The Central Idea
Consider
\[ \begin{cases} y\ge x+1,\\ y\le -x+5. \end{cases} \]The first inequality includes points on or above the line
\[ y=x+1. \]The second includes points on or below
\[ y=-x+5. \]The solution to the system is the overlap:
\[ \boxed{\text{points satisfying both inequalities}}. \]Where the two boundary lines meet,
\[ x+1=-x+5, \] \[ 2x=4, \] \[ x=2, \]and
\[ y=3. \]The point
\[ \boxed{(2,3)} \]is part of the boundary of the feasible region.
What Is a System of Inequalities?
A system of inequalities is a collection of inequalities considered simultaneously.
For example,
\[ \begin{cases} x+y\le 8,\\ x\ge0,\\ y\ge0 \end{cases} \]asks for all ordered pairs satisfying all three conditions.
Systems Use Logical “And”
A solution must satisfy
\[ \text{inequality 1} \]and
\[ \text{inequality 2} \]and every additional condition.
In set language, if the individual solution sets are
\[ S_1,S_2,\ldots,S_n, \]then the system solution is
\[ \boxed{ S_1\cap S_2\cap\cdots\cap S_n }. \]A Single Linear Inequality in Two Variables
Consider
\[ y>2x+1. \]The related equation
\[ y=2x+1 \]is the boundary line.
The inequality selects one side of that line.
Because the inequality is strict, points on the boundary are excluded.
Boundary Lines
To graph a linear inequality, first replace the inequality symbol with equality.
For
\[ 3x+2y\le12, \]the boundary is
\[ \boxed{ 3x+2y=12 }. \]This line separates the plane into two half-planes.
Solid and Dashed Boundaries
Use a solid boundary line when equality is included:
\[ \le,\qquad \ge. \]Use a dashed boundary line when equality is excluded:
\[ <,\qquad >. \]The line style records whether boundary points belong to the solution set.
Half-Planes
A line divides the coordinate plane into two regions called half-planes.
A linear inequality chooses one of these half-planes, possibly including the boundary.
For example,
\[ y\ge x-2 \]includes the half-plane on or above the line
\[ y=x-2. \]When the Inequality Is Solved for \(y\)
If the inequality is written
\[ y>mx+b, \]shade above the boundary line.
If it is written
\[ yThe same applies to inclusive versions using \(\ge\) and \(\le\).
Example: Shade Above
Graph
\[ y\ge2x-3. \]The boundary is
\[ y=2x-3. \]Because
\[ \ge \]includes equality, draw the line solid.
Shade the region above the line.
Example: Shade Below
Graph
\[ y<-x+4. \]The boundary is
\[ y=-x+4. \]Because the inequality is strict, draw a dashed line.
Shade below it.
Test Points
If the correct side is not immediately obvious, choose a test point not on the boundary.
The origin
\[ (0,0) \]is often convenient.
Substitute it into the inequality.
If the inequality is true, shade the side containing the test point.
Example: Test the Origin
Graph
\[ 2x+3y<12. \]The boundary is
\[ 2x+3y=12. \]Test
\[ (0,0). \]Then
\[ 2(0)+3(0)<12, \] \[ 0<12. \]This is true.
So shade the side containing the origin.
When the Origin Is on the Boundary
For
\[ y>2x, \]the origin lies on the boundary line
\[ y=2x. \]So \((0,0)\) cannot distinguish the two sides.
Choose another test point, such as
\[ (0,1). \]Systems as Overlapping Half-Planes
Suppose
\[ \begin{cases} y\ge x+1,\\ y\le -x+5. \end{cases} \]Graph the first permitted half-plane.
Graph the second.
The solution is the region where the shaded portions overlap.
The Feasible Region
In applications, the solution region of a system of inequalities is often called the feasible region.
Every point in the feasible region satisfies all constraints.
Every point outside violates at least one constraint.
Example: First-Quadrant Constraint
Suppose
\[ \begin{cases} x+y\le6,\\ x\ge0,\\ y\ge0. \end{cases} \]The conditions
\[ x\ge0 \]and
\[ y\ge0 \]restrict the solution to the first quadrant.
The inequality
\[ x+y\le6 \]keeps points on or below the line
\[ x+y=6. \]The feasible region is a triangle including its boundary.
