The Central Idea

A triangle is a polygon formed by three line segments joining three noncollinear points.

Every triangle can be classified in two independent ways:

These two classification systems work together. A triangle can therefore be described with a combined name such as acute scalene, right isosceles, or obtuse scalene.

\[ \boxed{\text{triangle classification}=\text{side type}+\text{angle type}} \]

What Is a Triangle?

Let three noncollinear points be called \(A\), \(B\), and \(C\). Joining the points with segments \(\overline{AB}\), \(\overline{BC}\), and \(\overline{CA}\) forms triangle \(ABC\).

\[ \boxed{\triangle ABC} \]

The requirement that the points be noncollinear matters. If all three points lie on one line, the figure collapses and does not form an ordinary Euclidean triangle.

Vertices, Sides, and Angles

A triangle has three vertices, three sides, and three interior angles.

For \(\triangle ABC\):

The side opposite \(\angle A\) is \(\overline{BC}\), the side opposite \(\angle B\) is \(\overline{AC}\), and the side opposite \(\angle C\) is \(\overline{AB}\).

Naming a Triangle

A triangle is named by listing its three vertices in order around the figure. For the same triangle, several names are possible:

\[ \triangle ABC,\qquad \triangle BCA,\qquad \triangle CAB. \]

Reversing direction also names the same triangle:

\[ \triangle ACB,\qquad \triangle CBA,\qquad \triangle BAC. \]

In later congruence and similarity statements, however, the order of the letters will carry additional information about corresponding parts.

Triangles Are Polygons

A triangle is the polygon with the fewest possible sides. A polygon must enclose a region using straight segments, and fewer than three segments cannot enclose a region in the Euclidean plane.

This makes the triangle a foundational building block. More complicated polygons can often be decomposed into triangles, allowing geometric questions about larger figures to be reduced to simpler triangular pieces.

Classification by Side Length

Side-based classification asks how many sides of the triangle have equal length.

There are three standard types:

Scalene Triangles

A scalene triangle has three different side lengths.

\[ AB\ne BC,\qquad BC\ne CA,\qquad CA\ne AB. \]

A triangle with side lengths

\[ 4,\qquad 5,\qquad 6 \]

is scalene because no two sides are equal.

Isosceles Triangles

An isosceles triangle has at least two equal sides.

If

\[ AB=AC, \]

then \(\triangle ABC\) is isosceles. The equal sides are often called the legs, and the remaining side \(\overline{BC}\) is the base.

The angle between the equal sides, \(\angle A\), is the vertex angle. The other two angles are the base angles.

Why “At Least Two” Matters

In the inclusive definition commonly used in modern mathematics, an isosceles triangle has at least two equal sides. Under this definition, every equilateral triangle is also isosceles.

Some elementary texts use an exclusive convention in which isosceles means exactly two equal sides. When classification depends on the convention, state the convention being used.

Malone Math uses the inclusive definition because it preserves the natural subset relationship:

\[ \boxed{\text{equilateral triangles}\subseteq\text{isosceles triangles}}. \]

Equilateral Triangles

An equilateral triangle has all three sides equal.

\[ AB=BC=CA. \]

In Euclidean geometry, an equilateral triangle is also equiangular: all three interior angles are equal.

Since the three angles together measure \(180^\circ\), each angle measures

\[ \frac{180^\circ}{3}=\boxed{60^\circ}. \]

Classification by Angle Measure

Angle-based classification is determined by the largest interior angle.

Because the total angle measure is \(180^\circ\), a triangle cannot have two right angles or two obtuse angles.

Acute Triangles

An acute triangle has three acute interior angles.

For example, a triangle with angles

\[ 50^\circ,\qquad 60^\circ,\qquad 70^\circ \]

is acute because every angle is less than \(90^\circ\).

Right Triangles

A right triangle contains one right angle.

\[ \boxed{90^\circ} \]

The side opposite the right angle is called the hypotenuse. The other two sides are the legs.

