The Central Idea

An identity is an equality that is true for every value in the common domain of the two expressions.

For example,

\[ \boxed{\sin^2\theta+\cos^2\theta=1} \]

is true for every real \(\theta\).

Similarly,

\[ \boxed{\tan\theta=\frac{\sin\theta}{\cos\theta}} \]

is true whenever \(\cos\theta\neq0\).

Identities allow one trigonometric expression to be replaced by another equivalent expression.

Identity versus Equation

An identity is different from an equation that is true only for selected inputs.

For example,

\[ \sin x=0 \]

is not an identity because it is true only at certain values of \(x\).

But

\[ \sin^2x+\cos^2x=1 \]

is an identity because it is true throughout its domain.

Conditional Equality

Some equalities are true only under a condition.

For example,

\[ \sin x=\cos x \]

is true for certain angles but not for all angles.

Such an equation should be solved for its valid inputs rather than treated as an identity.

The Reciprocal Identities

The reciprocal pairs give

\[ \boxed{\csc\theta=\frac1{\sin\theta}}, \] \[ \boxed{\sec\theta=\frac1{\cos\theta}}, \]

and

\[ \boxed{\cot\theta=\frac1{\tan\theta}}. \]

These identities apply wherever the denominators are nonzero.

Reciprocal Identities in Reverse

The same relationships can be written in reverse:

\[ \boxed{\sin\theta=\frac1{\csc\theta}}, \] \[ \boxed{\cos\theta=\frac1{\sec\theta}}, \]

and

\[ \boxed{\tan\theta=\frac1{\cot\theta}}. \]

Which direction is more useful depends on the expression being simplified.

Reciprocal Product Identities

Multiplying reciprocal partners gives

\[ \boxed{\sin\theta\csc\theta=1}, \] \[ \boxed{\cos\theta\sec\theta=1}, \]

and

\[ \boxed{\tan\theta\cot\theta=1}, \]

wherever both functions are defined.

The Quotient Identities

Tangent and cotangent can be expressed entirely in terms of sine and cosine:

\[ \boxed{\tan\theta=\frac{\sin\theta}{\cos\theta}} \]

and

\[ \boxed{\cot\theta=\frac{\cos\theta}{\sin\theta}}. \]

These identities are especially useful when an expression contains several different trigonometric functions.

Deriving the Tangent Quotient Identity

In a right triangle,

\[ \sin\theta=\frac{O}{H} \]

and

\[ \cos\theta=\frac{A}{H}. \]

Divide:

\[ \frac{\sin\theta}{\cos\theta} = \frac{O/H}{A/H} = \frac{O}{A}. \]

Since

\[ \tan\theta=\frac{O}{A}, \]

we obtain

\[ \boxed{\tan\theta=\frac{\sin\theta}{\cos\theta}}. \]

Deriving the Cotangent Quotient Identity

Taking the reciprocal of the tangent identity gives

\[ \frac1{\tan\theta} = \frac{\cos\theta}{\sin\theta}. \]

Since

\[ \frac1{\tan\theta}=\cot\theta, \]

we obtain

\[ \boxed{\cot\theta=\frac{\cos\theta}{\sin\theta}}. \]

The Fundamental Pythagorean Identity

The most important trigonometric identity is

\[ \boxed{\sin^2\theta+\cos^2\theta=1}. \]

It comes directly from the unit-circle equation

\[ x^2+y^2=1 \]

after substituting

\[ x=\cos\theta \]

and

\[ y=\sin\theta. \]

Rearranging the Fundamental Identity

From

\[ \sin^2\theta+\cos^2\theta=1, \]

we can isolate either squared function:

\[ \boxed{\sin^2\theta=1-\cos^2\theta} \]

and

\[ \boxed{\cos^2\theta=1-\sin^2\theta}. \]

These forms are often more useful during simplification.