Vertices of a Feasible Region
When boundary lines intersect, their intersection points often form vertices of the feasible region.
For
\[ \begin{cases} x+y\le6,\\ x\ge0,\\ y\ge0, \end{cases} \]the vertices are
\[ \boxed{(0,0),\ (6,0),\ (0,6)}. \]Why Vertices Matter
Vertices identify important boundary combinations.
Later, in linear optimization, maximum or minimum values of a linear objective over a bounded polygonal feasible region occur at vertices.
For now, vertices are useful landmarks for understanding the geometry of constraints.
Strict Systems Can Exclude Their Boundaries
Consider
\[ \begin{cases} x+y<6,\\ x>0,\\ y>0. \end{cases} \]The region lies inside the same triangular shape as before, but none of the three boundary lines is included.
The graph uses dashed boundaries.
Mixed Boundary Types
A system may mix strict and inclusive inequalities:
\[ \begin{cases} x+y\le6,\\ x>0,\\ y\ge0. \end{cases} \]Then:
- \(x+y=6\) is solid;
- \(x=0\) is dashed;
- \(y=0\) is solid.
Checking a Point in a System
Consider
\[ \begin{cases} x+y\le8,\\ x\ge2,\\ y\ge1. \end{cases} \]Test
\[ (3,4). \]First:
\[ 3+4\le8. \]True.
Second:
\[ 3\ge2. \]True.
Third:
\[ 4\ge1. \]True.
Therefore,
\[ \boxed{(3,4)} \]is a solution of the system.
A Point That Fails One Condition
Test
\[ (7,3) \]in the same system.
Although
\[ 7\ge2 \]and
\[ 3\ge1, \]we have
\[ 7+3\le8 \]false.
So the point is not in the feasible region.
No-Solution Systems
Consider
\[ \begin{cases} y>2x+5,\\ y<2x+1. \end{cases} \]The first inequality requires points above the higher parallel line.
The second requires points below the lower parallel line.
No point can satisfy both.
Therefore,
\[ \boxed{\text{the system has no solution}}. \]Systems with an Unbounded Region
Consider
\[ \begin{cases} y\ge x,\\ y\ge -x. \end{cases} \]The solution lies above both boundary lines.
The feasible region extends upward indefinitely.
So the solution region is unbounded.
Bounded Versus Unbounded Regions
A feasible region is bounded if it fits inside some finite enclosure.
It is unbounded if it extends indefinitely in at least one direction.
Both kinds occur naturally in systems of linear inequalities.
Redundant Inequalities
Consider
\[ \begin{cases} x\ge0,\\ y\ge0,\\ x+y\le10,\\ x+y\le15. \end{cases} \]If
\[ x+y\le10, \]then
\[ x+y\le15 \]is automatically true.
The fourth inequality adds no new restriction.
It is redundant.
Contradictory Constraints
Consider
\[ \begin{cases} x\ge5,\\ x\le2. \end{cases} \]No real number satisfies both conditions.
So the system has
\[ \boxed{\varnothing} \]as its solution set.
One-Variable Systems of Inequalities
Systems of inequalities also occur in one variable.
For example,
\[ \begin{cases} x>2,\\ x\le7. \end{cases} \]The solution is the overlap:
\[ \boxed{2“And” Means Intersection
For
\[ x>2 \]and
\[ x\le7, \]the solution is
\[ (2,\infty)\cap(-\infty,7] = \boxed{(2,7]}. \]The same intersection idea extends from number lines to coordinate planes.
Systems with Vertical Boundaries
Consider
\[ \begin{cases} x\ge2,\\ x\le6. \end{cases} \]The boundary lines are
\[ x=2 \]and
\[ x=6. \]The solution is the vertical strip between them, including both boundaries.
Systems with Horizontal Boundaries
Consider
\[ \begin{cases} y>-1,\\ y\le4. \end{cases} \]The solution is the horizontal strip
\[ \boxed{-1Standard-Form Inequalities
Many constraints appear naturally as
\[ Ax+By\le C. \]For example,
\[ 3x+5y\le60 \]may represent a resource limit.
There is no need to solve for \(y\) unless doing so makes graphing or interpretation easier.
