The Central Idea

A population process describes how the number or state of individuals changes over time.

The simplest model tracks only population size:

\[ N_0,N_1,N_2,\ldots \]

More detailed models divide the population into classes, such as:

The central mathematical question is:

\[ \boxed{\text{how does the population state change from one time step to the next?}} \]

Population Balance

A basic population accounting identity is

\[ \boxed{ N_{\text{new}} = N_{\text{old}} +B-D+I-E }. \]

Here:

A First Population Example

Suppose a population begins the year with

\[ 1200 \]

individuals.

During the year:

Then

\[ 1200+180-90+40-25 = \boxed{1305}. \]

Discrete-Time Growth

A simple deterministic growth model assumes that population changes by a fixed proportion each time step.

If \(r\) is the per-period growth rate, then

\[ \boxed{ N_{t+1}=(1+r)N_t }. \]

Let

\[ \lambda=1+r. \]

Then

\[ \boxed{N_{t+1}=\lambda N_t}. \]

Geometric Population Growth

Repeated application gives

\[ N_t=N_0\lambda^t. \]

Therefore,

\[ \boxed{ N_t=N_0(1+r)^t }. \]

This is the discrete analogue of exponential growth.

Growth Example

Suppose

\[ N_0=500 \]

and the population increases by \(8\%\) per year.

Then

\[ \lambda=1.08. \]

After \(4\) years,

\[ N_4=500(1.08)^4 \approx \boxed{680.2}. \]

A real count would ordinarily be interpreted with appropriate rounding or a more detailed integer-valued model.

Growth Factor Interpretation

If

\[ \lambda>1, \]

the population grows geometrically.

If

\[ \lambda=1, \]

the population remains constant.

If

\[ 0<\lambda<1, \]

the population declines geometrically.

Per-Capita Change

A useful quantity is change per individual.

If

\[ \Delta N=N_{t+1}-N_t, \]

then the proportional change is

\[ \boxed{ \frac{\Delta N}{N_t} }. \]

In the simple geometric model, this quantity equals \(r\).

Birth and Death Rates

Suppose each individual contributes an average birth rate \(b\) and death rate \(d\) per period.

A simple deterministic recurrence is

\[ N_{t+1} = N_t+bN_t-dN_t. \]

Therefore,

\[ \boxed{ N_{t+1}=(1+b-d)N_t }. \]

Net Growth Rate

Define

\[ r=b-d. \]

Then

\[ N_{t+1}=(1+r)N_t. \]

Birth and death rates therefore combine into a net growth rate in the simplest model.

Density Dependence

Unlimited geometric growth is often unrealistic.

As population grows, competition for:

may reduce future growth.

This motivates density-dependent models.

The Logistic Map

One discrete density-dependent model is

\[ \boxed{ N_{t+1} = N_t+rN_t\left(1-\frac{N_t}{K}\right) }. \]

Here:

Carrying Capacity

The parameter \(K\) represents a population scale at which net growth is reduced to zero in the standard logistic form.

When

\[ N_t=K, \]

then

\[ 1-\frac{N_t}{K}=0. \]

Therefore,

\[ N_{t+1}=N_t. \]

Logistic Example

Suppose

\[ N_t=400, \qquad r=0.3, \qquad K=1000. \]

Then

\[ N_{t+1} = 400+0.3(400)\left(1-\frac{400}{1000}\right). \]

Since

\[ 1-\frac{400}{1000}=0.6, \]

we get

\[ N_{t+1} = 400+120(0.6) = 400+72 = \boxed{472}. \]

Deterministic Versus Stochastic Models

A deterministic model gives one next state from a given current state.

A stochastic model gives a probability distribution over possible next states.

For example, instead of assuming exactly \(20\) births, a model may let the number of births be random.

Why Randomness Matters in Populations

Random variation can arise from:

Randomness is especially important in small populations.

Binomial Survival Model

Suppose a population has \(N\) individuals and each survives independently with probability \(s\).