The Tangent–Secant Pythagorean Identity

Divide

\[ \sin^2\theta+\cos^2\theta=1 \]

by \(\cos^2\theta\), assuming \(\cos\theta\neq0\):

\[ \frac{\sin^2\theta}{\cos^2\theta} + \frac{\cos^2\theta}{\cos^2\theta} = \frac1{\cos^2\theta}. \]

Therefore,

\[ \boxed{\tan^2\theta+1=\sec^2\theta}. \]

Useful Rearrangements of the Tangent–Secant Identity

From

\[ \tan^2\theta+1=\sec^2\theta, \]

we obtain

\[ \boxed{\tan^2\theta=\sec^2\theta-1} \]

and

\[ \boxed{1=\sec^2\theta-\tan^2\theta}. \]

The Cotangent–Cosecant Pythagorean Identity

Divide

\[ \sin^2\theta+\cos^2\theta=1 \]

by \(\sin^2\theta\), assuming \(\sin\theta\neq0\):

\[ 1+\frac{\cos^2\theta}{\sin^2\theta} = \frac1{\sin^2\theta}. \]

Therefore,

\[ \boxed{1+\cot^2\theta=\csc^2\theta}. \]

Useful Rearrangements of the Cotangent–Cosecant Identity

From

\[ 1+\cot^2\theta=\csc^2\theta, \]

we obtain

\[ \boxed{\cot^2\theta=\csc^2\theta-1} \]

and

\[ \boxed{1=\csc^2\theta-\cot^2\theta}. \]

The Three Pythagorean Identities

The family can be summarized as

\[ \boxed{\sin^2\theta+\cos^2\theta=1}, \] \[ \boxed{1+\tan^2\theta=\sec^2\theta}, \]

and

\[ \boxed{1+\cot^2\theta=\csc^2\theta}. \]

The latter two are consequences of the first.

Even–Odd Identities

Unit-circle symmetry gives

\[ \boxed{\sin(-\theta)=-\sin\theta}, \] \[ \boxed{\cos(-\theta)=\cos\theta}, \]

and

\[ \boxed{\tan(-\theta)=-\tan\theta}. \]

Sine and tangent are odd functions, while cosine is even.

Even–Odd Identities for Reciprocal Functions

Reciprocal partners inherit the same parity:

\[ \boxed{\csc(-\theta)=-\csc\theta}, \] \[ \boxed{\sec(-\theta)=\sec\theta}, \]

and

\[ \boxed{\cot(-\theta)=-\cot\theta}. \]

Cofunction Identities

Complementary angles exchange opposite and adjacent side roles.

Therefore,

\[ \boxed{ \sin\left(\frac{\pi}{2}-\theta\right)=\cos\theta } \]

and

\[ \boxed{ \cos\left(\frac{\pi}{2}-\theta\right)=\sin\theta }. \]

Tangent and Cotangent Cofunction Identities

The complementary relationship also gives

\[ \boxed{ \tan\left(\frac{\pi}{2}-\theta\right)=\cot\theta } \]

and

\[ \boxed{ \cot\left(\frac{\pi}{2}-\theta\right)=\tan\theta }. \]

Secant and Cosecant Cofunction Identities

Taking reciprocals of the sine–cosine cofunction identities gives

\[ \boxed{ \sec\left(\frac{\pi}{2}-\theta\right)=\csc\theta } \]

and

\[ \boxed{ \csc\left(\frac{\pi}{2}-\theta\right)=\sec\theta }. \]

Periodicity Identities

Sine and cosine repeat every full revolution:

\[ \boxed{\sin(\theta+2\pi)=\sin\theta}, \] \[ \boxed{\cos(\theta+2\pi)=\cos\theta}. \]

Tangent and cotangent repeat every half revolution:

\[ \boxed{\tan(\theta+\pi)=\tan\theta}, \] \[ \boxed{\cot(\theta+\pi)=\cot\theta}. \]

Why Identity Verification Is Different from Solving

When verifying an identity, the goal is not to find values of the variable.

The goal is to transform one side into an equivalent form until it matches the other side.

For example, to verify

\[ \frac{\sin\theta}{\cos\theta}=\tan\theta, \]

we recognize the quotient identity rather than solving for \(\theta\).

Work on One Side at a Time

A reliable identity-verification habit is to begin with the more complicated side and rewrite it until it becomes the simpler side.

This keeps the argument logically clear.

Avoid changing both sides independently in a way that hides whether each transformation preserves equivalence.

Example: Verify a Reciprocal Identity

Verify

\[ \sin\theta\csc\theta=1. \]

Begin with the left side:

\[ \sin\theta\csc\theta. \]

Replace cosecant:

\[ \sin\theta\left(\frac1{\sin\theta}\right). \]

Therefore,

\[ \boxed{\sin\theta\csc\theta=1} \]

wherever \(\sin\theta\neq0\).

