MGU Mathematics Series — Differential Equations
Part I: Foundations of Differential Equations and Modeling
ODEs · Solutions · Slope Fields · Models · Classification
Chapter 1 of 14
MGU Mathematics Series  ·  Differential Equations  ·  Library Textbook Edition

Chapter 1:
What Differential
Equations Study

The mathematics of change — what differential equations are, how they are classified, what their solutions mean, and how slope fields reveal behavior before a formula is found

■ Math Level: Post-Calculus ■

■ 14 Sections  •  Part I of 5 ■

Follows Calculus  ·  Alongside or After Linear Algebra  ·  Prepares students for Chapters 2 through 14

Purpose and Overview

This chapter opens the study of differential equations by explaining what differential equations are, why they matter, and how they connect to the calculus you already know. Before introducing solution techniques, this chapter builds understanding. You will learn to recognize differential equations, classify them, interpret their solutions as functions, and begin to see how they describe real systems in science, engineering, biology, economics, and many other fields.

Differential equations should not feel like a new subject disconnected from calculus. They are a natural continuation of it. Calculus studies rates of change and accumulation. Differential equations use those same ideas to describe relationships between changing quantities, and then ask: given this relationship between a function and its own rate of change, what function satisfies it? That question, simple to state but rich in consequence, is what differential equations study.

Opening Question

Suppose you know that the rate at which a population grows is proportional to the size of the population. Larger populations grow faster; smaller populations grow slower. You want to find a function $P(t)$ that describes the population at every time $t$. You are not given $P(t)$ directly. You are given a relationship: $\dfrac{dP}{dt} = kP$, where $k$ is a positive constant. This is a differential equation. It does not say what $P$ is. It says something about how $P$ changes. This chapter prepares you to understand what such an equation means, how its solutions behave, and what questions you will learn to answer throughout this book.

14Sections
11Objectives
20Key Terms
8+Worked Examples

Learning Objectives

  1. 1Explain what a differential equation is in your own words.
  2. 2Identify the dependent variable, independent variable, and derivative in a differential equation.
  3. 3Distinguish ordinary differential equations from partial differential equations.
  4. 4Determine the order and degree of a differential equation.
  5. 5Classify a differential equation as linear or nonlinear.
  6. 6Verify that a given function is a solution to a differential equation.
  7. 7Distinguish general solutions from particular solutions.
  8. 8Use initial conditions to determine a particular solution from a general solution.
  9. 9Interpret a slope field and sketch solution curves from it.
  10. 10Recognize how differential equations arise as mathematical models of real systems.
  11. 11Identify common early misunderstandings about differential equations.

Sections at a Glance

Sections 1.1 – 1.3
What Differential Equations Study
The Central Question · Functions and Rates · Equations Involving Unknown Functions

What Differential Equations Study

Calculus gives you two fundamental tools. Differentiation finds rates of change. Integration recovers quantities from rates of change. With these tools, you can describe how things move, grow, shrink, oscillate, heat up, cool down, and respond to forces.

But calculus, as you first learned it, usually starts with a known function and asks you to differentiate or integrate it. Differential equations reverse this situation. Instead of starting with a known function, you are given a relationship that the unknown function must satisfy. The relationship involves the function and one or more of its derivatives. Your task is to find the function itself.

Consider a simple example. Suppose you know that some quantity $y$ changes at a rate equal to the quantity itself:

$$\frac{dy}{dx} = y$$

This equation does not tell you what $y$ is. It tells you that the rate of change of $y$ equals $y$. Any function satisfying this relationship is a solution. The function $y = e^x$ satisfies it, because its derivative equals itself. More generally, $y = Ce^x$ for any constant $C$ satisfies it, as you can verify.

This is the essential picture of what differential equations study: relationships between unknown functions and their derivatives, and the task of finding functions that satisfy those relationships.

Core Vocabulary

A differential equation is an equation that involves an unknown function and one or more of its derivatives.

The dependent variable is the unknown function being solved for. The independent variable is the variable it depends on.

In $\dfrac{dP}{dt} = kP$, the dependent variable is $P$ (population) and the independent variable is $t$ (time).

Functions, Derivatives, and Rates of Change

QuantityFunction NotationDerivativeMeaning of Derivative
Population$P(t)$$\dfrac{dP}{dt}$Rate of growth or decay
Temperature$T(t)$$\dfrac{dT}{dt}$Rate of heating or cooling
Position$x(t)$$\dfrac{dx}{dt}$Velocity
Velocity$v(t)$$\dfrac{dv}{dt} = \dfrac{d^2x}{dt^2}$Acceleration
Charge$q(t)$$\dfrac{dq}{dt}$Current
Concentration$C(t)$$\dfrac{dC}{dt}$Rate of change of concentration

In real systems, the rate of change of a quantity often depends on the current state of the system. Population grows faster when there are more individuals. A hot object cools faster when the temperature difference is larger. A drug leaves the bloodstream faster when its concentration is higher. These observations, written mathematically, become differential equations.