Graphing a Standard-Form Inequality by Intercepts
Consider
\[ 2x+3y\le12. \]The boundary line is
\[ 2x+3y=12. \]The intercepts are
\[ (6,0) \]and
\[ (0,4). \]Draw the solid line through those points.
Test the origin:
\[ 0\le12. \]True.
So shade the side containing the origin.
Graphing After Solving for \(y\)
The same inequality
\[ 2x+3y\le12 \]can be rewritten as
\[ 3y\le-2x+12, \] \[ \boxed{ y\le-\frac23x+4 }. \]Now the direction “shade below” is immediately visible.
Be Careful with Negative Division
Consider
\[ 2x-y>4. \]Solve for \(y\):
\[ -y>4-2x. \]Multiply by \(-1\) and reverse the inequality:
\[ \boxed{ y<2x-4 }. \]Forgetting the reversal would shade the wrong side.
Applied Example: Production Constraint
Suppose product \(x\) requires \(2\) machine-hours and product \(y\) requires \(4\) machine-hours.
At most \(40\) machine-hours are available.
The capacity condition is
\[ \boxed{ 2x+4y\le40 }. \]If production quantities cannot be negative, also require
\[ x\ge0, \qquad y\ge0. \]Production Feasible Region
The system is
\[ \begin{cases} 2x+4y\le40,\\ x\ge0,\\ y\ge0. \end{cases} \]The boundary
\[ 2x+4y=40 \]has intercepts
\[ (20,0) \]and
\[ (0,10). \]The feasible region is the first-quadrant triangle on or below that line.
Adding a Second Resource Constraint
Suppose the same products also require labor:
\[ 3x+y\le30. \]Now the system becomes
\[ \begin{cases} 2x+4y\le40,\\ 3x+y\le30,\\ x\ge0,\\ y\ge0. \end{cases} \]The feasible region is the overlap of all four conditions.
Boundary Intersections Become Candidate Vertices
To find where
\[ 2x+4y=40 \]and
\[ 3x+y=30 \]meet, solve the system of equations.
From
\[ 3x+y=30, \]we get
\[ y=30-3x. \]Substitute:
\[ 2x+4(30-3x)=40. \]Then
\[ 2x+120-12x=40, \] \[ -10x=-80, \] \[ x=8. \]So
\[ y=6. \]The boundary lines intersect at
\[ \boxed{(8,6)}. \]Verify a Candidate Vertex
Check
\[ (8,6) \]in the original inequalities:
\[ 2(8)+4(6)=40, \]and
\[ 3(8)+6=30. \]Both are satisfied exactly.
Because
\[ 8\ge0 \]and
\[ 6\ge0, \]the point is feasible.
Not Every Boundary Intersection Is Feasible
With several constraints, two boundary lines may intersect at a point that violates a third inequality.
Therefore, every candidate vertex should be checked against the entire system.
Budget Example
Suppose item \(x\) costs \$4 and item \(y\) costs \$7.
A buyer can spend at most \$70:
\[ 4x+7y\le70. \]If quantities must be nonnegative:
\[ x\ge0, \qquad y\ge0. \]If the items are indivisible, we may additionally require
\[ x,y\in\mathbb{Z}. \]Continuous Region Versus Discrete Feasible Points
The inequality system may describe a continuous polygonal region over real numbers.
But if \(x\) and \(y\) count objects, only integer lattice points inside that region are practically meaningful.
This distinction becomes important in integer programming.
Minimum Requirements
Suppose a blend must contain at least \(20\) units of one nutrient:
\[ 3x+5y\ge20. \]This inequality selects the side on or beyond the threshold line.
Systems may therefore mix upper bounds and lower bounds.
Example with Upper and Lower Bounds
Consider
\[ \begin{cases} x+y\le10,\\ x+y\ge4,\\ x\ge0,\\ y\ge0. \end{cases} \]The solution lies between the parallel lines
\[ x+y=4 \]and
\[ x+y=10 \]inside the first quadrant.
Feasible Bands
When one quantity must stay between lower and upper limits, the solution often forms a band.
For example,
\[ 4\le x+y\le10 \]means both
\[ x+y\ge4 \]and
\[ x+y\le10. \]Systems Can Describe Geometry
A rectangle can be represented by
\[ \begin{cases} a\le x\le b,\\ c\le y\le d. \end{cases} \]For example,
\[ \begin{cases} 1\le x\le5,\\ -2\le y\le3 \end{cases} \]describes a closed rectangular region.
