MGU Mathematics Series — Trigonometry and Precalculus
Part II: Trigonometric Foundations
Amplitude · Period · Phase Shift · Asymptotes · Periodic Models
Chapter 5 of 14
MGU Mathematics Series  ·  Trigonometry and Precalculus  ·  Library Textbook Edition

Chapter 5:
Graphs of Trigonometric
Functions

Periodic behavior made visible — sine, cosine, tangent, and reciprocal graphs; amplitude, period, phase shift, midline, asymptotes, transformations, and models of waves, tides, seasons, and oscillation

■ Part II: Trigonometric Foundations ■

■ 14 Sections  •  Chapter 5 of 14 ■

Follows Chapter 4: The Unit Circle and Trigonometric Functions  ·  Prepares students for Chapter 6: Trigonometric Identities and Equations

Purpose and Overview

Chapter 4 established trigonometric functions as relationships between angles and coordinates on the unit circle. Sine and cosine emerged as the vertical and horizontal coordinates of a point tracing the unit circle. Tangent arose as their ratio. The six functions were defined, evaluated, and connected to special angles in both degrees and radians.

This chapter makes those functions visible. When you plot the output of sine, cosine, or tangent against the input angle — tracing the full rotation of the unit circle from left to right — a wave appears. That wave is not random. It has a precise shape, a predictable repeating cycle, and measurable features: the highest and lowest values, the distance between repetitions, the location of the center, and where the graph has been shifted horizontally. Every one of those features corresponds to a number you can read from the formula.

Understanding trigonometric graphs is not only a mathematical skill. It is the foundation for describing any quantity that repeats or oscillates over time. Sound is a wave. Light is a wave. The tides rise and fall in a periodic cycle. Electrical current alternates. Seasons repeat. A pendulum swings back and forth. A spinning wheel generates circular motion that projects onto a line as a sinusoidal wave. In every one of these situations, the mathematics of this chapter provides the model.

By the end of this chapter, you will be able to identify the amplitude, period, phase shift, and midline of a trigonometric function directly from its formula, graph it accurately, write a formula from a graph, and build models for periodic phenomena in science, engineering, and everyday life.

Opening Question

A buoy bobs on the ocean. At its highest point, it sits 2 meters above the average water line. At its lowest, it sits 2 meters below. It completes one full cycle every 8 seconds. If it starts at the average water line and moves upward, how high is the buoy after 2 seconds? After 6 seconds? After 20 seconds? By the end of this chapter, you will be able to write a single equation that answers these questions for any time value — and you will understand why that equation takes the shape it does.

14Sections
12Objectives
18Key Terms
12+Worked Examples

Learning Objectives

  1. 1Define a periodic function and identify its period, amplitude, midline, and range from a graph or formula.
  2. 2Graph y = sin(x) and y = cos(x) and identify their key features: zeros, maxima, minima, domain, and range.
  3. 3Interpret amplitude as vertical scale and connect it to the coefficient in front of sin or cos.
  4. 4Determine the period of a trigonometric function from its formula and connect it to the coefficient inside the argument.
  5. 5Identify the midline and vertical shift of a transformed trigonometric function.
  6. 6Identify and graph phase shift (horizontal shift) in sine and cosine functions.
  7. 7Graph fully transformed sine and cosine functions of the form y = A sin(Bx − C) + D.
  8. 8Write a trigonometric equation to match a described or displayed graph.
  9. 9Graph the tangent function, identify its period, asymptotes, and behavior near vertical asymptotes.
  10. 10Recognize and describe the graphs of secant, cosecant, and cotangent functions and their connections to sine and cosine.
  11. 11Build and interpret sinusoidal models for periodic real-world data.
  12. 12Identify and correct common mistakes made when graphing trigonometric functions.

Sections at a Glance

Sections 5.1 – 5.3
Periodic Functions and the Basic Graphs
Periodic Functions · The Sine Graph · The Cosine Graph

Periodic Functions

A function is called periodic if its values repeat in a regular cycle as the input increases. Instead of always producing new outputs, the function circles back and begins the same pattern again. The length of one complete cycle — the smallest positive value P for which f(x + P) = f(x) for all x in the domain — is called the period of the function.

Think of a wheel spinning at a constant rate. The height of a point on the rim goes up, reaches the top, comes back down, reaches the bottom, and then returns to where it started. That is one period. After one full rotation, the entire pattern begins again. This is exactly what happens on the unit circle: as the angle increases from 0 to 2π, the point traces one complete circle. The y-coordinate (sine) and the x-coordinate (cosine) each complete one cycle. As the angle continues past 2π, the pattern repeats.

Periodic behavior is not only mathematical. Daylight hours repeat each year. Ocean tides rise and fall every 12.4 hours. Sound vibrates air molecules back and forth hundreds or thousands of times per second. Alternating electrical current reverses direction 60 times per second in most of North America. The seasons follow a year-long cycle. Heart rate produces repeating beats. In all these situations, a periodic function provides the mathematical model.

Formal Definition — Periodic Function

A function f is periodic with period P if P is the smallest positive number such that: f(x + P) = f(x) for every x in the domain of f.

The function returns to the same output value after every interval of length P.

Connection to the Unit Circle

On the unit circle, a point at angle θ has coordinates (cos θ, sin θ). As θ increases from 0 to 2π, the point traces one full revolution and returns to its starting position. The coordinates at angle θ + 2π are identical to those at angle θ. This is why both sin(θ + 2π) = sin θ and cos(θ + 2π) = cos θ — the period of sine and cosine is exactly 2π radians.

Periodic PhenomenonPeriod (approximate)Trigonometric Model
Rotation of a wheel (at 1 rev/sec)1 secondSine or cosine
Ocean tide (semi-diurnal)12.4 hoursSine or cosine
A sound wave at concert A (440 Hz)1/440 secondSine
Annual temperature cycle12 monthsSine or cosine
AC electrical current (North America)1/60 secondSine
Why Radians and Periodicity Connect Naturally

The period of sin(x) and cos(x) is 2π. In calculus, the derivative of sin(x) is cos(x) only when x is measured in radians. When x is in degrees, a conversion factor appears. Radians make the mathematics of periodic functions clean, especially when limits and derivatives are involved. This is one major reason why radians are preferred in precalculus and beyond.

Practice 5.1Concept Check
  1. A function f satisfies f(x + 4) = f(x) for all x. What is the period of f? Describe what this means in words.
  2. A wheel completes one full rotation every 3 seconds. If the height of a point on the rim follows a periodic function, what is the period of that function?
  3. Explain in your own words why the output of sin(x) must repeat every 2π radians by connecting the argument to the unit circle.
  4. A heartbeat monitor shows a repeating waveform that completes 72 full cycles per minute. What is the period of this waveform in seconds?
  5. Can a function have two different periods? Explain your reasoning.

The Sine Graph

To graph y = sin(x), recall that sin(x) is the y-coordinate of the point on the unit circle at angle x. As x increases from 0 to 2π, that y-coordinate moves from 0 up to 1, back down through 0 to −1, and then back up to 0. When you plot these output values against the input angle, tracing the vertical coordinate as the angle sweeps around the circle, you obtain the familiar S-shaped wave.

The key values to know precisely come directly from the special angles on the unit circle. At x = 0, sin(0) = 0. At x = π/2, sin(π/2) = 1. At x = π, sin(π) = 0. At x = 3π/2, sin(3π/2) = −1. At x = 2π, sin(2π) = 0. These five anchor points — zero, maximum, zero, minimum, zero — are all you need to sketch one complete cycle. After x = 2π, the pattern repeats.

x (radians)sin(x)Description
00Starting zero (beginning of cycle)
π/61/2Rising
π/4√2/2 ≈ 0.707Rising
π/3√3/2 ≈ 0.866Rising
π/21Maximum
π0Middle zero (falling through)
3π/2−1Minimum
2π0Ending zero (one full cycle complete)
Graph Instruction — y = sin(x)

Draw a horizontal axis labeled x, with tick marks at multiples of π/2: 0, π/2, π, 3π/2, 2π, and extending to −2π on the left. Draw a vertical axis. Plot these five anchor points on one cycle from 0 to 2π: (0, 0), (π/2, 1), (π, 0), (3π/2, −1), (2π, 0). Connect with a smooth, continuous S-shaped curve — rising from (0,0) to the maximum at (π/2, 1), descending through (π, 0) to the minimum at (3π/2, −1), and rising back to (2π, 0). Repeat this pattern to the left for negative values of x. Label the maximum 1 and the minimum −1 on the vertical axis.