Physical PrincipleDifferential Equation
Newton's Law of Cooling$\dfrac{dT}{dt} = -k(T - T_{\text{amb}})$
Exponential growth$\dfrac{dN}{dt} = rN$
Simple harmonic motion$\dfrac{d^2x}{dt^2} = -\omega^2 x$

Equations Involving Unknown Functions

The central challenge of differential equations is this: you are given information about the derivative of a function, and you must recover the function. In the simplest case you already know how to do this. If $\frac{dy}{dx} = 2x$, direct integration gives $y = x^2 + C$. But when the right side involves $y$ itself, direct integration no longer suffices. The equation $\frac{dy}{dx} = y$ connects the rate of change of $y$ to the value of $y$, and a different strategy is needed.

EquationStructureSolution Family
$\dfrac{dy}{dx} = 3x^2$Derivative only on right; direct integration works$y = x^3 + C$
$\dfrac{dy}{dx} = y$Derivative equals the function itself$y = Ce^x$
$\dfrac{dy}{dx} = xy$Derivative equals product of $x$ and $y$$y = Ce^{x^2/2}$
$y'' + y = 0$Second derivative plus function equals zero$y = A\sin x + B\cos x$
$y'' + 2y' + y = e^x$Second-order with forcing termCovered in Chapter 8
Key Insight

When you solve a differential equation, the solution is a function, not a number. Finding the solution means finding a formula that works for every point in the function's domain. This is a fundamental shift from algebra.

Sections 1.4 – 1.6
Classifying Differential Equations
ODE vs PDE · Order and Degree · Linear and Nonlinear

Ordinary and Partial Differential Equations

The first major classification separates equations involving functions of a single variable from equations involving functions of several variables.

ODE vs PDE

An ordinary differential equation (ODE) involves a function of a single independent variable and its ordinary derivatives. All of Chapters 1–12 concern ODEs.

A partial differential equation (PDE) involves a function of several independent variables and its partial derivatives. PDEs are introduced as a preview in Chapter 13.

EquationTypeDescription
$\dfrac{dP}{dt} = kP$ODEPopulation growth; one variable $t$
$m\dfrac{d^2x}{dt^2} + kx = 0$ODEMass-spring; one variable $t$
$\dfrac{\partial u}{\partial t} = \alpha \dfrac{\partial^2 u}{\partial x^2}$PDEHeat equation; variables $x$ and $t$
$\dfrac{\partial^2 u}{\partial x^2} + \dfrac{\partial^2 u}{\partial y^2} = 0$PDELaplace's equation; variables $x$ and $y$
Notation Note

For ODEs, both Leibniz notation $\left(\dfrac{dy}{dx},\, \dfrac{d^2y}{dx^2}\right)$ and prime notation $(y', y'')$ are common throughout this book. In physics and engineering, dot notation $(\dot x, \ddot x)$ is also used for time derivatives. PDEs use the stylized $\partial$ to distinguish partial derivatives from ordinary ones.

Order and Degree

Definitions

The order of a differential equation is the order of the highest derivative present.

The degree is the power to which the highest-order derivative is raised, after the equation has been put in polynomial form in its derivatives.

EquationOrderDegreeReason
$y' = ky$1st1stHighest derivative is $y'$, appears once
$y'' - 3y' + 2y = 0$2nd1stHighest derivative is $y''$, appears once
$\left(\dfrac{d^2y}{dx^2}\right)^2 + y = 0$2nd2nd$y''$ is raised to the second power
$\left(\dfrac{dy}{dx}\right)^3 = y$1st3rd$y'$ is raised to the third power
$y''' + xy'' - y = e^x$3rd1stHighest derivative is $y'''$, appears once
Common Confusion — Order vs Degree

Order and degree are not the same. The equation $\left(y'\right)^3 = y$ is first-order (the highest derivative is $y'$) but third-degree (that derivative is cubed). Do not confuse the exponent on the derivative with the order of the derivative.

Why Order Matters

The order tells you how many arbitrary constants appear in the general solution, and therefore how many initial or boundary conditions are needed to pin down a unique particular solution. A first-order equation needs one condition; a second-order equation needs two.

Linear and Nonlinear Differential Equations

After determining order, the next major classification is linear versus nonlinear. This distinction determines which solution methods are available.

Linearity Conditions

A differential equation is linear if the unknown function and all its derivatives appear to the first power only, no products of $y$ with its derivatives appear, and coefficients are functions of the independent variable only — not of $y$.