Example: Verify a Quotient Identity

Verify

\[ \frac{\tan\theta}{\sec\theta}=\sin\theta. \]

Begin with the left side:

\[ \frac{\tan\theta}{\sec\theta}. \]

Rewrite in sine and cosine:

\[ \frac{\sin\theta/\cos\theta}{1/\cos\theta}. \]

Dividing by a fraction means multiplying by its reciprocal:

\[ \frac{\sin\theta}{\cos\theta}\cdot\cos\theta. \]

Therefore,

\[ \boxed{\frac{\tan\theta}{\sec\theta}=\sin\theta}. \]

Example: Use a Pythagorean Identity

Simplify

\[ 1-\sin^2\theta. \]

From

\[ \sin^2\theta+\cos^2\theta=1, \]

we have

\[ \boxed{1-\sin^2\theta=\cos^2\theta}. \]

Example: Simplify with Tangent and Secant

Simplify

\[ \sec^2\theta-\tan^2\theta. \]

Rearranging

\[ 1+\tan^2\theta=\sec^2\theta \]

gives

\[ \boxed{\sec^2\theta-\tan^2\theta=1}. \]

Example: Simplify with Cotangent and Cosecant

Simplify

\[ \csc^2\theta-\cot^2\theta. \]

From

\[ 1+\cot^2\theta=\csc^2\theta, \]

we obtain

\[ \boxed{\csc^2\theta-\cot^2\theta=1}. \]

Convert to Sine and Cosine

When an expression contains several different trigonometric functions, converting everything to sine and cosine often reveals common factors or cancellations.

The main replacements are

\[ \tan\theta=\frac{\sin\theta}{\cos\theta}, \qquad \cot\theta=\frac{\cos\theta}{\sin\theta}, \] \[ \sec\theta=\frac1{\cos\theta}, \qquad \csc\theta=\frac1{\sin\theta}. \]

Example: Convert Everything to Sine and Cosine

Simplify

\[ \tan\theta\cos\theta. \]

Replace tangent:

\[ \frac{\sin\theta}{\cos\theta}\cos\theta. \]

Cancel the common factor where valid:

\[ \boxed{\tan\theta\cos\theta=\sin\theta}. \]

Example: Reciprocal Cancellation

Simplify

\[ \frac{\cos\theta}{\sec\theta}. \]

Since

\[ \sec\theta=\frac1{\cos\theta}, \]

we have

\[ \frac{\cos\theta}{1/\cos\theta} = \cos^2\theta. \]

Therefore,

\[ \boxed{\frac{\cos\theta}{\sec\theta}=\cos^2\theta}. \]

Factoring Trigonometric Expressions

Ordinary algebraic factoring applies to trigonometric expressions.

For example,

\[ \sin\theta+\sin\theta\tan^2\theta \]

has the common factor \(\sin\theta\):

\[ \sin\theta(1+\tan^2\theta). \]

Use the Pythagorean identity:

\[ \boxed{ \sin\theta+\sin\theta\tan^2\theta = \sin\theta\sec^2\theta }. \]

Combining Fractions

Trigonometric expressions follow ordinary fraction rules.

Consider

\[ \frac{\sin\theta}{\cos\theta} + \frac{\cos\theta}{\sin\theta}. \]

Use the common denominator

\[ \sin\theta\cos\theta. \]

Then

\[ \frac{\sin^2\theta+\cos^2\theta} {\sin\theta\cos\theta}. \]

Apply the Pythagorean identity:

\[ \boxed{ \frac{1}{\sin\theta\cos\theta} }. \]

Recognizing a Hidden Pythagorean Numerator

In the expression

\[ \frac{\sin^2\theta+\cos^2\theta}{\cos\theta}, \]

the numerator equals \(1\).

Therefore,

\[ \frac1{\cos\theta} = \boxed{\sec\theta}. \]

Multiplying by a Conjugate

Some trigonometric expressions contain sums or differences such as

\[ 1-\cos\theta. \]

Multiplying by the conjugate

\[ 1+\cos\theta \]

can create a Pythagorean expression:

\[ (1-\cos\theta)(1+\cos\theta) = 1-\cos^2\theta = \sin^2\theta. \]

This technique becomes useful in more advanced identity manipulations.