  • Domain: all real numbers
  • Range: [−1, 1]
  • Period: 2π
  • Zeros: x = nπ for every integer n
  • Maximum value: 1, occurring at x = π/2 + 2πn
  • Minimum value: −1, occurring at x = 3π/2 + 2πn = −π/2 + 2πn
  • Symmetry: the sine function is an odd function; sin(−x) = −sin(x)
Key Properties of y = sin(x)

Domain: (−∞, ∞) — defined for all real numbers

Range: [−1, 1]

Period: 2π

Amplitude: 1 (the maximum distance from the midline)

Midline: y = 0 (the horizontal axis)

Zeros: x = nπ for every integer n (the function crosses the x-axis)

Symmetry: odd function — the graph has rotational symmetry about the origin

The Five-Point Method for Graphing One Cycle

Every sine or cosine cycle is anchored by five key points: start, quarter cycle, half cycle, three-quarter cycle, and end. For y = sin(x) on [0, 2π], these are (0,0), (π/2, 1), (π, 0), (3π/2, −1), (2π, 0). Learning to find the equivalents of these five points on any transformed sine or cosine function is the core graphing skill of this chapter.

Practice 5.2The Sine Graph
  1. List the five anchor points of one cycle of y = sin(x) starting at x = 0. Then list the five anchor points for the cycle starting at x = 2π and the cycle starting at x = −2π.
  2. Without a calculator, evaluate sin(0), sin(π/2), sin(π), sin(3π/2), sin(2π), sin(5π/2), sin(−π/2), and sin(−π).
  3. Describe the behavior of y = sin(x) on the interval [0, π/2]. Is it increasing or decreasing? What are the values at the endpoints?
  4. At what values of x does sin(x) = 0 on the interval [−2π, 4π]? List all of them.
  5. Graph two full cycles of y = sin(x) by hand, using the five-point method for each cycle.

The Cosine Graph

The graph of y = cos(x) is produced the same way as the sine graph — by tracking a coordinate on the unit circle — but this time it is the x-coordinate rather than the y-coordinate. As the angle increases from 0, the x-coordinate on the unit circle begins at 1 (the rightmost point), moves through 0 at the top, reaches −1 at the leftmost point, moves through 0 at the bottom, and returns to 1 at the end of one revolution. The cosine graph therefore begins at its maximum value and descends, rather than beginning at zero and rising as sine does.

The cosine function shares all of the same basic properties as sine — the same domain, the same range [−1, 1], the same period 2π, the same amplitude 1, and the same midline y = 0. The only difference is the phase relationship: the cosine graph is a horizontal shift of the sine graph. Specifically, cos(x) = sin(x + π/2). This means every feature of the cosine graph appears exactly π/2 units to the left of the corresponding feature on the sine graph.

x (radians)cos(x)Description
01Maximum (beginning of cycle)
π/20Descending zero
π−1Minimum
3π/20Ascending zero
2π1Maximum (one full cycle complete)
Graph Instruction — y = cos(x)

Draw horizontal and vertical axes as for the sine graph. Plot the five anchor points for one cycle on [0, 2π]: (0, 1), (π/2, 0), (π, −1), (3π/2, 0), (2π, 1). Connect with a smooth wave — starting at the maximum (0, 1), descending smoothly through (π/2, 0), reaching the minimum (π, −1), rising through (3π/2, 0), and returning to maximum (2π, 1). The shape is like a gentle arch that dips down to a trough and back up again. Extend the pattern in both directions. Label maximum 1 and minimum −1.

  • Domain: all real numbers
  • Range: [−1, 1]
  • Period: 2π
  • Zeros: x = π/2 + nπ for every integer n (halfway between multiples of π)
  • Maximum value: 1, occurring at x = 2πn
  • Minimum value: −1, occurring at x = π + 2πn
  • Symmetry: the cosine function is an even function; cos(−x) = cos(x)
Comparing Sine and Cosine

Both functions: domain (−∞, ∞), range [−1, 1], period 2π, amplitude 1, midline y = 0

Sine begins: at zero (0, 0), rises to maximum, falls through zero to minimum, returns

Cosine begins: at maximum (0, 1), falls to zero, reaches minimum, rises to zero, returns

Relationship: cos(x) = sin(x + π/2) and sin(x) = cos(x − π/2)

Sine symmetry: odd — sin(−x) = −sin(x) — rotational symmetry about origin

Cosine symmetry: even — cos(−x) = cos(x) — reflective symmetry about the y-axis

Practice 5.3The Cosine Graph
  1. List the five anchor points of one cycle of y = cos(x) starting at x = 0.
  2. Without a calculator, evaluate cos(0), cos(π/2), cos(π), cos(3π/2), cos(2π), cos(−π), and cos(5π).
  3. At what values of x does cos(x) = 0 on the interval [−2π, 4π]? List all of them.
  4. Sketch y = sin(x) and y = cos(x) on the same axes from x = −π to x = 3π. Label any intersection points within that window.
  5. Explain, using the unit circle, why cos(−x) = cos(x) but sin(−x) = −sin(x). Which function is even and which is odd?
  6. At what values of x on [0, 2π] do sin(x) and cos(x) have the same value? Find the exact x-values and the shared output.
Sections 5.4 – 5.7
The Four Parameters: Amplitude, Period, Midline, and Phase Shift
Amplitude · Period · Midline and Vertical Shift · Phase Shift

Amplitude

When the basic sine or cosine function is multiplied by a constant A, the graph stretches or compresses vertically. This vertical scale factor is captured by a quantity called the amplitude. The amplitude of a periodic function is the maximum distance the graph travels from the midline — in other words, half the total distance between the maximum and minimum values.

For y = A sin(x), the maximum output is |A| and the minimum is −|A|. The graph oscillates between these two extreme values, and the amplitude equals |A|. Note that amplitude is always a positive quantity — it measures distance, not direction. If A is negative, the graph is reflected across the midline (it begins by going down instead of up), but the amplitude is still |A|.

Amplitude controls the height of the wave. A sound wave with larger amplitude is louder. A water wave with larger amplitude is taller. An oscillating spring with larger amplitude moves farther from its rest position. In every physical context, amplitude measures the intensity or magnitude of the oscillation.

Amplitude of y = A sin(x) or y = A cos(x)

Amplitude = |A|

Maximum value: |A|

Minimum value: −|A|

If A > 0: same orientation as y = sin(x) or y = cos(x)

If A < 0: reflected across the midline — graph is vertically flipped

Example 5.4.1
Reading amplitude and sketching a vertical stretch
  • ProblemState the amplitude and range of y = 3 sin(x). Describe how its graph differs from y = sin(x).
  • ThinkThe coefficient in front of sin(x) is A = 3. Amplitude equals |A|.
  • Solve Amplitude = |3| = 3 Maximum value: 3 Minimum value: −3 Range: [−3, 3]
  • CheckWhen sin(x) = 1 at x = π/2, the function gives 3(1) = 3. When sin(x) = −1 at x = 3π/2, it gives 3(−1) = −3. Period and shape are unchanged. ✓
Amplitude = 3, Range = [−3, 3]. The graph has the same shape and period as y = sin(x) but oscillates three times as far from the midline.
Example 5.4.2
Negative amplitude — reflection
  • ProblemState the amplitude of y = −2 cos(x) and describe what the negative sign does.
  • ThinkA = −2, so |A| = 2. The negative sign reflects the graph across the midline.
  • Solve Amplitude = |−2| = 2 y = cos(x) starts at maximum (0, 1) y = −2 cos(x) starts at minimum (0, −2) [reflected and scaled]
  • CheckAt x = π, cos(π) = −1, so −2(−1) = 2 — the maximum. The original minimum becomes the maximum after the reflection. ✓
Amplitude = 2. The negative sign reflects the cosine graph across the midline, so it starts at its minimum value (0, −2) instead of its maximum.
Student Warning — Amplitude Is Always Positive

Amplitude is defined as a distance, so it is always non-negative. For y = −3 sin(x), the amplitude is 3, not −3. The negative sign tells you about the reflection, not the amplitude. Never report a negative amplitude.

Practice 5.4Amplitude
  1. y = 5 sin(x)
  2. y = (1/2) cos(x)
  3. y = −4 sin(x)
  4. y = −cos(x)
  5. y = 0.6 sin(x)
  6. y = (2/3) cos(x)

For each function: state the amplitude, maximum value, minimum value, and range. For functions with a negative coefficient, describe the reflection.