General linear first-order form:   $a_1(x)\,y' + a_0(x)\,y = f(x)$

General linear second-order form:   $a_2(x)\,y'' + a_1(x)\,y' + a_0(x)\,y = f(x)$

EquationLinear?Reason
$y' + 2y = e^x$Yes$y$ and $y'$ each appear to the first power
$y'' - 3y' + 2y = 0$YesAll derivatives appear linearly; constant coefficients
$x^2 y'' + xy' - y = \sin x$YesCoefficients are functions of $x$, not $y$
$y' = y^2$No$y$ appears squared
$y'' + \sin(y) = 0$No$\sin(y)$ is nonlinear in $y$
$y\,y' = x$NoProduct of $y$ with its derivative
Do Not Confuse These Uses of "Linear"

In this context, linear refers to the algebraic structure of how the unknown function and its derivatives appear in the equation — not to whether the solution curves are straight lines. A linear differential equation may have solutions that oscillate, grow exponentially, or decay. The linearity is in the equation's structure, not the shape of its solutions.

Why Linearity Matters

Linear equations satisfy a superposition principle: if $y_1$ and $y_2$ are both solutions to the homogeneous version, then $c_1 y_1 + c_2 y_2$ is also a solution. This powerful property allows systematic construction of general solutions and underlies all the methods in Chapters 3 through 10.

Practice 1.4–1.6Classification Practice

For each equation, state: (a) ODE or PDE, (b) order, (c) degree, (d) linear or nonlinear.

  1. $y' = 5y$
  2. $y'' - 4y' + 3y = 0$
  3. $\left(y'\right)^2 + y = x$
  4. $y''' + xy'' - y = e^x$
  5. $y\,y' = x$
  6. $y'' + \sin(y) = 0$
  7. $\dfrac{\partial u}{\partial t} = k\dfrac{\partial^2 u}{\partial x^2}$
  8. $y' = 1 + y^2$
Sections 1.7 – 1.10
Solutions, Conditions, and Slope Fields
Verifying Solutions · General and Particular · Initial Conditions · Direction Fields

Solutions as Functions

A solution to a differential equation is a function that, when substituted into the equation along with its required derivatives, makes the equation true for all values of the independent variable in some interval. Verifying a proposed solution always requires substitution, not just plausibility.

Example 1.7.1
Verifying a solution by substitution
  • ProblemVerify that $y = e^{2x}$ is a solution to $y' - 2y = 0$.
  • ThinkCompute $y'$, then substitute both $y$ and $y'$ into the equation and check whether the result is identically zero.
  • Solve y = e^(2x), so y' = 2e^(2x) y' − 2y = 2e^(2x) − 2·e^(2x) = 0 ✓
  • CheckThe equation holds for all $x$, not just at isolated points. The equality is an identity.
  • InterpretThe function $y = e^{2x}$ grows exponentially. Its rate of change, $y' = 2e^{2x}$, is exactly twice itself at every point, which is precisely what $y' = 2y$ requires.
Answer: Yes — $y = e^{2x}$ is a solution to $y' - 2y = 0$.
Example 1.7.2
Verifying a solution to a second-order equation
  • ProblemVerify that $y = \sin(x)$ is a solution to $y'' + y = 0$.
  • ThinkCompute $y'$ and $y''$, then substitute into the equation.
  • Solve y = sin(x), y' = cos(x), y'' = −sin(x) y'' + y = −sin(x) + sin(x) = 0 ✓
  • CheckThe equation holds identically.
  • Interpret$\sin(x)$ oscillates, and its second derivative is its own negative. This is the fundamental property that makes trigonometric functions solutions to harmonic oscillation equations. Note that $\cos(x)$ is also a solution, as is any combination $A\sin(x) + B\cos(x)$.
Answer: Yes — $y = \sin(x)$ is a solution to $y'' + y = 0$.
Example 1.7.3
Checking a function that is not a solution
  • ProblemIs $y = x^2$ a solution to $y' - 2y = 0$?
  • Solve y = x², y' = 2x y' − 2y = 2x − 2x² = 2x(1 − x)
  • CheckThis equals zero only when $x = 0$ or $x = 1$. It is not zero for all $x$, so the equation is not satisfied identically.
  • Interpret$y = x^2$ does not satisfy $y' = 2y$ as a functional identity. A solution must work at every point in its domain, not just at isolated values.
Answer: No — $y = x^2$ is not a solution to $y' - 2y = 0$.
Habit to Build Now

Always verify your solutions by substitution. Even when you derive an answer using a correct method, substituting back into the original equation is the most reliable way to catch computational errors. This takes one minute and should become automatic.

General Solutions and Particular Solutions

Definitions

The general solution of a differential equation is an expression describing the entire family of solutions, typically involving one or more arbitrary constants. A first-order equation has one arbitrary constant $C$; a second-order equation has two, often $C_1$ and $C_2$.