Since the two remaining angles must total \(90^\circ\), both are acute.

Obtuse Triangles

An obtuse triangle contains one angle greater than \(90^\circ\) and less than \(180^\circ\).

For example,

\[ 30^\circ,\qquad 40^\circ,\qquad 110^\circ \]

forms an obtuse triangle because \(110^\circ\) is obtuse.

The other two angles must be acute because their combined measure is only \(70^\circ\).

Equiangular Triangles

An equiangular triangle has three equal interior angles.

Since the angles sum to \(180^\circ\), each is \(60^\circ\):

\[ 60^\circ+60^\circ+60^\circ=180^\circ. \]

In Euclidean geometry, a triangle is equilateral if and only if it is equiangular.

Combined Classification

A complete basic classification can combine a side category and an angle category.

Examples include:

Not every apparent pairing is possible. For example, a right equilateral triangle cannot exist because every angle of an equilateral triangle is \(60^\circ\).

The Triangle Angle-Sum Relationship

In Euclidean geometry, the measures of the three interior angles of every triangle sum to \(180^\circ\).

\[ \boxed{m\angle A+m\angle B+m\angle C=180^\circ} \]

This relationship is one of the most frequently used facts in elementary geometry. Knowing any two interior angles determines the third.

Why the Angles Sum to \(180^\circ\)

The angle-sum relationship can be derived using parallel lines and a transversal.

Through one vertex of a triangle, draw a line parallel to the opposite side. The other two sides act as transversals. Alternate-interior-angle relationships transfer the two remote interior angles to the new line.

The three resulting adjacent angles form a straight angle, so their measures sum to

\[ \boxed{180^\circ}. \]

This also shows why the triangle angle sum belongs specifically to Euclidean geometry: the argument uses Euclidean parallel-line structure.

Example: Find a Missing Angle

Suppose two angles of a triangle measure \(48^\circ\) and \(67^\circ\). Let the third angle be \(x\).

\[ 48^\circ+67^\circ+x=180^\circ. \]

Combine the known angles:

\[ 115^\circ+x=180^\circ. \]

Therefore,

\[ \boxed{x=65^\circ}. \]

Example: Algebraic Angle Measures

Suppose the three angles measure

\[ x,\qquad 2x,\qquad 3x. \]

Use the triangle angle sum:

\[ x+2x+3x=180^\circ. \] \[ 6x=180^\circ. \] \[ x=30^\circ. \]

The angle measures are therefore

\[ \boxed{30^\circ,\qquad60^\circ,\qquad90^\circ}. \]

The triangle is a right triangle.

Exterior Angles of a Triangle

An exterior angle of a triangle is formed by one side of the triangle and the extension of an adjacent side.

The exterior angle and the adjacent interior angle form a linear pair, so they are supplementary.

\[ \boxed{m\angle_{\text{ext}}+m\angle_{\text{adjacent int}}=180^\circ} \]

The Exterior-Angle Relationship

The measure of an exterior angle of a triangle equals the sum of the two nonadjacent, or remote interior, angles.

If exterior angle \(D\) is adjacent to \(\angle C\), then

\[ \boxed{m\angle D=m\angle A+m\angle B}. \]

This follows directly from the triangle angle sum and the linear-pair relationship.

Example: Exterior Angle

Suppose the two remote interior angles measure \(35^\circ\) and \(72^\circ\).

The exterior angle measures

\[ 35^\circ+72^\circ=\boxed{107^\circ}. \]

The adjacent interior angle therefore measures

\[ 180^\circ-107^\circ=73^\circ. \]

One Exterior Angle at Each Vertex

If one exterior angle is chosen at each vertex of a triangle, all oriented consistently around the figure, their measures sum to \(360^\circ\).

\[ \boxed{e_1+e_2+e_3=360^\circ} \]

This is an early example of a broader polygon exterior-angle relationship developed later in the Euclidean Relationships sequence.