Period

The period of a trigonometric function is the horizontal length of one complete cycle. For y = sin(x) and y = cos(x), the period is 2π. But when the input is multiplied by a constant B — writing y = sin(Bx) — the period changes. A larger value of B causes the function to complete its cycle faster (smaller period). A smaller value of B causes the cycle to stretch out (larger period).

To see why, consider that y = sin(x) completes one cycle when its argument x goes from 0 to 2π. For y = sin(Bx) to complete one cycle, the argument Bx must go from 0 to 2π, which means x goes from 0 to 2π/B. The period is therefore 2π divided by B.

Period Formula for y = sin(Bx) or y = cos(Bx)

Period P = 2π / |B|

If B > 1: the period is less than 2π — the graph is horizontally compressed (faster cycle)

If 0 < B < 1: the period is greater than 2π — the graph is horizontally stretched (slower cycle)

If B < 0: use |B| for the period; the negative introduces a reflection in the horizontal direction

Example 5.5.1
Finding the period and sketching
  • ProblemFind the period of y = cos(4x). Identify the five anchor points for one cycle starting at x = 0.
  • ThinkB = 4. Use the period formula.
  • Solve Period P = 2π / 4 = π/2 One cycle runs from x = 0 to x = π/2 Quarter points: 0, π/8, π/4, 3π/8, π/2 Anchor points: (0, 1), (π/8, 0), (π/4, −1), (3π/8, 0), (π/2, 1)
  • CheckAt x = π/4, 4(π/4) = π, and cos(π) = −1. ✓ The cycle is compressed to width π/2 instead of 2π.
Period = π/2. One cycle fits entirely between x = 0 and x = π/2 — four full cycles occur in the same width that y = cos(x) uses for one.
Example 5.5.2
Finding B from a given period
  • ProblemA sinusoidal function y = sin(Bx) has period 8. Find the value of B.
  • ThinkUse the period formula and solve for B.
  • Solve P = 2π / B 8 = 2π / B B = 2π / 8 = π/4
  • CheckIf B = π/4, then P = 2π ÷ (π/4) = 2π × (4/π) = 8. ✓
B = π/4. The function is y = sin((π/4)x).
Frequency vs. Period

In physics and engineering, frequency is the number of cycles completed per unit of time — it is the reciprocal of the period: f = 1/P. For a sound wave with a period of 1/440 seconds, the frequency is 440 Hz (hertz, or cycles per second). When working with trigonometric models, period and frequency describe the same property from opposite perspectives.

Practice 5.5Period
  1. y = sin(2x)
  2. y = cos(3x)
  3. y = sin(x/2)
  4. y = cos(πx)
  5. y = sin(x/3)
  6. y = cos(6x)

For each function: state the period and list the x-values of the five anchor points for one cycle starting at x = 0.

  1. A sinusoidal function has period 3. Write a possible equation of the form y = sin(Bx).
  2. A sinusoidal function has period 2π/5. What is the value of B in y = cos(Bx)?
  3. Compare the graphs of y = sin(x), y = sin(2x), and y = sin(x/2) by describing how their periods and horizontal scales differ.

Midline and Vertical Shift

The midline of a trigonometric graph is the horizontal line that runs exactly halfway between the maximum and minimum values. For y = sin(x) and y = cos(x), the midline is the x-axis itself — the line y = 0. The function oscillates equally above and below this line.

When a constant D is added to the function — writing y = sin(x) + D or y = cos(x) + D — the entire graph shifts vertically. Every output value increases by D. The maximum becomes 1 + D, the minimum becomes −1 + D, and the midline moves from y = 0 to y = D. The shape, period, and amplitude are completely unchanged. Only the vertical position of the graph has shifted.

In real-world models, the vertical shift D often carries important meaning. If a sinusoidal function models the height of ocean water, D represents the average depth — the water level around which the tide oscillates. If it models temperature, D represents the average temperature for the cycle.

Midline and Vertical Shift in y = A sin(Bx) + D

Midline: y = D

Maximum value: D + |A|

Minimum value: D − |A|

Range: [D − |A|, D + |A|]

The midline shifts up when D > 0 and down when D < 0. The amplitude and period are not affected by D.

Example 5.6.1
Identifying midline, maximum, and minimum
  • ProblemFor y = 3 sin(x) + 2, state the midline, maximum value, minimum value, and range.
  • ThinkA = 3, D = 2. The amplitude is 3. The vertical shift is +2.
  • Solve Midline: y = 2 Maximum: 2 + 3 = 5 Minimum: 2 − 3 = −1 Range: [−1, 5]
  • CheckWhen sin(x) = 1: y = 3(1) + 2 = 5. When sin(x) = −1: y = 3(−1) + 2 = −1. ✓
Midline y = 2; Maximum value 5; Minimum value −1; Range [−1, 5].
Example 5.6.2
Writing a function from midline and amplitude information
  • ProblemA sinusoidal function has maximum value 8, minimum value 2, and period 2π. Write an equation of the form y = A sin(x) + D.
  • ThinkFind D from the midline, then A from the amplitude.
  • Solve Midline D = (8 + 2) / 2 = 10/2 = 5 Amplitude A = (8 − 2) / 2 = 6/2 = 3 Period = 2π means B = 1 Equation: y = 3 sin(x) + 5
  • CheckWhen sin(x) = 1: y = 3 + 5 = 8. ✓ When sin(x) = −1: y = −3 + 5 = 2. ✓
y = 3 sin(x) + 5
Practice 5.6Midline and Vertical Shift
  1. y = sin(x) + 4
  2. y = cos(x) − 3
  3. y = 2 sin(x) + 1
  4. y = −3 cos(x) − 2
  5. y = (1/2) sin(x) + 6
  6. y = 4 cos(x) − 1

For each function: state the midline, amplitude, maximum value, minimum value, and range.

  1. A sinusoidal function has maximum value 10 and minimum value 4. Find the midline and amplitude.
  2. A sinusoidal function has amplitude 6 and midline y = −2. Find the maximum and minimum values.
  3. Write an equation of the form y = A cos(x) + D with maximum 7 and minimum −1.

Phase Shift

A phase shift is a horizontal translation of a trigonometric graph — the entire wave moves left or right along the x-axis without changing its shape, height, or repeating cycle length. When the argument of sine or cosine includes a subtraction inside the parentheses — such as sin(Bx − C) — the graph is shifted horizontally.

The phase shift is the amount by which the graph has moved. Its value is C/B. To understand why, consider that sin(x) begins its standard cycle at x = 0, where the argument equals 0. For y = sin(Bx − C), the cycle begins when Bx − C = 0, which gives x = C/B. This is the new starting point of the cycle. When C/B is positive, the shift is to the right. When C/B is negative, the shift is to the left.

This is one of the most common sources of sign errors in trigonometry. The standard form is sin(Bx − C), not sin(Bx + C). When the function is written as sin(Bx + C), the phase shift is −C/B, which is a shift to the left. It is easy to confuse the direction. The safest approach is to always factor the B from inside the parentheses before reading the shift.

Phase Shift in y = A sin(Bx − C) + D

Phase shift = C/B

If C/B > 0: the graph shifts to the right by C/B units

If C/B < 0: the graph shifts to the left by |C/B| units

Equivalently, the cycle begins at x = C/B instead of x = 0.

Caution: if the function is written as y = A sin(Bx + C) + D, factor out B first: y = A sin[B(x + C/B)] + D, revealing a shift of −C/B (to the left).

Example 5.7.1
Identifying the phase shift
  • ProblemFind the phase shift of y = sin(2x − π). Describe what it means graphically.
  • ThinkIdentify B and C from the form Bx − C. Here B = 2, C = π.
  • Solve Phase shift = C/B = π/2 The graph shifts π/2 units to the right. The cycle begins at x = π/2 instead of x = 0.
  • CheckWhen x = π/2: argument = 2(π/2) − π = π − π = 0, and sin(0) = 0. The cycle starts at x = π/2 with output 0, as expected. ✓
Phase shift = π/2 to the right. The starting zero of the cycle moves from x = 0 to x = π/2.
Example 5.7.2
Phase shift written with addition — factoring method
  • ProblemFind the phase shift of y = cos(3x + π). State the direction carefully.
  • ThinkThe function is not in standard form. Factor 3 from the argument first.
  • Solve y = cos(3x + π) = cos[3(x + π/3)] Standard form: cos(Bx − C) where C = −π/3 Phase shift = C/B = (−π/3)/1... but we already see the shift directly: the graph shifts π/3 units to the LEFT.
  • CheckAt x = −π/3: argument = 3(−π/3) + π = −π + π = 0, and cos(0) = 1 (maximum). The maximum has moved from x = 0 to x = −π/3. ✓
Phase shift = π/3 to the left. The maximum of cosine moves from x = 0 to x = −π/3.
Student Warning — Phase Shift Direction

In y = sin(Bx − C): subtract means shift right. In y = sin(Bx + C): add means shift left. This is counterintuitive because adding shifts left. Always factor B from the argument before deciding direction: y = sin(Bx + C) = sin[B(x + C/B)] shifts C/B units to the left because the "+C/B" inside is moving the starting point to the left.