A particular solution is a specific member of the family, obtained when the constants are assigned specific values.

The general solution to $\dfrac{dy}{dx} = ky$ is $y = Ce^{kx}$. You can verify: $\dfrac{d}{dx}(Ce^{kx}) = Cke^{kx} = k(Ce^{kx}) = ky$ for any constant $C$. Each choice of $C$ gives a different solution curve, but every curve in the family satisfies the equation.

Example 1.8.1
Finding a particular solution from a general solution
  • ProblemThe general solution to $y' + y = 0$ is $y = Ce^{-x}$. Find the particular solution satisfying $y(0) = 3$.
  • ThinkSubstitute $x = 0$ and $y = 3$ into the general solution to determine $C$.
  • Solve 3 = C·e^(−0) = C·1 → C = 3 Particular solution: y = 3e^(−x)
  • Check$y' = -3e^{-x}$. Then $y' + y = -3e^{-x} + 3e^{-x} = 0$ ✓. Also $y(0) = 3e^0 = 3$ ✓.
  • InterpretAmong all functions of the form $Ce^{-x}$, this is the unique one that starts at $y = 3$ when $x = 0$. It decays exponentially toward zero as $x$ increases.
Answer: $y = 3e^{-x}$

Initial Conditions and Boundary Conditions

TypeDescriptionExampleUse
Initial conditionValue of solution (or derivative) specified at a single point$y(0) = 5$Initial value problems; time evolution forward from a known state
Boundary conditionValues specified at two or more different points$y(0) = 0,\; y(\pi) = 0$Boundary value problems; spatial problems with constraints at endpoints

An initial value problem (IVP) pairs a differential equation with initial conditions. For a first-order equation, one initial condition determines a unique solution. For a second-order equation, two initial conditions are required.

Example 1.9.1
Solving an initial value problem
  • ProblemSolve the IVP: $\dfrac{dy}{dx} = -2y$, $\;y(0) = 4$.
  • ThinkThe general solution is $y = Ce^{-2x}$. Apply the initial condition to find $C$.
  • Solve y(0) = Ce^0 = C = 4 → C = 4 Particular solution: y = 4e^(−2x)
  • Check$y' = -8e^{-2x} = -2(4e^{-2x}) = -2y$ ✓. And $y(0) = 4$ ✓.
  • InterpretThe quantity starts at 4 and decays exponentially toward zero. The rate of decay is controlled by the coefficient $-2$ in the equation.
Answer: $y = 4e^{-2x}$
Initial vs Boundary

Initial conditions specify values at a single point and are associated with time-evolution problems. Boundary conditions specify values at multiple points and arise when a system has constraints at two or more locations in space or time. The theory of these two problem types differs significantly, and boundary value problems can have zero, one, or infinitely many solutions even when an IVP has exactly one.

Slope Fields and Direction Fields

One of the most important geometric ideas in differential equations is the slope field, also called a direction field. For a first-order equation of the form $\dfrac{dy}{dx} = f(x,y)$, the equation assigns a slope value to every point $(x,y)$ in the plane. If you draw a short line segment at each point with that slope, the collection forms the slope field.

The slope field is a field of clues. Each segment says: if a solution curve passes through here, it must be heading in this direction at this moment. You can sketch solution curves by starting at any point and following the local slopes, as if navigating a river by following its current.

Diagram — Slope Field for $y' = y$

Draw a coordinate plane with $x$ from $-2$ to $2$ and $y$ from $-2$ to $2$. At each grid point $(x,y)$, draw a short segment with slope equal to $y$. Along $y = 0$, all segments are horizontal. Along $y = 1$, all segments have slope $1$ (rising at 45°). Along $y = -1$, all segments have slope $-1$ (falling at 45°). Solution curves starting above the $x$-axis curve upward and away; those starting below curve downward. The line $y = 0$ is an equilibrium: it is a horizontal row of horizontal segments, and the solution $y = 0$ satisfies the equation since $0' = 0 = y$.

Equilibrium Solutions

An equilibrium solution is a constant function $y = c$ satisfying the differential equation. In a slope field, equilibria appear as horizontal rows of horizontal segments. For $y' = g(y)$, equilibria occur where $g(c) = 0$.

A stable equilibrium attracts nearby solution curves. An unstable equilibrium repels them.