The Isosceles Triangle Relationship

In an isosceles triangle, equal sides are opposite equal angles.

If

\[ AB=AC, \]

then the base angles satisfy

\[ \boxed{m\angle B=m\angle C}. \]

This is often called the Isosceles Triangle Theorem or Base Angles Theorem.

The Converse Is Also True

If two angles of a triangle are congruent, then the sides opposite those angles are congruent.

Thus, if

\[ \angle B\cong\angle C, \]

then

\[ \boxed{AB=AC}. \]

The theorem and its converse create a two-way connection between equal sides and equal opposite angles.

Example: Isosceles Triangle Angles

Suppose an isosceles triangle has vertex angle \(40^\circ\). The two base angles are equal. Let each base angle be \(x\).

\[ 40^\circ+x+x=180^\circ. \] \[ 2x=140^\circ. \] \[ \boxed{x=70^\circ}. \]

The angle measures are

\[ \boxed{40^\circ,\qquad70^\circ,\qquad70^\circ}. \]

Opposite Sides and Opposite Angles

Side lengths and opposite angle measures are ordered together.

In any triangle:

This lets us compare sides without measuring them directly when the angle ordering is known, and compare angles when the side ordering is known.

Example: Ordering the Sides

Suppose

\[ m\angle A=40^\circ,\qquad m\angle B=55^\circ,\qquad m\angle C=85^\circ. \]

Since

\[ 40^\circ<55^\circ<85^\circ, \]

the opposite sides satisfy

\[ \boxed{BC<AC<AB}. \]

The Triangle Inequality

Not every three positive lengths can form a triangle. For a nondegenerate triangle, the sum of the lengths of any two sides must be greater than the length of the third side.

If the side lengths are \(a\), \(b\), and \(c\), then

\[ \boxed{ \begin{aligned} a+b&>c,\\ a+c&>b,\\ b+c&>a. \end{aligned}} \]

Why the Triangle Inequality Is Necessary

Imagine traveling from one endpoint of a side to the other by following the other two sides. That two-segment route must be longer than the direct side joining the endpoints.

If the two shorter lengths add to exactly the longest length, the three points fall on a straight line. If their sum is smaller, the endpoints cannot meet at all.

The Fast Triangle-Inequality Test

When three positive lengths are arranged so that

\[ a\le b\le c, \]

it is enough to test the two shorter sides against the longest:

\[ \boxed{a+b>c}. \]

If this strongest condition holds, the other two inequalities automatically hold because all side lengths are positive.

Example: Can These Lengths Form a Triangle?

Consider side lengths

\[ 5,\qquad7,\qquad10. \]

The two shorter sides satisfy

\[ 5+7=12>10. \]

Therefore, the lengths can form a nondegenerate triangle.

Example: A Failed Triangle Inequality

Consider

\[ 3,\qquad4,\qquad8. \]

The two shorter lengths give

\[ 3+4=7<8. \]

The segments cannot close to form a triangle.

Degenerate Triangles

If the two shorter lengths add exactly to the longest length, the three vertices become collinear.

For example,

\[ 3+4=7. \]

The lengths \(3\), \(4\), and \(7\) form a degenerate triangle in generalized usage, but not an ordinary nondegenerate Euclidean triangle.

Its enclosed area is zero.

Possible Length of a Third Side

If two side lengths are \(a\) and \(b\), then a third side \(x\) must satisfy

\[ \boxed{|a-b|<x<a+b}. \]

The upper bound comes from the ordinary triangle inequality. The lower bound prevents one known side together with \(x\) from being too short to reach the other known side.

Example: Range for the Third Side

Two sides have lengths \(8\) and \(13\). Let the third side be \(x\).

\[ |13-8|<x<13+8. \] \[ \boxed{5<x<21}. \]

If \(x\) must be a whole number, the possible values are \(6\) through \(20\).