Practice 5.7Phase Shift
  1. y = sin(x − π/2)
  2. y = cos(x + π)
  3. y = sin(2x − π/3)
  4. y = cos(3x + π/2)
  5. y = sin(x/2 − π/4)
  6. y = cos(4x − π)

For each function, state the phase shift and its direction. Then state the x-value where the first cycle begins.

Sections 5.8 – 5.10
Full Transformations of Sine and Cosine; The Tangent Graph
Transformations · The Tangent Graph · Asymptotes of Tangent

Transformations of Sine and Cosine

The four parameters — A (amplitude), B (period control), C (phase shift), and D (vertical shift) — combine in the general form y = A sin(Bx − C) + D. Reading this function correctly requires you to identify each parameter and understand its role before drawing a single point. This section develops a systematic procedure for graphing any transformed sine or cosine function and for writing an equation to match any given graph.

The procedure is: read A, B, C, D from the formula; compute the amplitude |A|, the period 2π/|B|, the phase shift C/B, and the midline y = D; locate the starting point of one cycle at x = C/B; divide the period into four equal parts to find the five anchor points; apply the amplitude and midline to find the y-values at those points; and sketch the smooth wave through all five points. Then extend the pattern as needed.

Graphing y = A sin(Bx − C) + D — Systematic Procedure

Step 1: Identify A, B, C, D directly from the formula (or factor B first if needed)

Step 2: Compute amplitude = |A|, period P = 2π/|B|, phase shift = C/B, midline y = D

Step 3: Locate the starting x of one cycle: x₀ = C/B. End of cycle: x₀ + P

Step 4: Divide the cycle into four equal intervals. The five x-values are: x₀, x₀ + P/4, x₀ + P/2, x₀ + 3P/4, x₀ + P

Step 5: Assign y-values at those five points. For y = A sin(Bx − C) + D: D, D+|A|, D, D−|A|, D (if A > 0); reversed if A < 0

Step 6: Draw the midline y = D as a dashed reference line. Plot all five points and connect with a smooth wave.

Example 5.8.1
Graphing a fully transformed sine function
  • ProblemGraph y = 2 sin(3x − π) + 1 for one complete cycle. State all key features.
  • ThinkRead A = 2, B = 3, C = π, D = 1. Compute each parameter systematically.
  • Solve Amplitude = |2| = 2 Period P = 2π / 3 Phase shift = π / 3 (to the right) Midline y = 1 Maximum value = 1 + 2 = 3 Minimum value = 1 − 2 = −1 Range = [−1, 3] Cycle starts at x₀ = π/3 Cycle ends at x₀ + P = π/3 + 2π/3 = π Quarter-cycle width = (2π/3) / 4 = π/6 Five anchor x-values: π/3, π/2, 2π/3, 5π/6, π Corresponding y-values: 1, 3, 1, −1, 1 (midline, max, midline, min, midline)
  • CheckAt x = π/2: argument = 3(π/2) − π = π/2, sin(π/2) = 1, y = 2(1) + 1 = 3. ✓ Maximum confirmed.
Amplitude 2, period 2π/3, phase shift π/3 right, midline y = 1. Five anchor points: (π/3, 1), (π/2, 3), (2π/3, 1), (5π/6, −1), (π, 1).
Example 5.8.2
Writing an equation from a graph description
  • ProblemA sinusoidal graph has maximum value 5, minimum value −1, period 4π, and the first maximum after x = 0 occurs at x = π. Write an equation of the form y = A cos(Bx − C) + D.
  • ThinkFind D and A from max/min; find B from period; find C from the phase shift (the maximum of cosine normally occurs at x = 0, so shift π to the right).
  • Solve D = (5 + (−1)) / 2 = 2 A = (5 − (−1)) / 2 = 3 Period 4π = 2π/B → B = 1/2 Cosine's maximum at x = π means phase shift = π → C/B = π → C = π · (1/2) = π/2 Equation: y = 3 cos((x/2) − (π/2)) + 2
  • CheckAt x = π: (π/2) − (π/2) = 0, cos(0) = 1, y = 3(1) + 2 = 5. ✓ Maximum is 5 at x = π.
y = 3 cos(x/2 − π/2) + 2
Graph Instruction — y = 2 sin(3x − π) + 1

Draw horizontal and vertical axes. Draw the midline y = 1 as a dashed horizontal line. Mark the five anchor points: (π/3, 1), (π/2, 3), (2π/3, 1), (5π/6, −1), (π, 1). Connect with a smooth sinusoidal wave that rises from the midline to the maximum, descends through the midline to the minimum, and returns. Label maximum y = 3 and minimum y = −1. Mark the period 2π/3 as the horizontal distance from start to end of the cycle. Extend the pattern one full cycle to the left as well.

Practice 5.8Transformations of Sine and Cosine

For each function: state amplitude, period, phase shift, midline, maximum value, minimum value, range, and five anchor points for one cycle. Then sketch the graph.

  1. y = 4 sin(x − π/2)
  2. y = −2 cos(2x) + 3
  3. y = 3 sin(πx/2 − π) − 1
  4. y = (1/2) cos(4x + π)
  5. y = −cos(x/3) + 2
  6. y = 5 sin(2x + π/2) − 3
  1. A sinusoidal graph has maximum 6, minimum −2, period π, and the cycle begins at x = π/4. Write an equation of the form y = A sin(Bx − C) + D.
  2. A sinusoidal graph begins its cycle at x = 0 at a midline value of 0, rises to a maximum of 4 at x = π/3, returns to midline at x = 2π/3, descends to −4 at x = π, and returns to 0 at x = 4π/3. Identify all four parameters and write the equation.

The Tangent Graph

The tangent function is fundamentally different from sine and cosine. While sin and cos are bounded — their outputs never exceed 1 or fall below −1 — the tangent function is unbounded. As its input approaches certain values, its output grows without limit in either the positive or negative direction. These values where tangent is undefined become vertical asymptotes on the graph.

Recall that tan(x) = sin(x)/cos(x). Tangent is undefined wherever cos(x) = 0, which occurs at x = ±π/2, ±3π/2, ±5π/2, and so on — the odd multiples of π/2. Between two consecutive asymptotes lies one complete cycle of the tangent function. Unlike sine and cosine, whose period is 2π, the period of tan(x) is π. The graph passes through zero once per cycle at the midpoint between consecutive asymptotes.

Within each cycle, the tangent curve rises from near −∞ at the left asymptote, crosses through zero at the center, and continues rising toward +∞ near the right asymptote. The shape is a steep S-curve or stretched diagonal that becomes nearly vertical close to the asymptotes.

x (radians)tan(x)Description
−π/2undefinedVertical asymptote (approaches −∞ from right)
−π/4−1Below zero
00Zero (center of cycle)
π/41Above zero
π/2undefinedVertical asymptote (approaches +∞ from left)
Key Properties of y = tan(x)

Domain: all real numbers except x = π/2 + nπ for any integer n

Range: (−∞, ∞) — unbounded in both directions

Period: π

Zeros: x = nπ for every integer n

Vertical asymptotes: x = π/2 + nπ for every integer n (odd multiples of π/2)

No amplitude: the function is unbounded, so amplitude is not defined for tangent

Midline: y = 0

Graph Instruction — y = tan(x)

Draw horizontal and vertical axes. Draw dashed vertical lines at x = −3π/2, −π/2, π/2, and 3π/2 to represent the asymptotes. On the interval (−π/2, π/2), plot the anchor points (−π/4, −1), (0, 0), and (π/4, 1). Connect with a smooth S-shaped curve that approaches −∞ near x = −π/2 and approaches +∞ near x = π/2. Repeat the same shape in the intervals (−3π/2, −π/2) and (π/2, 3π/2). Each branch is a separate curve that does not cross the asymptotes. Label the zeros at x = 0, ±π, ±2π.

Why Tangent Has Period π, Not 2π

Sine and cosine complete one full cycle as the unit circle makes one full revolution (2π radians). Tangent, as the ratio sin/cos, repeats its pattern in half that distance. After π radians, both sin and cos have opposite signs, but their ratio sin/cos is the same as it was π radians earlier. The sign pattern of the ratio repeats every π, so the period of tangent is π.