Then the number of survivors \(X\) can be modeled as

\[ \boxed{ X\sim\operatorname{Binomial}(N,s) }. \]

Therefore,

\[ E[X]=Ns. \]

Survival Example

Suppose

\[ N=100 \]

and each individual survives independently with probability

\[ s=0.85. \]

Then the expected number of survivors is

\[ E[X]=100(0.85)=\boxed{85}. \]

Expected Value Is Not a Guarantee

If the expected number of survivors is \(85\), the actual number need not be exactly \(85\).

Expected value is a long-run average or probability-weighted center, not a guaranteed outcome for one population.

Branching Processes

A branching process models reproduction when each individual independently produces a random number of descendants.

Let

\[ X \]

be the number of offspring produced by one individual.

If the current generation contains \(Z_t\) individuals, then

\[ \boxed{ Z_{t+1} = X_1+X_2+\cdots+X_{Z_t} }. \]

Mean Offspring Number

Let

\[ m=E[X]. \]

Then \(m\) is the expected number of descendants per individual.

In a basic Galton-Watson branching process:

Expected Branching Population

If

\[ Z_0=z_0 \]

and each individual has mean offspring number \(m\), then

\[ \boxed{ E[Z_t]=z_0m^t }. \]

This resembles geometric growth, but the actual population remains random.

Branching Example

Suppose

\[ Z_0=10 \]

and

\[ m=1.2. \]

Then

\[ E[Z_3] = 10(1.2)^3 = 10(1.728) = \boxed{17.28}. \]

Extinction

In a branching process, extinction occurs if the population eventually reaches

\[ Z_t=0. \]

Once the process reaches zero, no further descendants appear in the basic model.

Supercritical Does Not Mean Guaranteed Survival

Even when

\[ m>1, \]

extinction can still occur with positive probability in many branching processes.

The condition \(m>1\) concerns expected reproduction, not certainty for one realization.

Generating Functions in Branching Processes

If offspring probabilities are

\[ P(X=k)=p_k, \]

the probability generating function is

\[ \boxed{ G(s)=\sum_{k=0}^{\infty}p_ks^k }. \]

Generating functions provide a compact way to study offspring distributions and extinction probabilities.

Extinction Equation

In a standard branching process, the eventual extinction probability \(q\) is the smallest solution in \([0,1]\) of

\[ \boxed{G(q)=q}. \]

This is an important example of a probability problem becoming a fixed-point problem.

Age-Structured Populations

Populations often contain classes with different survival and reproduction rates.

For example, we may divide a population into:

\[ \text{juveniles},\qquad \text{adults}. \]

A vector can represent the state:

\[ \boxed{ \mathbf n_t= \begin{bmatrix} J_t\\ A_t \end{bmatrix} }. \]

Matrix Population Models

A linear class-structured model can be written

\[ \boxed{ \mathbf n_{t+1}=A\mathbf n_t }. \]

The entries of \(A\) can represent:

A Two-Class Example

Suppose

\[ A= \begin{bmatrix} 0 & 1.5\\ 0.6 & 0.8 \end{bmatrix} \]

and

\[ \mathbf n_t= \begin{bmatrix} 100\\ 200 \end{bmatrix}. \]

Then

\[ \mathbf n_{t+1} = \begin{bmatrix} 0(100)+1.5(200)\\ 0.6(100)+0.8(200) \end{bmatrix}. \]

Therefore,

\[ \boxed{ \mathbf n_{t+1} = \begin{bmatrix} 300\\ 220 \end{bmatrix} }. \]

Markov Population States

Sometimes the number of individuals is fixed while individuals move among states.

Examples include:

Markov chains can model these transitions.

Transition Matrices

Suppose a two-state system has transition matrix

\[ P= \begin{bmatrix} 0.8 & 0.2\\ 0.3 & 0.7 \end{bmatrix}. \]

Each row gives probabilities of moving from one current state to the next state.