Triangular Regions
A triangular region can be formed by three nonparallel boundary inequalities.
For example,
\[ \begin{cases} x\ge0,\\ y\ge0,\\ x+y\le6. \end{cases} \]The three boundary lines form a triangle.
Polygonal Regions
Several linear inequalities can combine to form polygons with many sides.
Each active boundary contributes part of the feasible region's edge.
This geometry is fundamental to later linear programming.
Inactive or Redundant Boundaries
An inequality may have a boundary line that never forms part of the final feasible region.
If another constraint is stricter everywhere relevant, the weaker boundary is inactive.
This is the geometric version of redundancy.
Systems of Strict Inequalities Can Be Open Regions
A system such as
\[ \begin{cases} x>0,\\ y>0,\\ x+y<6 \end{cases} \]describes the interior of a triangle without its sides.
Topologically, the feasible region is open relative to those boundaries.
Inclusive Systems Can Be Closed Regions
The system
\[ \begin{cases} x\ge0,\\ y\ge0,\\ x+y\le6 \end{cases} \]includes all three boundary segments.
The triangular feasible region is closed and bounded.
Checking Feasibility Algebraically
A point belongs to the feasible region if substitution makes every inequality true.
This gives an exact algebraic check independent of the graph.
Graphing as a Representation of Logical Intersection
Each shaded half-plane represents one solution set.
The final overlap represents logical conjunction:
\[ \boxed{\text{condition 1 and condition 2 and condition 3}}. \]The graph is therefore a visual representation of set intersection and logic.
Systems of Inequalities and Optimization Preview
Suppose a business has a feasible production region.
A later problem may ask which feasible point maximizes profit or minimizes cost.
That adds an objective function to the constraint system.
The present lesson focuses only on describing the feasible region itself.
Objective Functions Are Separate from Constraints
For example, constraints may be
\[ \begin{cases} 2x+4y\le40,\\ 3x+y\le30,\\ x\ge0,\\ y\ge0, \end{cases} \]while profit might be
\[ P=5x+8y. \]The inequalities define what is allowed.
The objective function measures how desirable each allowed point is.
Systems of Inequalities with More Variables
In three variables, a linear inequality such as
\[ Ax+By+Cz\le D \]describes one side of a plane in three-dimensional space.
A system of such inequalities describes an intersection of half-spaces.
Higher-Dimensional Feasible Regions
In many variables, linear inequalities define higher-dimensional regions called polyhedra or, more generally, convex feasible sets.
The two-dimensional shaded polygon is the simplest visual case of a much broader idea.
Convexity Preview
Linear inequality feasible regions are convex.
Informally, this means that if two points are feasible, then the entire line segment connecting them is also feasible.
This property becomes important later in optimization and geometry.
Why Convexity Holds
Suppose both points satisfy
\[ Ax+By\le C. \]A weighted average of the two points also satisfies the same linear inequality.
Because intersections of convex sets remain convex, a system of linear inequalities also has a convex feasible region.
Test-Point Method for a Full System
To graph
\[ \begin{cases} 2x+y\le8,\\ x-y\ge1, \end{cases} \]graph each boundary:
\[ 2x+y=8, \] \[ x-y=1. \]Then test a convenient point for each inequality separately.
Finally, keep only the overlapping shaded region.
Boundary Intersections Help Organize the Graph
For the system
\[ \begin{cases} 2x+y\le8,\\ x-y\ge1, \end{cases} \]the boundary lines intersect where
\[ 2x+y=8 \]and
\[ x-y=1. \]From
\[ x-y=1, \]we have
\[ y=x-1. \]Substitute:
\[ 2x+x-1=8, \] \[ 3x=9, \] \[ x=3, \] \[ y=2. \]So the boundaries meet at
\[ \boxed{(3,2)}. \]Parallel Boundary Systems
Consider
\[ \begin{cases} y\ge2x+1,\\ y\le2x+5. \end{cases} \]The boundaries are parallel.
The feasible region is the strip between them, including both lines.