Practice 5.9The Tangent Graph
  1. List the vertical asymptotes of y = tan(x) on the interval [−2π, 2π].
  2. At what x-values does y = tan(x) cross the x-axis on [−2π, 2π]?
  3. Evaluate tan(0), tan(π/4), tan(π/3), tan(π/6), tan(−π/4). Leave exact answers.
  4. Sketch two full cycles of y = tan(x) from x = −π to x = π, including dashed asymptotes.
  5. For y = tan(2x): state the period and locations of vertical asymptotes.
  6. For y = 3 tan(x): how does the graph compare to y = tan(x)? What changes and what stays the same?

Asymptotes of Tangent

The vertical asymptotes of the tangent function deserve careful attention because they arise directly from the definition: tan(x) = sin(x)/cos(x). Division by zero is undefined. Wherever cos(x) = 0, the tangent function cannot be evaluated, and the graph approaches ±∞ near that input value. The asymptotes of y = tan(x) occur at every value where cos(x) = 0: that is, at x = π/2 + nπ for every integer n.

When the tangent is transformed to y = A tan(Bx − C) + D, the same logic applies. The vertical asymptotes occur wherever the argument Bx − C equals ±π/2 + nπ. To find the asymptote equations, set the argument equal to π/2 and −π/2 (and their periodic repetitions) and solve for x.

Near an asymptote, the tangent function grows rapidly toward +∞ on one side and falls rapidly toward −∞ on the other side. It does not cross or touch the asymptote. The asymptote is a boundary that the curve approaches but never reaches. Each branch of the tangent curve is trapped between two consecutive asymptotes and fills the entire vertical range (−∞, +∞) within that interval.

Asymptotes of y = A tan(Bx − C) + D

Vertical asymptotes occur where the argument equals π/2 + nπ:

Bx − C = π/2 + nπ

x = (C + π/2 + nπ) / B for every integer n

Period of y = tan(Bx): P = π / |B|

Adjacent asymptotes are separated by exactly one period P = π/|B|.

Example 5.10.1
Finding asymptotes of a transformed tangent
  • ProblemFind the period and the equations of the first two positive vertical asymptotes of y = tan(2x).
  • ThinkB = 2. Use the period formula and solve for asymptotes.
  • Solve Period = π / 2 Asymptotes where 2x = π/2 + nπ x = π/4 + nπ/2 First positive asymptote (n = 0): x = π/4 Second positive asymptote (n = 1): x = π/4 + π/2 = 3π/4
  • CheckAt x = π/4: 2(π/4) = π/2, and tan(π/2) is undefined. ✓ Distance between asymptotes: 3π/4 − π/4 = π/2 = one period. ✓
Period = π/2. Asymptotes at x = π/4 and x = 3π/4 (and repeating every π/2 in both directions).
Practice 5.10Asymptotes of Tangent
  1. y = tan(3x): period and first two positive asymptotes
  2. y = tan(x/2): period and first two positive asymptotes
  3. y = tan(x − π/4): describe the shift and list two asymptotes
  4. y = 2 tan(πx): period and two asymptotes near x = 0
  5. y = tan(x): how does the graph behave as x → π/2 from the left? From the right?
  6. y = −tan(x): how does the reflection affect the graph near asymptotes? Describe the behavior.
Sections 5.11 – 5.12
Reciprocal Function Graphs and Periodic Modeling
Secant · Cosecant · Cotangent Graphs · Modeling Periodic Data

Secant, Cosecant, and Cotangent Graphs

The graphs of the three reciprocal functions — secant, cosecant, and cotangent — are derived directly from the graphs of cosine, sine, and tangent. Because they are reciprocals, they are undefined wherever the base function equals zero, and their asymptotes occur at exactly those zero locations.

Cosecant is the reciprocal of sine: csc(x) = 1/sin(x). It is undefined wherever sin(x) = 0, which is at x = nπ for every integer n. The graph consists of U-shaped arches opening upward and downward alternately. Where sine reaches its maximum value of 1, cosecant equals 1. Where sine reaches its minimum of −1, cosecant equals −1. Between those extremes, cosecant curves away from the x-axis toward the asymptotes at the zeros of sine. The range of cosecant is (−∞, −1] ∪ [1, ∞) — it is never between −1 and 1.

Secant is the reciprocal of cosine: sec(x) = 1/cos(x). Its asymptotes occur at the zeros of cosine: x = π/2 + nπ. The secant graph is similar in shape to cosecant — alternating arches opening upward and downward — but offset by π/2 because cosine and sine are related by that horizontal shift. The range of secant is also (−∞, −1] ∪ [1, ∞).

Cotangent is the reciprocal of tangent: cot(x) = cos(x)/sin(x). Its asymptotes occur where sin(x) = 0, at x = nπ. Like tangent, cotangent has period π. But its shape is reversed: where tangent rises steeply from left to right, cotangent falls steeply from left to right within each cycle. Cotangent passes through zero at x = π/2 + nπ.

FunctionBase FunctionAsymptotesPeriodRange
csc(x)sin(x)x = nπ (where sine = 0)2π(−∞,−1] ∪ [1,∞)
sec(x)cos(x)x = π/2 + nπ (where cosine = 0)2π(−∞,−1] ∪ [1,∞)
cot(x)tan(x) (or sin/cos)x = nπ (where sine = 0)π(−∞,∞)
Graph Instruction — y = csc(x)

First, lightly sketch y = sin(x). Draw dashed vertical asymptotes at x = 0, ±π, ±2π (the zeros of sine). On the interval (0, π), where sine is positive, draw a U-shaped arch opening upward with its vertex at (π/2, 1) — the minimum of this arch, touching the maximum of sine. On the interval (π, 2π), where sine is negative, draw a U-shaped arch opening downward with its vertex at (3π/2, −1). Repeat this pattern in both directions. The cosecant graph never touches the x-axis; the arches approach the asymptotes without crossing them.

Graph Instruction — y = sec(x)

First, lightly sketch y = cos(x). Draw dashed vertical asymptotes at x = ±π/2, ±3π/2 (the zeros of cosine). On (−π/2, π/2), where cosine is positive, draw a U-shaped arch opening upward with vertex at (0, 1) touching the cosine maximum. On (π/2, 3π/2), where cosine is negative, draw a U-shaped arch opening downward with vertex at (π, −1). Repeat. Secant never equals zero and never exists between −1 and 1.

Graph Instruction — y = cot(x)

Draw dashed vertical asymptotes at x = 0, ±π, ±2π. On (0, π), the cotangent curve falls from near +∞ just right of x = 0, passes through (π/4, 1), crosses zero at (π/2, 0), passes through (3π/4, −1), and falls toward −∞ approaching x = π. The shape is a descending S-curve that mirrors the rising S-curve of tangent. Repeat the pattern between each pair of consecutive asymptotes.

Student Warning — Asymptotes of Reciprocal Functions

Students often confuse which function contributes the asymptotes. The rule is simple: the asymptotes of a reciprocal function occur at the zeros of the base function. Cosecant's asymptotes come from sine's zeros; secant's asymptotes come from cosine's zeros; cotangent's asymptotes come from sine's zeros (not cosine's). When in doubt, write out the base function and find where it equals zero.

Practice 5.11Secant, Cosecant, and Cotangent Graphs
  1. State the domain, range, period, and asymptotes of y = csc(x). Then describe the shape of one arch on (0, π).
  2. State the domain, range, period, and asymptotes of y = sec(x). How does the secant graph relate to the cosine graph?
  3. Compare the graphs of y = cot(x) and y = tan(x). How are they alike? How do they differ?
  4. Sketch y = csc(x) and y = sin(x) on the same axes from x = −π to x = 2π. Label the points of tangency (where the curves touch).
  5. For y = 2 sec(x): what is the minimum positive value the function can take? What is the range?
  6. For y = csc(2x): state the period and the locations of the asymptotes on [0, π].
  7. Evaluate: csc(π/2), sec(0), cot(π/4), sec(π), csc(3π/2), cot(π/2). Leave exact answers.

Modeling Periodic Data

A sinusoidal model is a function of the form y = A sin(Bx − C) + D or y = A cos(Bx − C) + D that is fitted to describe real-world data that repeats in a cycle. The four parameters carry specific meanings in every context: |A| is the amplitude — the half-range of oscillation; B determines the period — the length of one complete cycle; C/B is the phase shift — the horizontal position of the first peak or zero; and D is the vertical shift — the average or equilibrium value about which the oscillation occurs.