Example: Simplify with a Conjugate

Consider

\[ \frac{\sin^2\theta}{1-\cos\theta}. \]

Since

\[ \sin^2\theta=1-\cos^2\theta, \]

factor the numerator:

\[ \frac{(1-\cos\theta)(1+\cos\theta)} {1-\cos\theta}. \]

Where the canceled factor is nonzero,

\[ \boxed{ \frac{\sin^2\theta}{1-\cos\theta} = 1+\cos\theta }. \]

Domain Restrictions Matter

Algebraic simplification can hide values that were excluded from the original expression.

For example,

\[ \frac{\sin^2\theta}{1-\cos\theta} \]

is undefined when

\[ 1-\cos\theta=0. \]

Thus,

\[ \cos\theta=1 \]

is excluded from the original domain even though

\[ 1+\cos\theta \]

itself is defined there.

Equivalent Expressions Can Have Different Written Domains

Simplification preserves values on the original domain, but canceling a factor can make the simplified expression appear defined at additional inputs.

Therefore, when an identity involves quotients, the precise statement is understood over the common domain where both sides are defined.

Numerical Checks Are Useful but Not Proof

Substituting several values can help detect an incorrect identity.

For example, if someone claims

\[ \sin\theta+\cos\theta=1, \]

try

\[ \theta=\frac{\pi}{4}. \]

Then

\[ \frac{\sqrt2}{2}+\frac{\sqrt2}{2} = \sqrt2 \neq1. \]

One counterexample disproves the proposed identity.

Why Numerical Agreement Is Not Enough

If two expressions agree at one, ten, or even a thousand tested values, that does not by itself prove they agree for every input.

Identity verification requires a general algebraic or geometric argument.

Numerical testing is best used as a secondary check.

Example: Verify an Even–Odd Identity

Verify

\[ \sec(-\theta)=\sec\theta. \]

Begin with the left side:

\[ \sec(-\theta) = \frac1{\cos(-\theta)}. \]

Since cosine is even,

\[ \cos(-\theta)=\cos\theta. \]

Therefore,

\[ \boxed{\sec(-\theta)=\sec\theta}. \]

Example: Verify a Cofunction Identity

Verify

\[ \csc\left(\frac{\pi}{2}-\theta\right)=\sec\theta. \]

Begin with the left side:

\[ \csc\left(\frac{\pi}{2}-\theta\right) = \frac1{ \sin\left(\frac{\pi}{2}-\theta\right) }. \]

Use

\[ \sin\left(\frac{\pi}{2}-\theta\right)=\cos\theta. \]

Thus,

\[ \frac1{\cos\theta} = \boxed{\sec\theta}. \]

Example: A Multi-Step Verification

Verify

\[ \frac{1-\cos^2\theta}{\sin\theta} = \sin\theta. \]

Begin with the left side:

\[ \frac{1-\cos^2\theta}{\sin\theta}. \]

Use

\[ 1-\cos^2\theta=\sin^2\theta. \]

Then

\[ \frac{\sin^2\theta}{\sin\theta} = \boxed{\sin\theta}, \]

for inputs where the original denominator is nonzero.

Example: Simplify a Mixed Expression

Simplify

\[ \frac{\sec\theta-\cos\theta}{\tan\theta}. \]

Rewrite secant and tangent:

\[ \frac{ \frac1{\cos\theta}-\cos\theta }{ \frac{\sin\theta}{\cos\theta} }. \]

Combine the numerator:

\[ \frac{ \frac{1-\cos^2\theta}{\cos\theta} }{ \frac{\sin\theta}{\cos\theta} }. \]

Use

\[ 1-\cos^2\theta=\sin^2\theta. \]

Then

\[ \frac{ \sin^2\theta/\cos\theta }{ \sin\theta/\cos\theta } = \boxed{\sin\theta}. \]

Choose the Identity That Matches the Structure

Effective simplification is largely pattern recognition.

If you see

\[ 1-\sin^2\theta, \]

think

\[ \cos^2\theta. \]

If you see

\[ 1+\tan^2\theta, \]

think

\[ \sec^2\theta. \]

If you see several different functions, consider rewriting them in sine and cosine.

Do Not Expand without a Purpose

Algebraic expansion can sometimes make an identity harder to recognize.

Before expanding, ask whether factoring, a reciprocal identity, a quotient identity, or a Pythagorean replacement exposes structure more directly.