Parallel Constraints Can Also Be Inconsistent
Consider
\[ \begin{cases} y\ge2x+5,\\ y\le2x+1. \end{cases} \]Now the required upper region starts above the required lower region.
No overlap exists.
The system is infeasible.
Coincident Boundaries
Consider
\[ \begin{cases} 2x+4y\le8,\\ x+2y\le4. \end{cases} \]The inequalities are equivalent.
The second constraint adds no new information.
The system has the same solution set as either inequality alone.
Reversed Equivalent Boundaries
Consider
\[ \begin{cases} x+y\le5,\\ 2x+2y\ge10. \end{cases} \]The second inequality simplifies to
\[ x+y\ge5. \]Both can be true only when
\[ \boxed{x+y=5}. \]The system solution collapses from a two-dimensional region to a line.
A System Can Have Lower-Dimensional Solutions
Although many systems of inequalities produce regions with area, some produce:
- a line;
- a line segment;
- a single point;
- the empty set.
The dimension of the solution set depends on how the constraints interact.
Single-Point Feasible Region Example
Consider
\[ \begin{cases} x\ge2,\\ x\le2,\\ y\ge3,\\ y\le3. \end{cases} \]The only possible values are
\[ x=2, \qquad y=3. \]So the feasible region is the single point
\[ \boxed{(2,3)}. \]A Reliable Single-Inequality Graphing Workflow
- Replace the inequality with equality to find the boundary line.
- Graph the boundary accurately.
- Use a solid line for \(\le\) or \(\ge\).
- Use a dashed line for \(<\) or \(>\).
- Use the solved-for-\(y\) direction or a test point to choose the correct side.
A Reliable System-Graphing Workflow
- Graph each boundary line.
- Mark each boundary as solid or dashed.
- Shade the permitted half-plane for each inequality.
- Identify the overlap of all shaded regions.
- Find important boundary intersections.
- Check representative points algebraically.
A Reliable Feasible-Region Workflow
- List every constraint.
- Add nonnegativity or domain restrictions when required.
- Graph all boundaries.
- Find the common overlap.
- Identify candidate vertices.
- Verify each candidate against every inequality.
- Determine whether the region is bounded, unbounded, empty, or lower-dimensional.
A Reliable Applied-Constraint Workflow
- Define the variables and units.
- Translate phrases such as at most, at least, no more than, and no less than.
- Construct one inequality per independent constraint.
- Add physical restrictions such as \(x\ge0\) and \(y\ge0\).
- Graph or solve for the feasible region.
- Interpret the geometry in context.
Common Translation Phrases
| Phrase | Symbol |
|---|---|
| at most | \(\le\) |
| no more than | \(\le\) |
| at least | \(\ge\) |
| no less than | \(\ge\) |
| more than | \(>\) |
| less than | \(<\) |
Common Errors
Shading the Union Instead of the Intersection
A system requires every inequality to hold, so use the overlapping region.
Using a Solid Line for a Strict Inequality
\(<\) and \(>\) exclude the boundary and require dashed lines.
Using a Dashed Line for an Inclusive Inequality
\(\le\) and \(\ge\) include the boundary and require solid lines.
Forgetting to Reverse the Symbol When Solving for \(y\)
Dividing by a negative number reverses the inequality.
Testing a Point on the Boundary
A boundary point cannot distinguish which side satisfies a strict inequality. Choose a point off the line.
Ignoring Nonnegativity
Applied quantities such as production, time, and inventory often require \(x\ge0\) and \(y\ge0\).
Assuming Every Boundary Intersection Is Feasible
A candidate vertex must satisfy every inequality in the system.
Missing Redundant Constraints
Some inequalities add no new restriction and may never form part of the final boundary.
Assuming Every Feasible Region Is Bounded
Many systems produce unbounded strips, wedges, or half-planes.
Ignoring Discrete Domains
If variables count objects, only integer points may be meaningful even though the graphical region is continuous.
Practice
1. Check a Point
Does
\[ (2,3) \]satisfy
\[ \begin{cases} x+y\le6,\\ x\ge0,\\ y\ge0? \end{cases} \]Check Answer
\[ 2+3=5\le6, \] \[ 2\ge0, \] \[ 3\ge0. \]All conditions are true.
\[ \boxed{\text{Yes.}} \]2. Boundary Type
Should the boundary of
\[ y<3x+2 \]be solid or dashed?