To build a sinusoidal model from data or a described situation, the procedure is: find the maximum and minimum values; compute D = (max + min)/2 and |A| = (max − min)/2; determine the period from the data and use B = 2π/P; determine the phase shift from the location of the first maximum, minimum, or zero. Then write the equation and verify it matches the data.

Building a Sinusoidal Model — Procedure

Step 1: Find maximum value M and minimum value m from the data or description

Step 2: D = (M + m) / 2 (midline = average of max and min)

Step 3: |A| = (M − m) / 2 (amplitude = half the total range)

Step 4: P = length of one complete cycle → B = 2π / P

Step 5: Determine phase shift from the location of the first max, min, or zero

Step 6: Write y = A sin(Bx − C) + D or y = A cos(Bx − C) + D and verify

Example 5.12.1
Modeling ocean tide height
  • SituationAt a coastal location, high tide reaches 4.5 meters and low tide drops to 0.5 meters. The tidal cycle repeats every 12 hours. High tide first occurs at t = 3 hours after midnight. Let t = hours since midnight.
  • ThinkCosine reaches its maximum at the start of a cycle; cosine is natural here because the first notable event is a maximum. Compute D, A, B, and the phase shift.
  • Solve D = (4.5 + 0.5) / 2 = 2.5 meters (average tide level) A = (4.5 − 0.5) / 2 = 2 meters (amplitude) P = 12 hours → B = 2π/12 = π/6 First maximum at t = 3 → phase shift 3 Cosine form: C/B = 3 → C = 3 · (π/6) = π/2 Model: y = 2 cos((π/6)t − π/2) + 2.5
  • CheckAt t = 3: (π/6)(3) − π/2 = π/2 − π/2 = 0, cos(0) = 1, y = 2(1) + 2.5 = 4.5. ✓ High tide at t = 3. At t = 9: (π/6)(9) − π/2 = 3π/2 − π/2 = π, cos(π) = −1, y = −2 + 2.5 = 0.5. ✓ Low tide at t = 9.
y = 2 cos((π/6)t − π/2) + 2.5 meters, where t is hours since midnight. The average tide is 2.5 m, amplitude is 2 m, and the cycle repeats every 12 hours.
Example 5.12.2
Modeling average monthly temperature
  • SituationA city's average monthly temperatures vary from a minimum of 30°F in January (month 1) to a maximum of 90°F in July (month 7). Model temperature T as a function of month m using a sinusoidal function.
  • ThinkThe cycle is 12 months long. The minimum is in month 1 and the maximum in month 7 — they are 6 months apart (half a period), which is expected for a sinusoidal cycle. Use cosine with a reflection (the minimum comes first) or use sine with careful phase placement.
  • Solve D = (90 + 30) / 2 = 60°F A = (90 − 30) / 2 = 30°F P = 12 months → B = 2π/12 = π/6 Minimum at m = 1: use −cos or shifted cosine. −cos(Bm − C) reaches minimum when argument = 0 → Bm − C = 0 → m = 1 C = B · 1 = π/6 Model: T = −30 cos((π/6)m − π/6) + 60
  • CheckAt m = 1: −(π/6) + (π/6) = 0? Wait: (π/6)(1) − π/6 = 0. cos(0) = 1. T = −30(1) + 60 = 30. ✓ Minimum in January. At m = 7: (π/6)(7) − π/6 = 6π/6 = π. cos(π) = −1. T = −30(−1) + 60 = 90. ✓ Maximum in July.
T = −30 cos((π/6)m − π/6) + 60°F, where m = 1 for January through m = 12 for December.
Sine vs. Cosine for Modeling — How to Choose

Both sine and cosine can model the same phenomenon — they differ only by a phase shift. In practice, choose cosine when the first notable feature in the data is a maximum or minimum (cosine starts at an extreme). Choose sine when the first notable feature is a zero crossing moving upward (sine starts at zero and rises). Either choice gives an equivalent model; the phase shift adjusts accordingly.

Practice 5.12Periodic Modeling Problems
  1. A buoy bobs so that its height above the ocean floor varies between 2 meters and 6 meters, completing one cycle every 10 seconds. At t = 0 it is at the midline and rising. Write a sinusoidal model for its height h as a function of time t in seconds.
  2. A Ferris wheel has a diameter of 40 meters and its lowest point is 5 meters above the ground. It completes one revolution every 30 seconds. A rider boards at the lowest point. Write a model for the rider's height h(t) as a function of time t in seconds.
  3. Average monthly temperatures in a northern city range from −10°C in February to 22°C in August. Model the temperature T as a function of month m (January = 1). What temperature does the model predict for May?
  4. A spring oscillates so that a weight attached to it moves between 8 cm above and 8 cm below its rest position, completing 3 full cycles per second. Write a model for the displacement d(t) if the weight starts at maximum displacement.
  5. A sinusoidal graph has maximum 12, minimum 4, passes through the midline going upward at x = 2, and has period 8. Write the equation.
  6. Sunlight duration (hours of daylight) in a city varies from 9 hours on the winter solstice (day 355 of the year) to 15 hours on the summer solstice (day 172). Write a model for daylight hours D as a function of day of the year t.
Sections 5.13 – 5.14
Common Mistakes and Preparing for Chapter 6
Common Trigonometric Graph Mistakes · Preparing for Identities and Equations

Common Trigonometric Graph Mistakes

Trigonometric graphing concentrates several common misconceptions in a small space. A student who misreads one parameter can produce a graph that is wrong in two or three ways simultaneously. The following errors appear repeatedly. Understanding each one before it trips you up will save significant time on exams and homework.

Mistake 1 — Confusing the period formula with the amplitude
For y = sin(3x), stating amplitude = 3 and period = 2π

Correct: The coefficient in front of the trig function is the amplitude. The coefficient inside the argument is B, which controls the period via P = 2π/B. For y = sin(3x), amplitude = 1 (no coefficient outside) and period = 2π/3. For y = 3 sin(x), amplitude = 3 and period = 2π.

Mistake 2 — Wrong direction for phase shift
For y = sin(x + π/3), stating the phase shift is π/3 to the right

Correct: When the argument is Bx + C (addition inside), the shift is to the LEFT by C/B. Factor first: sin(x + π/3) = sin[1·(x − (−π/3))], revealing a shift of −π/3, which is π/3 to the left. Subtraction inside → right. Addition inside → left.

Mistake 3 — Reporting a negative amplitude
For y = −4 sin(x), stating amplitude = −4

Correct: Amplitude is always non-negative. For y = −4 sin(x), amplitude = |−4| = 4. The negative sign indicates a vertical reflection — the graph is flipped — but the amplitude is 4, not −4.

Mistake 4 — Forgetting the midline when graphing
For y = 2 sin(x) + 3, drawing the graph oscillating between −2 and +2

Correct: The vertical shift D = 3 raises the midline from y = 0 to y = 3. The graph oscillates between 3 − 2 = 1 and 3 + 2 = 5, not between −2 and 2. Always draw the midline first and measure amplitude from it.

Mistake 5 — Treating asymptotes as zeros for tangent
Marking the asymptotes of y = tan(x) at x = 0, π, 2π (the zeros of tangent)

Correct: The asymptotes of y = tan(x) occur at x = π/2 + nπ — the zeros of cosine, not the zeros of tangent. The zeros of tangent (where tan(x) = 0) occur at x = nπ, which is exactly where the curve crosses the x-axis. Asymptotes and zeros are at different locations.

Mistake 6 — Incorrectly dividing the cycle into five points
Placing the five anchor points at equal spacing of P/5 apart

Correct: The five anchor points divide one cycle into FOUR equal intervals, each of width P/4. The five points are at x₀, x₀ + P/4, x₀ + P/2, x₀ + 3P/4, x₀ + P — that is, start of cycle, quarter cycle, half cycle, three-quarter cycle, end of cycle. There are four intervals between the five points, not five.

Mistake 7 — Drawing a sharp peak or corner at the maximum or minimum
Drawing the sine wave with a pointed tip at the maximum (π/2, 1)

Correct: The sine and cosine graphs are smooth, continuous curves. At the maximum and minimum, the curve is rounded — it has zero slope at that point. The top and bottom of each cycle are smooth arches, not pointed spikes. Only asymptotes involve behavior that approaches infinity; maxima and minima are smooth turning points.

Practice 5.13Error Analysis

Each problem describes a student's work or claim. Identify the error and state the correct answer or corrected approach.