Each row sums to

\[ \boxed{1}. \]

Population Proportions Under Markov Transitions

If the row vector

\[ \boldsymbol\pi_t \]

gives current state proportions, then

\[ \boxed{ \boldsymbol\pi_{t+1} = \boldsymbol\pi_tP }. \]

Repeated multiplication models the evolution of the population distribution across states.

Migration Models

Population change may occur through migration between locations.

A transition matrix can represent the fraction moving from one region to another each period.

This can model:

Survival Analysis as State Transition

A simple survival process has states

\[ \text{alive} \]

and

\[ \text{dead}. \]

Death is an absorbing state because once entered, the process does not return to alive in the standard model.

Absorbing States

A state \(i\) is absorbing if

\[ \boxed{P_{ii}=1}. \]

Once the process enters that state, it remains there.

Absorbing-state models appear in:

Infection Processes

Disease spread can be modeled by dividing a population into health states.

A classic structure is:

\[ S=\text{susceptible}, \qquad I=\text{infectious}, \qquad R=\text{removed or recovered}. \]

The state at time \(t\) can be written

\[ (S_t,I_t,R_t). \]

Discrete SIR-Style Change

A simplified discrete-time model might use

\[ \Delta S_t = -\beta\frac{S_tI_t}{N}, \] \[ \Delta I_t = \beta\frac{S_tI_t}{N} - \gamma I_t, \] \[ \Delta R_t = \gamma I_t. \]

This is a deterministic approximation. Real infection and recovery counts can be modeled stochastically.

Basic Reproduction Number

In epidemic modeling, a reproduction measure such as

\[ R_0 \]

summarizes the expected number of secondary infections generated by a typical infectious individual under specified conditions.

The exact formula depends on the model.

In simple settings:

Expected Spread Is Not Guaranteed Spread

Even if a reproduction measure exceeds \(1\), early transmission can still die out by chance when case numbers are small.

This is another branching-process idea:

\[ \boxed{\text{average growth can coexist with a positive extinction probability}}. \]

Contact Networks

Homogeneous mixing assumes every individual interacts in roughly the same way.

Real contact patterns are often networked.

A graph can represent:

Network structure can strongly affect spread.

Population Variance

Stochastic population models describe not only expected population size but also variability.

Two models can have the same

\[ E[N_t] \]

while having very different

\[ \operatorname{Var}(N_t). \]

Variability matters when extinction, thresholds, or capacity limits are important.

Small-Population Risk

Random fluctuations have greater proportional effects in small populations.

Losing \(10\) individuals from a population of \(10000\) is a small fractional change.

Losing \(10\) from a population of \(20\) is potentially catastrophic.

This is why stochastic models are often especially important in conservation and outbreak initiation.

Demographic Stochasticity

Demographic stochasticity is random variation arising from individual birth, death, reproduction, or transition events.

Even in a constant environment, individual outcomes differ.

Environmental Stochasticity

Environmental stochasticity arises when external conditions affect many individuals simultaneously.

Examples include:

Environmental effects can create correlated population outcomes.

Population Thresholds

Some systems behave differently above or below a threshold.

Thresholds can arise from:

Threshold models are often nonlinear.

Harvesting and Removal

A population may experience planned removal through harvesting, culling, or extraction.

A simple recurrence is

\[ \boxed{ N_{t+1}=f(N_t)-H_t }. \]

Here \(f(N_t)\) describes biological growth and \(H_t\) is the number removed.

Harvesting Example

Suppose a population grows according to

\[ N_{t+1}=1.1N_t \]

before harvest.

If

\[ N_t=500 \]

and \(40\) individuals are removed, then

\[ N_{t+1}=1.1(500)-40. \]

Therefore,

\[ N_{t+1}=550-40=\boxed{510}. \]

Stochastic Harvest Risk

A harvest level that appears sustainable under average growth can become risky if actual reproduction varies.