Example 1.10.1
Reading a slope field — finding equilibria and describing solution behavior
  • ProblemFor the equation $y' = 1 - y$, determine the equilibrium solution, and describe the behavior of solutions starting above and below it.
  • ThinkSet $y' = 0$ to find equilibria. Then check the sign of $y'$ above and below.
  • Solve 1 − y = 0 → y = 1 (equilibrium) y > 1: y' = 1 − y < 0 (solution decreases toward 1) y < 1: y' = 1 − y > 0 (solution increases toward 1)
  • CheckVerify $y = 1$ satisfies the equation: if $y = 1$, then $y' = 0$ and $1 - y = 1 - 1 = 0$ ✓.
  • InterpretEvery solution curve approaches $y = 1$ as $x$ increases, regardless of starting point. The equilibrium $y = 1$ is stable — it attracts all nearby solutions. This geometric conclusion requires no formula for the solution.
Answer: Equilibrium at $y = 1$; it is stable. Solutions above it decrease; solutions below it increase. All approach $y = 1$ as $x \to \infty$.
Practice 1.7–1.10Solutions and Slope Fields
  1. Verify by substitution that $y = e^{-3x}$ is a solution to $y' + 3y = 0$. Show all steps.
  2. Verify that $y = 2\cos(x) + 3\sin(x)$ is a solution to $y'' + y = 0$.
  3. The general solution to $y' = 4y$ is $y = Ce^{4x}$. Find the particular solution satisfying $y(0) = 6$. Verify your answer.
  4. For $y' = y - 2$, find the equilibrium solution. Describe the behavior of solutions starting above $y = 2$ and below $y = 2$. Is the equilibrium stable or unstable?
  5. For $y' = y(y - 3)$, find all equilibrium solutions. For each one, state whether nearby solutions move toward or away from it.
Sections 1.11 – 1.14
Models, Applications, and Preparation
Modeling Process · Survey of Applications · Common Misunderstandings · Road Ahead

Differential Equations as Models

The most important application of differential equations is mathematical modeling: translating a description of a real system into a differential equation, solving or analyzing the equation, and interpreting the result. A model is not complete merely because an equation has been solved. A solution must be interpreted, checked, and connected back to the real system.

The Seven-Step Modeling Process

1. Define — Identify the dependent variable, independent variable, and parameters. Assign units.

2. State — Describe the rate relationship in words: what makes the quantity increase or decrease, and by how much?

3. Write — Translate the rate statement into a differential equation.

4. Condition — Identify initial or boundary conditions from the problem.

5. Solve or Analyze — Use exact methods, qualitative analysis, or numerical approximation.

6. Interpret — Connect the mathematical solution back to the real system. What does the function describe? What do parameters mean?

7. Check and Refine — Verify units, test limiting behavior, and assess whether the model's assumptions are reasonable.

Example 1.11.1
Setting up a growth model
  • ProblemA bacterial colony grows at a rate proportional to the number of bacteria present. At time $t = 0$, the colony contains 1000 bacteria. Set up a differential equation model for the population $P(t)$.
  • DefineLet $P(t)$ = number of bacteria at time $t$ hours. Let $k > 0$ = proportionality constant (per hour).
  • State"Rate proportional to $P$" means the growth rate equals $k$ times the current population.
  • Write dP/dt = kP Initial condition: P(0) = 1000
  • CheckUnits: $\dfrac{dP}{dt}$ has units bacteria/hour. $kP$ has units (1/hour)(bacteria) = bacteria/hour. ✓
  • InterpretThis model says that at any moment the colony's growth rate is proportional to its current size — larger colonies add bacteria faster. Solving this equation (Chapter 3) gives $P(t) = 1000e^{kt}$, exponential growth.
Answer: IVP is $\dfrac{dP}{dt} = kP$, $\;P(0) = 1000$.

Differential Equations in Science, Engineering, Biology, and Finance

Differential equations appear in virtually every quantitative field. This section surveys the breadth of applications, not to teach each one in full, but to establish the scope of what you are learning to use.

FieldModelEquation
MechanicsFree fall with air resistance$m\dfrac{dv}{dt} = mg - kv$
MechanicsSimple harmonic oscillator$m\dfrac{d^2x}{dt^2} + kx = 0$
CircuitsRC circuit (charging)$R\dfrac{dq}{dt} + \dfrac{q}{C} = V(t)$
CircuitsRLC circuit$L\dfrac{d^2q}{dt^2} + R\dfrac{dq}{dt} + \dfrac{q}{C} = V(t)$
BiologyLogistic population growth$\dfrac{dP}{dt} = rP\!\left(1 - \dfrac{P}{K}\right)$
EpidemiologySIR epidemic model$\dfrac{dS}{dt} = -\beta SI$, $\;\dfrac{dI}{dt} = \beta SI - \gamma I$
ChemistryFirst-order reaction$\dfrac{d[A]}{dt} = -k[A]$
FinanceContinuous compounding$\dfrac{dA}{dt} = rA$
PhysicsNewton's Law of Cooling$\dfrac{dT}{dt} = -k(T - T_{\text{amb}})$
A Unifying Thread

In every row of the table above, the differential equation is not derived from a known formula for the quantity. It is derived from a physical, biological, chemical, or economic principle about how the quantity changes. The function itself is what you need to find. That is the defining task of differential equations.