  1. A student says the function y = cos(5x) has amplitude 5. Identify and correct the error.
  2. A student graphs y = sin(x − π/4) and shifts the graph to the LEFT by π/4. Is this correct? Explain.
  3. A student states that y = −2 cos(x) has amplitude −2. What is the amplitude, and what does the negative sign actually indicate?
  4. A student is graphing y = 3 sin(x) + 5 and draws the graph oscillating between −3 and 3. What is wrong? What should the range be?
  5. A student marks the asymptotes of y = tan(x) at x = 0 and x = π. What is the error? Where are the actual asymptotes?
  6. A student places the five anchor points of y = sin(x) at x = 0, π/5, 2π/5, 3π/5, 4π/5 for one cycle. What is wrong? Where should the five points be?

Preparing for Identities and Equations

Chapter 6 will study trigonometric identities and equations. An identity is an equation that is true for every value in the domain of the functions involved — it describes a structural relationship rather than asking you to find a specific value. Knowing the graphs of all six trigonometric functions prepares you for identity work in two important ways.

First, the graphs help you understand whether a proposed identity is plausible. If you claim that sin(x) = cos(x) for all x, you need only recall that the sine and cosine graphs intersect at only two points per cycle — they are clearly not identical. On the other hand, the observation that sin(x + π/2) = cos(x) is visually obvious from the graphs: the cosine curve is the sine curve shifted π/2 units to the left. The graph confirms the identity before any algebra begins.

Second, the graphs help you solve trigonometric equations. A trigonometric equation asks for the values of x that make the equation true — this is a different question from evaluating a function or verifying an identity. Graphically, solving sin(x) = 0.5 means finding the x-values where the horizontal line y = 0.5 intersects the sine curve. Because the sine curve is periodic, there are infinitely many solutions. Chapter 6 will develop the algebraic methods for finding them precisely, but the graphical understanding from Chapter 5 provides the foundation.

Graphical Preview — Solving Trigonometric Equations

Consider the equation 2 sin(x) − 1 = 0. Solving gives sin(x) = 1/2. Graphically, this asks where the horizontal line y = 1/2 intersects the graph of y = sin(x). From the unit circle, sin(π/6) = 1/2 and sin(5π/6) = 1/2. Within each period of 2π, there are exactly two solutions. On the interval [0, 2π], the solutions are x = π/6 and x = 5π/6. The graph makes the number of solutions per cycle visible before any algebraic work begins.

Practice 5.14Readiness Check
  1. On the interval [0, 2π], at how many points does the graph of y = sin(x) equal 1/2? Estimate those x-values from the graph.
  2. On [0, 2π], at how many points does y = cos(x) equal −1? At how many does it equal −1/2?
  3. Use the graphs of sin and cos to explain visually why sin²(x) + cos²(x) = 1 is plausible. (Hint: think about what sin²(x) + cos²(x) represents on the unit circle.)
  4. Verify numerically that sin(x + π/2) = cos(x) at x = 0, π/4, π/2, and π. Then explain what this means graphically.
  5. The equation sin(x) = sin(π − x) is an identity. Verify it at x = π/6, x = π/4, and x = π/3. What symmetry of the sine graph does this reflect?
  6. Graphically estimate the solutions to cos(x) = 0.7 on [0, 2π] by sketching the sine graph and a horizontal line. Then describe how many solutions exist over all real numbers.

Chapter Summary

Key Terms Review

periodic function
A function whose values repeat in a regular cycle; f(x + P) = f(x) for all x in the domain, where P is the period.
period
The horizontal length of one complete cycle of a periodic function. For y = A sin(Bx), the period is 2π/|B|.
amplitude
The maximum distance from the midline to the maximum or minimum value. Amplitude = |A| for y = A sin(Bx) + D. Always non-negative.
midline
The horizontal line y = D that runs halfway between the maximum and minimum of a sinusoidal function. The function oscillates equally above and below this line.
vertical shift
The constant D in y = A sin(Bx) + D that moves the entire graph up (D > 0) or down (D < 0) without changing shape, amplitude, or period.
phase shift
A horizontal translation of a trigonometric graph equal to C/B in y = A sin(Bx − C) + D. Positive C/B shifts the graph to the right.
sinusoidal function
A function of the form y = A sin(Bx − C) + D or y = A cos(Bx − C) + D. Its graph is a smooth wave with constant amplitude, period, and midline.
vertical asymptote
A vertical line x = a that a graph approaches but never reaches; the function grows without bound near this value. Tangent, secant, cosecant, and cotangent all have vertical asymptotes.
tangent function
tan(x) = sin(x)/cos(x). Period π, range (−∞, ∞), undefined where cosine equals zero. The graph is an unbounded S-shaped curve between consecutive asymptotes.
secant function
sec(x) = 1/cos(x). Its graph consists of alternating U-shaped arches; asymptotes at zeros of cosine; range (−∞, −1] ∪ [1, ∞).
cosecant function
csc(x) = 1/sin(x). Its graph consists of alternating U-shaped arches; asymptotes at zeros of sine; range (−∞, −1] ∪ [1, ∞).
cotangent function
cot(x) = cos(x)/sin(x). Period π, range (−∞, ∞), asymptotes where sine equals zero, zeros at π/2 + nπ. The graph is a descending S-curve within each cycle.
five-point method
A graphing procedure that identifies the five anchor points of one cycle — start, quarter cycle, half cycle, three-quarter cycle, and end — spaced P/4 apart, to sketch any transformed sine or cosine function.
frequency
The number of cycles completed per unit of time. Frequency = 1/Period. Used especially in physics and signal processing to describe how rapidly a wave oscillates.
sinusoidal model
A sinusoidal function fitted to describe real-world data that repeats cyclically. Parameters A, B, C, D are determined from the amplitude, period, phase shift, and midline of the data.
even function
A function satisfying f(−x) = f(x) for all x; its graph is symmetric about the y-axis. Cosine is even.
odd function
A function satisfying f(−x) = −f(x) for all x; its graph has rotational symmetry about the origin. Sine and tangent are odd.
cycle
One complete pattern of a periodic function from start to just before the pattern repeats. For y = sin(x), one cycle covers an interval of length 2π.

Concept Review Questions

  1. What does it mean for a function to be periodic? How is the period defined formally?
  2. What are the domain, range, period, and amplitude of y = sin(x)? How do these properties arise from the unit circle?
  3. In what ways are the graphs of y = sin(x) and y = cos(x) alike? In what ways do they differ?
  4. Explain the difference between amplitude and vertical shift. Which parameter changes the maximum value of the function, and how?
  5. A student says "bigger B means a longer period." Is this correct? Explain with the period formula.
  6. Explain why the phase shift of y = sin(Bx + C) is to the left, not to the right, when C is positive.
  7. Why does y = tan(x) have vertical asymptotes while y = sin(x) does not?
  8. What is the connection between the graph of y = csc(x) and the graph of y = sin(x)? Where are the asymptotes of cosecant, and why?
  9. A sinusoidal model is built from data showing maximum 10 and minimum −2. Without knowing the period or phase, state the midline and amplitude.
  10. Describe in words how to graph y = A sin(Bx − C) + D using the five-point method. What information do you need and in what order do you use it?

Sine and Cosine Graphing Practice

Part AIdentifying Features from Formulas

For each function, state: amplitude, period, phase shift, midline, maximum value, minimum value, and range.

  1. y = 5 sin(x)
  2. y = −3 cos(x)
  3. y = sin(4x)
  4. y = cos(x/3)
  5. y = 2 sin(x) − 4
  6. y = cos(x) + 7
  7. y = 4 cos(2x) + 1
  8. y = −sin(3x) − 2
  9. y = (3/2) sin(πx) + 3
  10. y = −2 cos(x/4) − 5
Part BFive Anchor Points and Sketching

For each function, find the five anchor points for one complete cycle and sketch the graph. Label the midline.

  1. y = 3 sin(2x)
  2. y = −2 cos(x/2) + 1
  3. y = sin(x − π/4)
  4. y = 4 cos(x + π/2)
  5. y = 2 sin(3x − π/2) + 1
  6. y = −3 cos(2x + π) − 2

Transformation Practice

Part CFull Transformations — All Four Parameters
  1. For y = 4 sin(2x − π) + 3: state all four parameters, compute all features, find the five anchor points, and sketch one complete cycle with the midline labeled.
  2. For y = −5 cos(πx/2 + π) − 1: state all four parameters and find the five anchor points for the first cycle beginning at x ≥ 0.
  3. A sinusoidal graph has the following properties: maximum 9, minimum 1, period 6, first maximum at x = 1. Write a cosine equation of the form y = A cos(Bx − C) + D.
  4. A sinusoidal graph passes through (0, 0) going upward, reaches a maximum of 6 at x = π/4, returns to zero at x = π/2, reaches minimum −6 at x = 3π/4, and returns to zero at x = π. Write an equation for the function.
  5. Starting with y = sin(x), describe in words the sequence of transformations needed to produce y = −2 sin(3x − π) + 4. Then graph the result.