Therefore, management decisions may need to consider:

Simulation of Population Processes

Simulation is useful when:

A Simple Survival Simulation

Suppose \(100\) individuals each survive one period with probability

\[ 0.9. \]

One simulation can generate \(100\) independent Bernoulli outcomes and count the survivors.

Repeating the simulation many times estimates the distribution of future population size.

Monte Carlo Population Analysis

A Monte Carlo study repeats a stochastic model many times.

It can estimate quantities such as:

Common Error: Treating Expected Population as the Actual Population

If

\[ E[N_t]=50, \]

one realization may produce

\[ 41,\ 53,\ 67, \]

or another value.

Expected value summarizes the distribution; it does not determine one sample path.

Common Error: Assuming Constant Percentage Growth Forever

Geometric growth can be useful over limited ranges.

But long-run growth may be limited by:

Model assumptions should match the scale and time horizon.

Common Error: Confusing Growth Rate and Growth Factor

If the growth rate is

\[ r=0.08, \]

the growth factor is

\[ 1+r=1.08. \]

Multiplying by \(0.08\) gives only the change amount, not the next total.

Common Error: Ignoring Integer Counts

Deterministic models can produce values such as

\[ 680.2. \]

Real populations contain whole individuals.

Fractional values may represent an expectation, approximation, density, or scaled quantity rather than a literal count.

Common Error: Assuming Independence Without Justification

Individual survival events may be correlated if individuals share the same environment.

A drought, storm, or disease event can affect many individuals together.

Independence is a model assumption, not an automatic fact.

Common Error: Mixing Deterministic and Stochastic Quantities

A recurrence such as

\[ N_{t+1}=1.05N_t \]

produces a deterministic next value.

A branching or binomial model produces a probability distribution.

These should not be interpreted in the same way.

Common Error: Treating \(R_0\) as a Fixed Universal Constant

Reproduction measures depend on:

Their interpretation must remain tied to the assumptions used to estimate them.

A Reliable Procedure for Deterministic Population Models

  1. Define the population being counted.
  2. Choose the time step.
  3. Identify births, deaths, immigration, and emigration.
  4. Determine whether proportional growth is reasonable.
  5. Write the recurrence relation.
  6. Calculate one step carefully.
  7. Iterate or derive a closed form when possible.
  8. Check whether resource limits or density dependence should be included.
  9. Interpret fractional outputs appropriately.

A Reliable Procedure for Stochastic Population Models

  1. Define the random events.
  2. Identify the probability distribution for each event.
  3. State independence or dependence assumptions.
  4. Write the transition or reproduction rule.
  5. Calculate expected values and variances when useful.
  6. Identify absorbing states or extinction conditions.
  7. Use simulation when the full distribution is difficult to derive.
  8. Report probabilities, not only averages.

A Reliable Procedure for Markov Population Models

  1. Define the states.
  2. Estimate transition probabilities.
  3. Build the transition matrix.
  4. Verify that each row sums to \(1\).
  5. Represent the current state distribution.
  6. Multiply by the transition matrix.
  7. Repeat for multiple periods if required.
  8. Interpret stable or absorbing behavior when relevant.

Example: Full Deterministic Workflow

Suppose a population begins at

\[ N_0=800 \]

and grows by \(5\%\) per year.

The growth factor is

\[ \lambda=1.05. \]

After \(3\) years,

\[ N_3=800(1.05)^3. \]

Therefore,

\[ N_3 = 800(1.157625) = \boxed{926.1}. \]

Example: Full Stochastic Survival Workflow

Suppose \(60\) animals each survive independently with probability

\[ s=0.8. \]

Then

\[ X\sim\operatorname{Binomial}(60,0.8). \]

Expected survivors:

\[ E[X]=60(0.8)=\boxed{48}. \]

Variance:

\[ \operatorname{Var}(X) = 60(0.8)(0.2) = \boxed{9.6}. \]

Example: Full Markov Workflow

Suppose a population is divided between locations A and B.

