Elimination Workflow
- Write equations with like variables aligned.
- Choose a variable to eliminate.
- Scale one or both equations if needed.
- Add or subtract the equations.
- Solve the remaining one-variable equation.
- Back-substitute.
- Verify the final solution.
A Reliable Classification Workflow
- Simplify both equations.
- Compare slopes or coefficient structure.
- If the lines intersect, identify the unique solution.
- If the lines are distinct and parallel, report no solution.
- If the equations are equivalent, report infinitely many solutions.
- Use algebraic identities or contradictions to confirm the classification.
A Reliable Applied-System Workflow
- Define the unknown quantities.
- Translate each independent condition into an equation.
- Check units and domain restrictions.
- Choose a solving method.
- Solve and verify.
- Interpret the ordered pair or tuple in context.
- Reject solutions that violate physical or discrete constraints.
Common Errors
Solving Only One Equation
A system solution must satisfy every equation, not just one.
Forgetting to Back-Substitute
Solving for \(x\) alone does not complete a two-variable solution unless \(y\) is also found.
Reporting \(x=2\) Instead of \((2,5)\)
For two variables, the solution should usually be reported as an ordered pair.
Substituting into the Wrong Expression
Replace a variable with an expression known to be equal to that variable.
Scaling Only Part of an Equation
When multiplying an equation, multiply every term on both sides by the same nonzero factor.
Missing the No-Solution Case
A contradiction such as \(0=4\) means the system is inconsistent.
Missing the Infinite-Solution Case
An identity such as \(0=0\) after correct elimination may indicate dependent equations.
Trusting a Graph Without Verification
A hand-drawn intersection may be approximate. Substitute the candidate values into the equations.
Ignoring Domain Restrictions
Negative counts or impossible physical values may invalidate an algebraic solution in context.
Assuming More Equations Always Mean More Information
Dependent equations may repeat information already present.
Practice
1. Check a Solution
Does
\[ (2,3) \]solve
\[ \begin{cases} x+y=5,\\ 2x-y=1? \end{cases} \]Check Answer
\[ 2+3=5, \]and
\[ 2(2)-3=1. \]Both equations are true.
\[ \boxed{\text{Yes, }(2,3)\text{ is a solution.}} \]2. Solve by Substitution
Solve
\[ \begin{cases} y=x+4,\\ 2x+y=10. \end{cases} \]Check Answer
Substitute:
\[ 2x+(x+4)=10. \] \[ 3x=6. \] \[ x=2. \]Then
\[ y=6. \]So
\[ \boxed{(2,6)}. \]3. Solve by Elimination
Solve
\[ \begin{cases} x+y=9,\\ x-y=3. \end{cases} \]Check Answer
Add the equations:
\[ 2x=12, \] \[ x=6. \]Then
\[ y=3. \]Therefore,
\[ \boxed{(6,3)}. \]4. Eliminate After Scaling
Solve
\[ \begin{cases} 2x+y=8,\\ 3x-2y=5. \end{cases} \]Check Answer
Multiply the first equation by \(2\):
\[ 4x+2y=16. \]Add:
\[ 7x=21. \] \[ x=3. \]Then
\[ 2(3)+y=8, \] \[ y=2. \]So
\[ \boxed{(3,2)}. \]5. Classify the System
Classify
\[ \begin{cases} y=4x+1,\\ y=4x-6. \end{cases} \]Check Answer
The slopes are equal and the intercepts differ.
The lines are distinct and parallel.
\[ \boxed{\text{No solution; inconsistent system.}} \]6. Dependent System
Classify
\[ \begin{cases} x+2y=6,\\ 2x+4y=12. \end{cases} \]Check Answer
The second equation is twice the first.