Tangent Graph Practice

Part DTangent Functions
  1. y = tan(x): period, asymptotes on [−π, π], zeros, sketch
  2. y = tan(2x): period, asymptotes near x = 0, sketch one cycle
  3. y = tan(x/2): period and first two positive asymptotes
  4. y = 3 tan(x): how does the 3 affect the graph?
  5. y = −tan(x): describe the reflection
  6. y = tan(x − π/4): phase shift and new zero location
  1. Compare the graphs of y = tan(x), y = 2 tan(x), and y = tan(2x). For each, state the period and describe how it differs from the basic tangent graph.
  2. Explain why it is impossible for y = tan(x) to have an amplitude. What makes this function different from sine and cosine in this respect?

Periodic Modeling Problems

For each situation: identify the four parameters A, B, C, D; write the equation; use the model to answer the question asked; and verify the model at the boundary conditions.

  1. Spring oscillation. A spring stretches a weight from 3 cm above its rest position to 3 cm below, completing 2 full cycles per second. At t = 0, the weight is at the rest position and moving downward. Write a model for displacement d(t) in centimeters. What is the displacement at t = 0.25 seconds?
  2. Ferris wheel. A Ferris wheel of radius 25 meters has its lowest point 4 meters above the ground and completes one rotation every 40 seconds. A rider boards at the bottom. Write a model for height h(t) in meters. How high is the rider at t = 10 seconds? At t = 25 seconds?
  3. Sound wave. A pure musical tone can be modeled as a sinusoidal function. Concert A has frequency 440 Hz (cycles per second). Write a model of the form y = sin(Bt) for this tone. What is the period in seconds?
  4. Daylight hours. In a northern city, the longest day of the year (June 21, approximately day 172) has 16 hours of daylight, and the shortest (December 21, day 355) has 8 hours. Write a sinusoidal model D(t) for daylight hours as a function of day t. Estimate the daylight hours on March 21 (day 80) and September 21 (day 264).
  5. Tidal data interpretation. Suppose you are given the following tide height data (in meters): at t = 0, height = 3.0 m; at t = 3, height = 5.5 m (high tide); at t = 6, height = 3.0 m; at t = 9, height = 0.5 m (low tide); at t = 12, height = 3.0 m (back to start). Identify the period, amplitude, midline, and phase shift. Write a sinusoidal model and use it to estimate height at t = 4 and t = 10.
  6. Breathing rate. A person at rest breathes in and out with chest displacement modeled sinusoidally. The maximum chest expansion is 2.5 cm from the rest position, and the person completes 15 full breath cycles per minute. Write a model, then determine the displacement at t = 1 second and t = 3 seconds after the start of an inhalation (at maximum expansion).

Error Analysis

Each problem describes a student's claim or work. Identify the error and write the correct answer.

Error Analysis Problem 1
For y = 2 sin(πx/3), a student states amplitude = 2 and period = π/3.

What is wrong? State the correct period and explain how to compute it.

Error Analysis Problem 2
For y = sin(x + π/6), a student states the phase shift is π/6 to the right.

Identify the direction error. What is the correct phase shift and direction?

Error Analysis Problem 3
A student graphs y = 3 sin(x) + 2 and says the graph ranges from −3 to 3.

What is the error? Find the correct maximum, minimum, and range.

Error Analysis Problem 4
A student states that csc(x) = 0 when sin(x) = 0.

Explain the error completely. What actually happens to csc(x) when sin(x) = 0?

Error Analysis Problem 5
A student places vertical asymptotes of y = cot(x) at x = π/2 + nπ.

Are these the correct asymptotes for cotangent? If not, state the correct asymptote locations and explain why.

Error Analysis Problem 6
To model a phenomenon with max 8 and min 2, a student writes A = 8 and D = 2.

What are the correct values of A and D? Explain the formulas used to find them.

Chapter 5 Checkpoint

Chapter 5 Checkpoint
Complete without assistance — assesses all key skills and concepts from Chapter 5
Section 1 — Vocabulary and Concepts
  1. Define periodic function. What is the period of y = sin(x), and why?
  2. What is amplitude? How is it related to the coefficient A in y = A sin(Bx) + D?
  3. Explain the difference between phase shift and vertical shift. What parameter controls each?
  4. Why does y = tan(x) have vertical asymptotes? Where are they, and what is the period of tangent?
  5. How are the graphs of y = csc(x) and y = sin(x) related? Where do the asymptotes of cosecant occur?
Section 2 — Reading Parameters
  1. For y = 3 sin(2x − π) + 1, state the amplitude, period, phase shift, midline, maximum value, minimum value, and range.
  2. For y = −(1/2) cos(πx/4) − 3, state the same six features. Does the negative sign affect the amplitude?
Section 3 — Graphing
  1. List the five anchor points for one cycle of y = 4 cos(3x − π/2) + 2 starting at x = π/6.
  2. Sketch two complete cycles of y = 2 sin(x/2) by hand. Label the amplitude, midline, and one complete period on your sketch.
  3. Describe the graph of y = −tan(2x). State the period, asymptotes on [−π/2, π/2], and the direction of the curve.
Section 4 — Writing Equations from Graphs
  1. A sinusoidal graph has maximum value 5, minimum value −3, period 4, and the first maximum after x = 0 occurs at x = 1. Write an equation of the form y = A cos(Bx − C) + D.
  2. A graph of a cosine function starts at (0, 7), descends to a minimum of −1 at x = 4, and returns to maximum at x = 8. Write an equation for the function.
Section 5 — Modeling
  1. A buoy bobs between 1 meter and 7 meters above the ocean floor, completing one cycle every 6 seconds. At t = 0, it is at the midline and rising. Write a sinusoidal model for its height h(t). What is the height at t = 1.5 seconds?
  2. A city's average daily high temperature varies between 50°F in January (month 1) and 86°F in July (month 7). Model the temperature T as a function of month m. Estimate the average high in April (month 4).
Section 6 — Error Analysis
  1. A student states that y = sin(5x) has amplitude 5 and period 2π. Identify both errors and give the correct values.
  2. A student graphs y = cos(x + π/3) and shifts the graph π/3 to the right. Explain the error and state the correct direction of shift with justification.
  3. A student is building a model with maximum 10 and minimum 4 and writes A = 10, D = 4. Find the correct values of A and D using the midline formula.
Bridge Note — Looking Ahead
Chapter 6: Trigonometric Identities and Equations

Chapter 5 made trigonometric functions visible. You can now recognize and produce the wave shape of any transformed sine, cosine, tangent, or reciprocal function, and you can build models from real periodic data. Chapter 6 will move inside those graphs, asking a different question: what algebraic relationships hold between the six trigonometric functions? An identity is a relationship that is always true — valid for every input where the expressions are defined. The Pythagorean identity sin²(x) + cos²(x) = 1 is the most fundamental, arising directly from the equation of the unit circle. From it flow the reciprocal identities, quotient identities, even-odd identities, cofunction identities, and eventually the sum, difference, double-angle, and half-angle identities. You will use these identities to simplify expressions, verify relationships, and solve trigonometric equations — finding the exact set of x-values where a trigonometric equation holds. The graphical intuition from Chapter 5 — knowing approximately where curves intersect, understanding periodic repetition, and recognizing the shape of the wave — will support every step.

MGU Library Connection
  • Appendix F: Unit Circle Reference — all special angle values for sin, cos, tan and reciprocals
  • Appendix G: Trigonometric Identities Reference — all identities developed in Chapter 6
  • Appendix H: Trigonometric Graphs Reference — quick visual reference for all six function graphs
  • Chapter 4 of this textbook: The Unit Circle and Trigonometric Functions — foundation for all graph features
  • Chapter 6: Trigonometric Identities and Equations — direct continuation; graphs support identity and equation work
  • Chapter 12: Parametric Equations and Vectors — parametric curves produced by trigonometric functions
  • Chapter 13: Limits and Continuity — the derivatives of sin(x) and cos(x) in Calculus I depend on the graph's slope behavior at each point
  • MGU Physics Library: Waves, Oscillations, and Periodic Motion — sinusoidal models in mechanical and electromagnetic waves
  • MGU Engineering Library: Signal Processing — frequency, amplitude, phase, and the Fourier series as an extension of trigonometric modeling