Transition matrix:

\[ P= \begin{bmatrix} 0.9 & 0.1\\ 0.2 & 0.8 \end{bmatrix}. \]

Current proportions:

\[ \boldsymbol\pi_0= \begin{bmatrix} 0.6 & 0.4 \end{bmatrix}. \]

Then

\[ \boldsymbol\pi_1 = \boldsymbol\pi_0P. \]

Therefore,

\[ \boldsymbol\pi_1 = \begin{bmatrix} 0.6(0.9)+0.4(0.2) & 0.6(0.1)+0.4(0.8) \end{bmatrix}. \]

So

\[ \boxed{ \boldsymbol\pi_1= \begin{bmatrix} 0.62 & 0.38 \end{bmatrix} }. \]

Practice 1: Population Balance

A population begins at \(900\), has \(120\) births, \(70\) deaths, \(25\) immigrants, and \(15\) emigrants.

Find the new population.

Practice 2: Growth Factor

A population grows by \(6\%\) per year.

Find the growth factor.

Practice 3: Geometric Growth

A population begins at \(400\) and grows by \(10\%\) per period.

Find the population after \(2\) periods.

Practice 4: Expected Survivors

A group contains \(80\) individuals, each surviving independently with probability \(0.75\).

Find the expected number of survivors.

Practice 5: Branching Expectation

A branching process begins with \(5\) individuals and has mean offspring number

\[ m=1.4. \]

Find

\[ E[Z_2]. \]

Practice 6: Logistic Update

Suppose

\[ N_t=200,\qquad r=0.5,\qquad K=1000. \]

Use

\[ N_{t+1}=N_t+rN_t\left(1-\frac{N_t}{K}\right) \]

to find the next population.

Practice 7: Markov Row Check

Is

\[ [0.3,\ 0.4,\ 0.3] \]

a valid probability row of a transition matrix?

Practice 8: Absorbing State

What must the self-transition probability \(P_{ii}\) equal for state \(i\) to be absorbing?

Practice 9: Harvesting

A population of \(300\) grows by \(20\%\) before a harvest of \(50\).

Find the population after growth and harvest.

Practice 10: Expected Value Interpretation

If the expected future population is \(72\), must the actual future population equal \(72\)?

Practice Answers

Practice 1

\[ 900+120-70+25-15 = \boxed{960}. \]

Practice 2

\[ 1+0.06=\boxed{1.06}. \]

Practice 3

\[ N_2=400(1.10)^2 =400(1.21) = \boxed{484}. \]

Practice 4

\[ E[X]=80(0.75)=\boxed{60}. \]

Practice 5

\[ E[Z_2]=5(1.4)^2 =5(1.96) = \boxed{9.8}. \]

Practice 6

\[ N_{t+1} = 200+0.5(200)\left(1-\frac{200}{1000}\right). \] \[ = 200+100(0.8) = \boxed{280}. \]

Practice 7

Yes.

\[ 0.3+0.4+0.3=\boxed{1}. \]

Practice 8

\[ \boxed{P_{ii}=1}. \]

Practice 9

First grow:

\[ 300(1.2)=360. \]

Then harvest:

\[ 360-50=\boxed{310}. \]

Practice 10

No.

Expected value is a probability-weighted average, not a guaranteed outcome for one realization.

What to Remember

Biological and population processes combine recurrence relations, probability, stochastic processes, matrices, and simulation.

The central habit is: decide whether the system is best modeled by deterministic change, random individual events, state transitions, or a combination of all three.

Where We Go Next

Biological and population processes show how discrete and stochastic models describe growth, survival, transition, and extinction. The next applied problem family uses similar probability tools to study uncertain financial outcomes, claims, losses, portfolios, and risk.

The next lesson, Finance, Insurance, and Risk, develops expected-value, probability, loss-distribution, and decision models for financial and insurance systems.