Using Side Lengths to Predict Angle Type

Later, the Pythagorean relationship will provide a powerful numerical test for classifying a triangle as acute, right, or obtuse from its side lengths.

For now, remember the structural principle: the largest angle lies opposite the longest side. Therefore, the angle type of a triangle is controlled by the angle opposite its longest side.

The exact squared-length test belongs with the later Pythagorean lesson.

Coordinate Triangles

A triangle can be represented by three noncollinear points in the coordinate plane.

Coordinate methods allow us to calculate side lengths and slopes, then use those results to classify the triangle.

Common tools include:

The Distance Formula

For points \((x_1,y_1)\) and \((x_2,y_2)\), the distance between them is

\[ \boxed{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}. \]

Applying this formula to all three pairs of vertices gives the three side lengths of a coordinate triangle.

When only equality or ordering is needed, comparing squared distances can avoid unnecessary square roots.

Example: Classify by Sides from Coordinates

Let

\[ A(0,0),\qquad B(4,0),\qquad C(2,3). \]

Compare squared side lengths:

\[ AB^2=(4-0)^2+(0-0)^2=16, \] \[ AC^2=(2-0)^2+(3-0)^2=13, \] \[ BC^2=(2-4)^2+(3-0)^2=13. \]

Since \(AC=BC\), the triangle is

\[ \boxed{\text{isosceles}}. \]

Example: Identify a Right Triangle by Slopes

Let

\[ A(0,0),\qquad B(4,0),\qquad C(0,3). \]

Segment \(AB\) is horizontal and segment \(AC\) is vertical. Horizontal and vertical lines are perpendicular, so

\[ \angle A=90^\circ. \]

Therefore, \(\triangle ABC\) is a right triangle.

Collinearity Must Be Checked

Three listed coordinate points do not automatically form a triangle.

For example,

\[ A(0,0),\qquad B(1,1),\qquad C(2,2) \]

all lie on the line \(y=x\). The points are collinear, so they do not form a nondegenerate triangle.

Coordinate classification begins by confirming that the three vertices are not collinear.

A Triangle Cannot Have More Than One Right Angle

Suppose two interior angles were each \(90^\circ\). Their sum would already be

\[ 90^\circ+90^\circ=180^\circ. \]

No positive angle measure would remain for the third interior angle.

Therefore, a nondegenerate Euclidean triangle can contain at most one right angle.

A Triangle Cannot Have More Than One Obtuse Angle

Every obtuse angle measures more than \(90^\circ\). Two obtuse angles would therefore have a sum greater than \(180^\circ\), exceeding the entire interior-angle total of the triangle.

Thus, every obtuse triangle contains exactly one obtuse angle and two acute angles.

Every Equilateral Triangle Is Acute

Every angle of an equilateral triangle measures \(60^\circ\).

\[ 60^\circ<90^\circ. \]

Therefore,

\[ \boxed{\text{every equilateral triangle is acute}}. \]

This eliminates the categories right equilateral and obtuse equilateral in ordinary Euclidean geometry.

A Right Isosceles Triangle

A triangle can be both right and isosceles.

If one angle is \(90^\circ\) and the other two angles are equal, let each equal angle be \(x\):

\[ 90^\circ+x+x=180^\circ. \] \[ 2x=90^\circ, \] \[ \boxed{x=45^\circ}. \]

A right isosceles triangle therefore has angle measures

\[ \boxed{45^\circ,\qquad45^\circ,\qquad90^\circ}. \]

An Obtuse Isosceles Triangle

A triangle can also be both obtuse and isosceles.

Suppose the vertex angle is \(120^\circ\). The two equal base angles must share the remaining \(60^\circ\):

\[ \frac{60^\circ}{2}=30^\circ. \]

The triangle has angle measures

\[ \boxed{30^\circ,\qquad30^\circ,\qquad120^\circ}. \]

Classification from Partial Information

Sometimes a diagram gives only a few markings rather than numerical measurements.