Common Early Differential Equation Misunderstandings

Misunderstanding 1 — "I solve a differential equation for a number."
Solving y′ = 2y gives y = 2.

Correction: A differential equation is solved for a function, not a number. The solution to $y' = 2y$ is the family of functions $y = Ce^{2x}$.

Misunderstanding 2 — "There is only one solution."
"The solution is y = e^(2x)."

Correction: There is a family of solutions $y = Ce^{2x}$ for any constant $C$. A unique solution requires additional information, such as an initial condition.

Misunderstanding 3 — "If I can integrate, I can solve any differential equation."
Direct integration always works: just integrate both sides.

Correction: Direct integration only works for $y' = f(x)$ where the right side does not involve $y$. When $y$ appears on the right, different methods are needed: separation of variables, integrating factors, characteristic equations, Laplace transforms, and more.

Misunderstanding 4 — "Every differential equation has a closed-form solution."
"If I just work harder, I will find the formula."

Correction: Most differential equations arising from real applications cannot be solved exactly. Numerical methods (Chapter 11) and qualitative analysis (Chapter 12) are essential tools, not fallbacks.

Misunderstanding 5 — "The constant C is unimportant."
"I will just drop C at the end."

Correction: $C$ represents the entire family of solutions. In applications, $C$ is determined by initial conditions and carries physical meaning: initial population, initial charge, initial temperature difference.

Misunderstanding 6 — "Slope fields are just decorative."
"I do not need to draw the field; I will just solve the equation."

Correction: Slope fields are a primary tool, especially for nonlinear and autonomous equations where exact solutions may not exist. The geometric picture often reveals equilibrium, stability, and long-term behavior directly.

Misunderstanding 7 — "Order and degree mean the same thing."
"The equation (y′)³ = y is third-order."

Correction: Order is the highest derivative that appears (here: $y'$, so first-order). Degree is the power of that derivative (here: $3$, so third-degree). This equation is first-order, third-degree.

Misunderstanding 8 — "Checking my answer is optional."
"I used the right method so the answer must be correct."

Correction: Every method can produce computational errors. Always substitute your proposed solution and its derivatives back into the original equation. Verification takes one minute and is the most reliable check available.

Preparing for First-Order Equations

This chapter has built the conceptual foundation for the rest of the book. You now have the vocabulary, classification tools, solution-checking method, and a geometric picture from slope fields. Chapter 2 introduces first-order differential equations in depth, developing slope fields and direction fields as the primary geometric tool before any symbolic method is introduced.

As you move into Chapters 2 through 5, you will draw on differentiation rules (product rule, chain rule, implicit differentiation), integration techniques (substitution, integration by parts, partial fractions), and the properties of exponential, logarithmic, and trigonometric functions. If any of these feel uncertain, Appendix A and Appendix B at the back of this textbook provide targeted review.

The question to carry into Chapter 2 is this: given a differential equation, and without solving it explicitly, what can you say about how its solutions behave? Can you identify where solutions grow, where they decay, where they level off, and which equilibria attract or repel nearby curves? Slope fields and direction fields are the tools that will answer these questions.

Practice 1.11–1.14Modeling Questions
  1. A savings account grows at a continuous rate of $5\%$ per year. The initial deposit is $\$2000$. Define variables, write the differential equation model, and state the initial condition.
  2. A radioactive substance decays at a rate proportional to the amount present. Initially 100 grams are present. Write the IVP.
  3. A cup of coffee at $90°C$ cools in a room at $20°C$. The cooling rate is proportional to the temperature difference. Write the IVP for $T(t)$.
  4. A fish population grows proportionally but 10 fish per year are removed by fishing. Write the differential equation model.
  5. A ball is thrown upward at $20$ m/s. Write a second-order IVP for its height $h(t)$, using $g = 9.8$ m/s². State both initial conditions.