Check Answer
The inequality is strict, so the boundary is
\[ \boxed{\text{dashed}}. \]3. Shade Above or Below
For
\[ y\ge-2x+5, \]which side of the boundary is shaded?
Check Answer
Because \(y\) is greater than or equal to the line, shade
\[ \boxed{\text{on or above the boundary}}. \]4. Test-Point Method
Does the origin satisfy
\[ 3x+2y>8? \]Check Answer
\[ 3(0)+2(0)>8 \]becomes
\[ 0>8, \]which is false.
So the solution lies on the side opposite the origin.
5. One-Variable System
Solve
\[ \begin{cases} x>-1,\\ x\le4. \end{cases} \]Check Answer
\[ \boxed{-16. No-Solution System
Determine the solution set:
\[ \begin{cases} x\ge5,\\ x<2. \end{cases} \]Check Answer
No real number satisfies both inequalities.
\[ \boxed{\varnothing}. \]7. First-Quadrant Feasible Region
What are the vertices of
\[ \begin{cases} x+y\le8,\\ x\ge0,\\ y\ge0? \end{cases} \]Check Answer
The boundary intercepts are
\[ (8,0) \]and
\[ (0,8). \]Including the origin, the vertices are
\[ \boxed{(0,0),\ (8,0),\ (0,8)}. \]8. Standard-Form Constraint
A product \(x\) uses \(2\) hours and product \(y\) uses \(5\) hours. At most \(50\) hours are available. Write the system including nonnegativity.
Check Answer
\[ \boxed{ \begin{cases} 2x+5y\le50,\\ x\ge0,\\ y\ge0. \end{cases} } \]9. Boundary Intersection
Find the intersection of
\[ x+y=7 \]and
\[ 2x+y=10. \]Check Answer
Subtract the first equation from the second:
\[ x=3. \]Then
\[ y=4. \]So the intersection is
\[ \boxed{(3,4)}. \]10. Redundant Constraint
In
\[ \begin{cases} x+y\le6,\\ x+y\le10, \end{cases} \]which inequality is redundant?
Check Answer
If
\[ x+y\le6, \]then
\[ x+y\le10 \]is automatically true.
So
\[ \boxed{x+y\le10} \]is redundant.
11. Strip Between Parallel Lines
Describe the solution of
\[ \begin{cases} y\ge2x+1,\\ y\le2x+5. \end{cases} \]Check Answer
The solution is the strip between the two parallel lines, including both boundaries.
12. Collapsed Region
Solve
\[ \begin{cases} x+y\le4,\\ x+y\ge4. \end{cases} \]Check Answer
Both inequalities can hold only when
\[ \boxed{x+y=4}. \]The solution set is the boundary line itself.
Key Ideas
- A system of inequalities requires all inequality conditions to hold simultaneously.
- The solution set is the intersection of the individual solution sets.
- A linear inequality in two variables describes a half-plane separated by a boundary line.
- Use solid boundaries for \(\le\) and \(\ge\), and dashed boundaries for \(<\) and \(>\).
- Test points help determine which side of a boundary satisfies an inequality.
- The overlap of all permitted half-planes is the feasible region.
- Feasible regions may be bounded, unbounded, empty, or lower-dimensional.
- Boundary intersections often form vertices of polygonal feasible regions.
- Every candidate vertex must satisfy every original constraint.
- Redundant inequalities add no new restriction.
- Applied systems commonly include resource limits, minimum requirements, budgets, and nonnegativity constraints.
- Continuous graphical regions may need to be restricted to integer points when variables count discrete objects.
- Systems of linear inequalities form the foundation of feasible-region methods and linear optimization.
Where This Leads
Systems of inequalities extend simultaneous reasoning from isolated intersection points to entire regions of allowable values. Instead of asking where several equations are exactly equal, we ask where several upper bounds, lower bounds, thresholds, and domain restrictions all hold together.
From here, Systems and Matrix Methods can move deeper into substitution and elimination, augmented matrices, row operations, Gaussian elimination, matrix equations, determinants, rank, and eventually optimization problems where a linear objective is evaluated over a feasible region defined by systems of inequalities.