Factoring Can Reveal an Identity

Consider

\[ \cos^3\theta+\cos\theta\sin^2\theta. \]

Factor \(\cos\theta\):

\[ \cos\theta(\cos^2\theta+\sin^2\theta). \]

Use the Pythagorean identity:

\[ \boxed{ \cos^3\theta+\cos\theta\sin^2\theta = \cos\theta }. \]

A Common-Denominator Example

Simplify

\[ \frac1{1+\sin\theta} + \frac1{1-\sin\theta}. \]

Use the common denominator

\[ (1+\sin\theta)(1-\sin\theta) = 1-\sin^2\theta. \]

The numerator becomes

\[ (1-\sin\theta)+(1+\sin\theta)=2. \]

Therefore,

\[ \frac{2}{1-\sin^2\theta} = \frac{2}{\cos^2\theta} = \boxed{2\sec^2\theta}. \]

Identity Chains

One simplification may use several identities in sequence.

For example,

\[ \frac{\tan\theta}{\sec\theta} \]

first becomes

\[ \frac{\sin\theta/\cos\theta}{1/\cos\theta}, \]

then simplifies to

\[ \sin\theta. \]

Each step should preserve equivalence over the relevant domain.

Identity Verification Is Algebra with Trigonometric Vocabulary

The underlying algebra remains familiar:

The new skill is recognizing which trigonometric relationship makes the algebra simpler.

Common Error: Trying to Prove an Identity by Checking One Angle

Showing that both sides have the same value at

\[ \theta=30^\circ \]

verifies only that single input.

An identity requires a general argument valid throughout the common domain.

Common Error: Changing Both Sides Randomly

If both sides are rewritten independently, it can become unclear whether the transformations actually connect the original expressions.

A cleaner strategy is usually:

  1. start with the more complicated side;
  2. apply valid identities and algebra;
  3. stop when the other side appears.

Common Error: Canceling Terms across Addition

In

\[ \frac{\sin\theta+\cos\theta}{\sin\theta}, \]

you cannot cancel \(\sin\theta\) from only the first term in the numerator.

Instead, split the fraction:

\[ \frac{\sin\theta}{\sin\theta} + \frac{\cos\theta}{\sin\theta} = 1+\cot\theta. \]

Cancellation applies to factors, not isolated terms within a sum.

Common Error: Forgetting Function Squares

The identity

\[ 1+\tan^2\theta=\sec^2\theta \]

does not imply

\[ 1+\tan\theta=\sec\theta. \]

The squares are essential.

Common Error: Taking Square Roots without Sign Information

From

\[ \sin^2\theta=1-\cos^2\theta, \]

it does not follow that

\[ \sin\theta=\sqrt{1-\cos^2\theta} \]

for every angle.

In general,

\[ \boxed{ \sin\theta=\pm\sqrt{1-\cos^2\theta} } \]

with the sign determined by the angle or other given information.

Common Error: Ignoring Original Restrictions after Cancellation

If a denominator contains

\[ \sin\theta, \]

then inputs with

\[ \sin\theta=0 \]

are excluded from the original expression.

Canceling the factor later does not restore those values to the original domain.

Common Error: Confusing Identity Verification with Equation Solving

If the task is to verify

\[ 1-\sin^2\theta=\cos^2\theta, \]

do not try to isolate \(\theta\).

The equality is already intended as a general relationship.

The next lesson will focus specifically on equations whose valid angles must be found.

A Reliable Procedure for Verifying an Identity

  1. Identify the more complicated side.
  2. Look for reciprocal, quotient, or Pythagorean patterns.
  3. Convert to sine and cosine if several functions are mixed.
  4. Apply ordinary algebra carefully.
  5. Factor or combine fractions when useful.
  6. Use conjugates when a difference of squares may appear.
  7. Track all denominator restrictions.
  8. Continue until the expression matches the other side.
  9. Use a numerical check only as secondary verification.

A Reliable Procedure for Simplifying a Trigonometric Expression

  1. Inventory the functions present.
  2. Choose a target form if one is suggested by the problem.
  3. Replace reciprocal or quotient functions when useful.
  4. Search for one of the three Pythagorean identities.
  5. Factor common expressions.
  6. Combine fractions using a common denominator.
  7. Cancel only common factors, never separate terms.
  8. State or preserve relevant domain restrictions.