Use only the information actually marked or stated. Do not classify a triangle from appearance alone.

Diagrams Are Not Measurements

A triangle may look isosceles without having marked equal sides. It may look right without a right-angle mark. It may appear acute or obtuse because of scaling or drawing distortion.

Unless the problem explicitly authorizes measurement, classify from given values, markings, coordinate calculations, or proven relationships.

Common Error: Classifying by Appearance

A student sees two sides that appear equal and declares the triangle isosceles.

Visual similarity is not sufficient evidence. Equal side lengths must be stated, marked, calculated, or proved.

Common Error: Forgetting the Inclusive Isosceles Definition

Under the inclusive definition, an equilateral triangle has at least two equal sides and therefore satisfies the definition of isosceles.

Saying that an equilateral triangle is “not isosceles” uses a different, exclusive convention.

Common Error: Using \(\ge\) in the Triangle Inequality

For an ordinary nondegenerate triangle, the sum of two side lengths must be strictly greater than the third side.

\[ a+b>c, \]

not

\[ a+b\ge c. \]

Equality produces a degenerate, collinear configuration.

Common Error: Forgetting the Third Angle

If two angle measures are known, the third is not found by comparing the two known angles. Use the full angle sum:

\[ m\angle C=180^\circ-m\angle A-m\angle B. \]

The result should be positive and less than \(180^\circ\).

Common Error: Confusing a Side with Its Opposite Angle

In \(\triangle ABC\), side \(\overline{BC}\) is opposite \(\angle A\), not \(\angle B\) or \(\angle C\).

A useful habit is to identify the vertex not contained in the side name. That vertex gives the opposite angle.

Common Error: Calling Every Equal-Looking Pair “Base Angles”

Base angles belong specifically to an isosceles triangle relative to its two equal sides and its base.

The term is not simply a label for the two lower-looking angles in a drawing. Rotating the triangle does not change which side is the base or which angles are the base angles.

A Reliable Procedure for Classifying a Triangle

  1. Confirm that three noncollinear points or three valid side lengths form a triangle.
  2. Compare side lengths to classify as scalene, isosceles, or equilateral.
  3. Determine the angle measures or identify the largest angle.
  4. Classify by angles as acute, right, or obtuse.
  5. Combine the two classifications when useful.
  6. Check that the classification is consistent with the angle sum and triangle inequality.

A Reliable Procedure for Missing-Angle Problems

  1. Identify all known interior angles.
  2. Use equal-angle information from isosceles structure when available.
  3. Write an equation whose interior-angle total is \(180^\circ\).
  4. Solve for the unknown.
  5. Substitute back if the angles are algebraic expressions.
  6. Verify that all three angles are positive and total \(180^\circ\).

A Reliable Procedure for Triangle-Inequality Problems

  1. Confirm that all proposed side lengths are positive.
  2. Order the lengths from least to greatest.
  3. Add the two shorter lengths.
  4. Compare their sum with the longest length.
  5. If the sum is greater, a nondegenerate triangle is possible.
  6. If the sum is equal, the configuration is degenerate.
  7. If the sum is smaller, no triangle can be formed.

Practice 1: Classify by Sides

Classify a triangle with side lengths

\[ 7,\qquad7,\qquad10. \]

Practice 2: Classify by Angles

Classify a triangle with angle measures

\[ 35^\circ,\qquad55^\circ,\qquad90^\circ. \]

Practice 3: Combined Classification

A triangle has side lengths \(5\), \(5\), and \(6\), and all three of its angles are less than \(90^\circ\). Give its combined classification.

Practice 4: Missing Interior Angle

Two angles of a triangle measure \(46^\circ\) and \(79^\circ\). Find the third angle.

Practice 5: Isosceles Triangle

An isosceles triangle has a vertex angle of \(36^\circ\). Find the two base angles.