They describe the same line.
\[ \boxed{\text{Infinitely many solutions; dependent system.}} \]7. Horizontal and Vertical Lines
Solve
\[ \begin{cases} x=-3,\\ y=5. \end{cases} \]Check Answer
The lines intersect at
\[ \boxed{(-3,5)}. \]8. Compare Two Plans
Plan A costs
\[ A(x)=6x+12 \]and Plan B costs
\[ B(x)=4x+30. \]Find the crossover point.
Check Answer
\[ 6x+12=4x+30. \] \[ 2x=18. \] \[ x=9. \]The common cost is
\[ 6(9)+12=66. \]So
\[ \boxed{(9,66)}. \]9. Ticket System
Adult tickets cost \$10 and child tickets cost \$6. A total of \(80\) tickets brings in \$640. How many of each were sold?
Check Answer
Let \(a\) be adult tickets and \(c\) child tickets:
\[ \begin{cases} a+c=80,\\ 10a+6c=640. \end{cases} \]From \(c=80-a\):
\[ 10a+6(80-a)=640. \] \[ 10a+480-6a=640. \] \[ 4a=160. \] \[ a=40. \]Then
\[ c=40. \]So
\[ \boxed{40\text{ adult and }40\text{ child tickets}}. \]10. Mixture System
How many liters of \(10\%\) solution and \(40\%\) solution are needed to make \(20\) liters of \(25\%\) solution?
Check Answer
Let \(x\) be liters of \(10\%\) solution and \(y\) liters of \(40\%\) solution:
\[ \begin{cases} x+y=20,\\ 0.10x+0.40y=5. \end{cases} \]Use \(x=20-y\):
\[ 0.10(20-y)+0.40y=5. \] \[ 2-0.10y+0.40y=5. \] \[ 0.30y=3. \] \[ y=10. \]Then
\[ x=10. \]Therefore,
\[ \boxed{10\text{ L of each solution}}. \]11. Identify a Contradiction
What does the system
\[ \begin{cases} 2x+3y=7,\\ 4x+6y=20 \end{cases} \]tell you?
Check Answer
Doubling the first equation gives
\[ 4x+6y=14, \]but the second says
\[ 4x+6y=20. \]The equations are contradictory.
\[ \boxed{\text{The system has no solution.}} \]12. Parameterize a Dependent System
Describe all solutions of
\[ \begin{cases} x+y=4,\\ 2x+2y=8. \end{cases} \]Check Answer
The equations are equivalent.
Let
\[ x=t. \]Then
\[ y=4-t. \]So all solutions are
\[ \boxed{ (x,y)=(t,4-t), \qquad t\in\mathbb{R} }. \]Key Ideas
- A system of equations requires several equations to be satisfied simultaneously.
- The solution set of a system is the intersection of the individual solution sets.
- For two variables, solutions are usually ordered pairs.
- Two linear equations may have one solution, no solution, or infinitely many solutions.
- Intersecting nonparallel lines give one solution.
- Distinct parallel lines give no solution.
- Equivalent equations describing the same line give infinitely many solutions.
- A consistent system has at least one solution; an inconsistent system has none.
- Substitution replaces a variable with an equivalent expression.
- Elimination combines equations to cancel a variable.
- Graphing, substitution, elimination, and matrix methods are different representations of the same solution problem.
- Equivalent-system transformations preserve the solution set.
- Applied systems model several independent conditions involving the same unknown quantities.
- Domain restrictions and units remain important when interpreting solutions.
- Larger systems naturally lead to matrices, row operations, rank, and systematic elimination methods.
Where This Leads
Systems of equations extend algebra from one condition at a time to simultaneous relationships. A solution is no longer merely a zero or intercept; it is a point, tuple, or set of values where several mathematical statements agree at once.
From here, the course can develop substitution and elimination in greater depth, organize larger systems with augmented matrices, formalize row operations and row-echelon forms, study Gaussian and Gauss-Jordan elimination, examine matrix equations and inverses, and connect system structure with determinants, rank, and applications throughout algebra, geometry, modeling, and numerical computation.