Practice 1: Reciprocal Identity

Simplify:

\[ \cos\theta\sec\theta. \]

Practice 2: Quotient Identity

Simplify:

\[ \frac{\sin\theta}{\cos\theta}. \]

Practice 3: Pythagorean Identity

Simplify:

\[ 1-\cos^2\theta. \]

Practice 4: Tangent–Secant Identity

Simplify:

\[ \sec^2\theta-1. \]

Practice 5: Cotangent–Cosecant Identity

Simplify:

\[ \csc^2\theta-1. \]

Practice 6: Mixed Functions

Simplify:

\[ \frac{\tan\theta}{\sec\theta}. \]

Practice 7: Factor First

Simplify:

\[ \sin^3\theta+\sin\theta\cos^2\theta. \]

Practice 8: Common Denominator

Simplify:

\[ \frac{\sin\theta}{\cos\theta} + \frac{\cos\theta}{\sin\theta}. \]

Practice 9: Even–Odd Identity

Simplify:

\[ \cos(-\theta). \]

Practice 10: Cofunction Identity

Simplify:

\[ \sin\left(\frac{\pi}{2}-\theta\right). \]

Practice 11: Verify an Identity

Verify:

\[ \frac{1-\sin^2\theta}{\cos\theta} = \cos\theta. \]

Practice 12: Identify the Error

A student claims that

\[ 1+\tan\theta=\sec\theta \]

follows from the Pythagorean identities.

Explain the error.

Practice Answers

Practice 1

\[ \cos\theta\sec\theta = \cos\theta\left(\frac1{\cos\theta}\right) = \boxed{1}, \]

where the original expression is defined.

Practice 2

\[ \boxed{ \frac{\sin\theta}{\cos\theta} = \tan\theta }. \]

Practice 3

\[ \boxed{ 1-\cos^2\theta = \sin^2\theta }. \]

Practice 4

\[ \boxed{ \sec^2\theta-1 = \tan^2\theta }. \]

Practice 5

\[ \boxed{ \csc^2\theta-1 = \cot^2\theta }. \]

Practice 6

\[ \frac{\tan\theta}{\sec\theta} = \frac{\sin\theta/\cos\theta}{1/\cos\theta} = \boxed{\sin\theta}. \]

Practice 7

Factor \(\sin\theta\):

\[ \sin\theta(\sin^2\theta+\cos^2\theta). \]

Therefore,

\[ \boxed{ \sin^3\theta+\sin\theta\cos^2\theta = \sin\theta }. \]

Practice 8

\[ \frac{\sin^2\theta+\cos^2\theta} {\sin\theta\cos\theta} = \boxed{ \frac1{\sin\theta\cos\theta} }. \]

An equivalent form is

\[ \boxed{\sec\theta\csc\theta}. \]

Practice 9

Cosine is even:

\[ \boxed{\cos(-\theta)=\cos\theta}. \]

Practice 10

\[ \boxed{ \sin\left(\frac{\pi}{2}-\theta\right) = \cos\theta }. \]

Practice 11

Begin with the left side:

\[ \frac{1-\sin^2\theta}{\cos\theta}. \]

Since

\[ 1-\sin^2\theta=\cos^2\theta, \]

we obtain

\[ \frac{\cos^2\theta}{\cos\theta} = \boxed{\cos\theta}, \]

for inputs where the original denominator is nonzero.

Practice 12

The correct Pythagorean identity is

\[ \boxed{1+\tan^2\theta=\sec^2\theta}. \]

The squares cannot be removed term by term.

In general,

\[ 1+\tan\theta\neq\sec\theta. \]

What to Remember

The major identity families are:

Reciprocal:

\[ \boxed{ \csc\theta=\frac1{\sin\theta}, \qquad \sec\theta=\frac1{\cos\theta}, \qquad \cot\theta=\frac1{\tan\theta} }. \]

Quotient:

\[ \boxed{ \tan\theta=\frac{\sin\theta}{\cos\theta}, \qquad \cot\theta=\frac{\cos\theta}{\sin\theta} }. \]

Pythagorean:

\[ \boxed{\sin^2\theta+\cos^2\theta=1}, \] \[ \boxed{1+\tan^2\theta=\sec^2\theta}, \] \[ \boxed{1+\cot^2\theta=\csc^2\theta}. \]

Where We Go Next

Trigonometric identities provide tools for rewriting expressions without changing their values.

The next lesson, Trigonometric Equations, uses these identities together with unit-circle values, inverse functions, factoring, and periodicity to find the angles that satisfy particular trigonometric conditions.