Chapter Summary

Key Terms Review

differential equation
An equation involving an unknown function and one or more of its derivatives.
ordinary DE (ODE)
A differential equation with a single independent variable and ordinary derivatives.
partial DE (PDE)
A differential equation with multiple independent variables and partial derivatives.
order
The order of the highest derivative present in a differential equation.
degree
The power to which the highest-order derivative is raised, in polynomial form.
linear DE
An equation in which the unknown and all its derivatives appear to the first power only, with no products among them and coefficients depending only on the independent variable.
nonlinear DE
A differential equation that fails the conditions for linearity.
dependent variable
The unknown function being solved for.
independent variable
The variable the unknown function depends on, such as $x$ or $t$.
solution
A function that satisfies a differential equation identically for all values in its domain.
general solution
A family of solutions involving one or more arbitrary constants, describing all solutions.
particular solution
A specific member of the solution family, obtained by assigning values to all arbitrary constants.
arbitrary constant
A constant $C$ in the general solution that may take any value. Its value is fixed by initial or boundary conditions.
initial condition
A specification of the solution's value (or a derivative's value) at a single point.
boundary condition
A specification of values at two or more different points, associated with boundary value problems.
initial value problem
A differential equation together with one or more initial conditions specifying the state at a starting point.
slope field
A diagram showing short line segments at each point $(x,y)$ with slope equal to $f(x,y)$, representing the local direction of solution curves.
equilibrium solution
A constant function $y = c$ satisfying the differential equation. Appears in a slope field as a horizontal row of horizontal segments.
mathematical model
A differential equation (or system) that represents a real-world process using defined variables and parameters.
autonomous equation
A differential equation in which the independent variable does not appear explicitly; the rate depends only on the dependent variable.

Concept Review Questions

  1. What is a differential equation? How does it differ from an algebraic equation?
  2. What is the dependent variable in a differential equation, and what is the independent variable? Give an example of each from a physical setting.
  3. What is the order of a differential equation? How do you determine it?
  4. What is the degree of a differential equation? Give an example of a second-order, second-degree equation.
  5. What does it mean for a differential equation to be linear? Give one linear and one nonlinear example.
  6. What does it mean to say a function is a solution to a differential equation? How do you verify it?
  7. What is the difference between a general solution and a particular solution?
  8. What is an arbitrary constant? Why does it appear, and how is its value determined?
  9. What is the difference between an initial value problem and a boundary value problem?
  10. What is a slope field, and how is it constructed?
  11. How can you identify a stable equilibrium from a slope field?
  12. Name three fields in which differential equations serve as primary modeling tools.

Classification Practice

For each equation, state: (a) ODE or PDE, (b) order, (c) degree, (d) linear or nonlinear.

  1. $y' = 5y$
  2. $y'' - 4y' + 3y = 0$
  3. $(y')^2 + y = x$
  4. $\dfrac{\partial u}{\partial t} = k\dfrac{\partial^2 u}{\partial x^2}$
  5. $y''' + xy'' - y = e^x$
  6. $y\,y' = x$
  7. $\dfrac{d^2x}{dt^2} + \sin(x) = 0$
  8. $y' = 1 + y^2$
  9. $\dfrac{d^3y}{dx^3} - 2y'' + y' = \cos(x)$
  10. $\dfrac{\partial^2 u}{\partial x^2} + \dfrac{\partial^2 u}{\partial y^2} = 0$

Solution Verification Practice

Verify by substitution that each function is a solution to the given equation. Show all steps.

  1. $y = e^{-3x}$; equation: $y' + 3y = 0$
  2. $y = 2\cos(x) + 3\sin(x)$; equation: $y'' + y = 0$
  3. $y = x^2 + 1$; equation: $y' = 2x$
  4. $y = \dfrac{1}{1-x}$; equation: $y' = y^2$ (domain: $x \ne 1$)
  5. $y = e^{x^2/2}$; equation: $y' = xy$
  6. $y = Ce^{-4x}$ for any constant $C$; equation: $y' + 4y = 0$
  7. $y = A\cos(2t) + B\sin(2t)$ for any $A$, $B$; equation: $y'' + 4y = 0$

Slope Field Interpretation

  1. For $y' = 2$, what slope does every segment in the slope field have? What do the solution curves look like?
  2. For $y' = x$, describe how the slopes change as $x$ increases. What do solution curves look like?
  3. For $y' = -y$, describe the slope field. Where are slopes zero? Where positive? Negative? What happens to solutions starting above the $x$-axis?
  4. For $y' = y(1-y)$, identify both equilibrium solutions. Describe the behavior of curves starting between the two equilibria. Starting above the upper one.
  5. A slope field is described as follows: along $y = 2$, all segments are horizontal; above $y = 2$, all segments slope downward; below $y = 2$, all segments slope upward. Identify the equilibrium, classify it as stable or unstable, and write a simple differential equation consistent with this description.

Modeling Questions

Define variables, write the differential equation, and state initial conditions.

  1. A savings account grows continuously at $5\%$ per year. Initial deposit: $\$2000$.
  2. A radioactive substance decays at a rate proportional to the amount present. Initially 100 grams are present.
  3. A cup of coffee at $90°C$ cools in a $20°C$ room. Cooling rate is proportional to the temperature difference.
  4. A fish population grows proportionally but $10$ fish per year are harvested.
  5. A ball is thrown upward at $20$ m/s. Write a second-order IVP for height $h(t)$; use $g = 9.8$ m/s$^2$.
  6. Medicine: A patient receives a drug at $r$ mg/hr intravenously. Elimination rate is proportional to concentration $C(t)$ with constant $k$. Write the IVP for $C(t)$ given blood volume $V$ liters and initial concentration zero.
  7. Finance: An investor places $\$10{,}000$ at $7\%$ continuous return but withdraws $\$1{,}000$ per year continuously. Write the differential equation for account balance $A(t)$. Classify it.