Practice 6: Exterior Angle

Two remote interior angles measure \(42^\circ\) and \(63^\circ\). Find the exterior angle.

Practice 7: Triangle Inequality

Determine whether side lengths

\[ 6,\qquad8,\qquad13 \]

can form a nondegenerate triangle.

Practice 8: Degenerate Case

Determine whether side lengths

\[ 5,\qquad9,\qquad14 \]

form an ordinary nondegenerate triangle.

Practice 9: Range of a Third Side

Two sides of a triangle have lengths \(9\) and \(15\). Find the range of possible values for the third side \(x\).

Practice 10: Order the Sides

In \(\triangle ABC\),

\[ m\angle A=72^\circ,\qquad m\angle B=41^\circ,\qquad m\angle C=67^\circ. \]

Order the side lengths from shortest to longest.

Practice 11: Coordinate Classification

Let

\[ A(0,0),\qquad B(6,0),\qquad C(3,4). \]

Classify the triangle by its side lengths.

Practice 12: Identify the Error

A student says that side lengths \(4\), \(6\), and \(10\) form a triangle because

\[ 4+6=10. \]

Explain the error.

Practice Answers

Practice 1

Two sides are equal, so the triangle is

\[ \boxed{\text{isosceles}}. \]

Practice 2

One angle measures \(90^\circ\), so the triangle is

\[ \boxed{\text{right}}. \]

The angle sum checks:

\[ 35^\circ+55^\circ+90^\circ=180^\circ. \]

Practice 3

Two side lengths are equal, so the triangle is isosceles. All three angles are acute, so the combined classification is

\[ \boxed{\text{acute isosceles}}. \]

Practice 4

\[ x=180^\circ-46^\circ-79^\circ. \] \[ \boxed{x=55^\circ}. \]

Practice 5

The two base angles are equal. Their combined measure is

\[ 180^\circ-36^\circ=144^\circ. \]

Therefore, each base angle is

\[ \frac{144^\circ}{2}=\boxed{72^\circ}. \]

Practice 6

The exterior angle equals the sum of the two remote interior angles:

\[ 42^\circ+63^\circ=\boxed{105^\circ}. \]

Practice 7

Test the two shorter sides against the longest:

\[ 6+8=14>13. \]

Therefore,

\[ \boxed{\text{a nondegenerate triangle can be formed}}. \]

Practice 8

\[ 5+9=14. \]

Equality produces a degenerate collinear configuration, so

\[ \boxed{\text{no ordinary nondegenerate triangle is formed}}. \]

Practice 9

\[ |15-9|<x<15+9. \] \[ \boxed{6<x<24}. \]

Practice 10

Order the angles:

\[ 41^\circ<67^\circ<72^\circ. \]

Their opposite sides therefore satisfy

\[ \boxed{AC<AB<BC}. \]

Practice 11

Compare squared side lengths:

\[ AB^2=36, \] \[ AC^2=3^2+4^2=25, \] \[ BC^2=(-3)^2+4^2=25. \]

Since \(AC=BC\), the triangle is

\[ \boxed{\text{isosceles}}. \]

Practice 12

A nondegenerate triangle requires the sum of the two shorter sides to be strictly greater than the longest side.

\[ 4+6=10 \]

gives equality, so the three segments form a degenerate collinear configuration rather than an ordinary triangle.

What to Remember

The three most useful structural relationships are:

\[ \boxed{A+B+C=180^\circ}, \] \[ \boxed{\text{exterior angle}=\text{remote interior angle}_1+\text{remote interior angle}_2}, \] \[ \boxed{|a-b|<c<a+b}. \]

Where We Go Next

Classification tells us what kind of triangle we have, but geometry often asks a stronger question: when can we prove that two triangles have exactly the same size and shape?

The next lesson, Triangle Congruence, develops the side-and-angle conditions that are sufficient to establish triangle congruence, explains why some combinations work while others do not, and shows how corresponding parts can be used after congruence has been proved.