Error Analysis

Each problem contains an error. Identify it and write the correct answer.

Problem 1
A student says: "The solution to y′ = 3y is y = 3."

What is wrong? What is the correct answer?

Problem 2
A student writes: "y = e^(3x) is the solution to y′ = 3y. There is only one solution."

What is wrong with the word "only one"?

Problem 3
A student classifies y″ + y² = 0 as a linear second-order equation.

Identify the error and state the correct classification.

Problem 4
A student says: "The order of (y′)³ = y is 3, because of the exponent 3."

What is the actual order, and what is the actual degree?

Problem 5
A student verifies y = sin(x) in y″ + y = 1: "−sin(x) + sin(x) = 0, and the right side is 1, but the answer is probably still right."

What should the student actually conclude?

Problem 6
A student solves a second-order equation using only y(0) = 3, and concludes this is enough for a unique solution.

What is missing, and why?

Problem 7
A student draws the slope field for y′ = y − 1 and marks the equilibrium at y = 0.

Find the correct equilibrium and explain how to determine it.

Chapter 1 Checkpoint

Chapter 1 Checkpoint
Complete without assistance — assesses all major skills and concepts from Chapter 1
Part A — Classification
  1. State the order, degree, and linearity of each equation:
    (a) $y'' + 4y' + 4y = 0$
    (b) $y' = y^3 - x$
    (c) $y''' - y'' + e^x y = \cos(x)$
    (d) $\left(\dfrac{d^2y}{dx^2}\right)^2 + y = 0$
Part B — Verification
  1. Verify that $y = e^{-2x} + 3$ is not a solution to $y' + 2y = 0$. Then determine what equation it does satisfy.
  2. Verify that $y = C_1 e^x + C_2 e^{-x}$ is a solution to $y'' - y = 0$ for any constants $C_1$ and $C_2$.
Part C — Initial Value Problems
  1. The general solution to $y' = -3y$ is $y = Ce^{-3x}$. Find the particular solution satisfying $y(0) = 7$. Verify your answer.
  2. The general solution to $y'' + 4y = 0$ is $y = C_1\cos(2x) + C_2\sin(2x)$. Find the particular solution satisfying $y(0) = 1$ and $y'(0) = -2$.
Part D — Slope Fields
  1. For the equation $y' = 2 - y$:
    (a) Find the equilibrium solution.
    (b) Describe the direction of solution curves above the equilibrium.
    (c) Describe the direction below.
    (d) Is this equilibrium stable or unstable? Explain briefly.
Part E — Modeling
  1. A lake contains $P(t)$ kilograms of a pollutant at time $t$ years. Clean water dilutes the pollutant at a rate proportional to the current amount, with proportionality constant $0.1$ per year. Initially the lake contains $500$ kg. Write the IVP for $P(t)$.
  2. Classify the equation from problem 7. State its order and whether it is linear.
Part F — Reflection
  1. Explain in your own words the difference between a general solution and a particular solution. Why does one exist before initial conditions are applied and the other after?
  2. A classmate says a slope field is unnecessary once you can solve the equation. Give one situation where a slope field provides information that an exact formula does not.
Looking Ahead
Chapter 2: First-Order Differential Equations and Slope Fields

Chapter 1 gave you the vocabulary, classification tools, and geometric picture of differential equations. Chapter 2 deepens the geometric theory: slope fields, direction fields, autonomous equations, equilibrium solutions, stability, and the long-term behavior of solution curves. All of this geometric work comes before any symbolic solution method. By the time you reach Chapter 3 (separation of variables) and Chapter 4 (integrating factors), you will be able to look at a slope field and know immediately whether a proposed symbolic solution makes geometric sense.

The question to carry with you: given a differential equation, what can you say about how solutions behave without solving it explicitly?

MGU Library Connection
  • Appendix A: Calculus Readiness Review — differentiation rules, chain rule, implicit differentiation
  • Appendix B: Integration Techniques Review — substitution, integration by parts, partial fractions
  • Appendix D: Differential Equation Classification Reference — order, degree, linearity at a glance
  • MGU Calculus Library — derivatives, antiderivatives, and the Fundamental Theorem of Calculus
  • MGU Linear Algebra Library — matrices and eigenvalues, needed for Chapters 9 and 10
  • MGU Physics and Engineering pages — Newton's laws, circuits, and oscillation as differential equation applications